Metamath Proof Explorer


Theorem coseq1

Description: A complex number whose cosine is one is an integer multiple of 2 _pi . (Contributed by Mario Carneiro, 12-May-2014)

Ref Expression
Assertion coseq1 ⊢ A ∈ ℂ → cos ⁡ A = 1 ↔ A 2 ⁢ π ∈ ℤ

Proof

Step Hyp Ref Expression
1 2cn ⊢ 2 ∈ ℂ
2 2ne0 ⊢ 2 ≠ 0
3 divcan2 ⊢ A ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 2 ⁢ A 2 = A
4 1 2 3 mp3an23 ⊢ A ∈ ℂ → 2 ⁢ A 2 = A
5 4 fveq2d ⊢ A ∈ ℂ → cos ⁡ 2 ⁢ A 2 = cos ⁡ A
6 halfcl ⊢ A ∈ ℂ → A 2 ∈ ℂ
7 cos2tsin ⊢ A 2 ∈ ℂ → cos ⁡ 2 ⁢ A 2 = 1 − 2 ⁢ sin ⁡ A 2 2
8 6 7 syl ⊢ A ∈ ℂ → cos ⁡ 2 ⁢ A 2 = 1 − 2 ⁢ sin ⁡ A 2 2
9 5 8 eqtr3d ⊢ A ∈ ℂ → cos ⁡ A = 1 − 2 ⁢ sin ⁡ A 2 2
10 9 eqeq1d ⊢ A ∈ ℂ → cos ⁡ A = 1 ↔ 1 − 2 ⁢ sin ⁡ A 2 2 = 1
11 6 sincld ⊢ A ∈ ℂ → sin ⁡ A 2 ∈ ℂ
12 11 sqcld ⊢ A ∈ ℂ → sin ⁡ A 2 2 ∈ ℂ
13 mulcl ⊢ 2 ∈ ℂ ∧ sin ⁡ A 2 2 ∈ ℂ → 2 ⁢ sin ⁡ A 2 2 ∈ ℂ
14 1 12 13 sylancr ⊢ A ∈ ℂ → 2 ⁢ sin ⁡ A 2 2 ∈ ℂ
15 ax-1cn ⊢ 1 ∈ ℂ
16 subsub23 ⊢ 1 ∈ ℂ ∧ 2 ⁢ sin ⁡ A 2 2 ∈ ℂ ∧ 1 ∈ ℂ → 1 − 2 ⁢ sin ⁡ A 2 2 = 1 ↔ 1 − 1 = 2 ⁢ sin ⁡ A 2 2
17 15 15 16 mp3an13 ⊢ 2 ⁢ sin ⁡ A 2 2 ∈ ℂ → 1 − 2 ⁢ sin ⁡ A 2 2 = 1 ↔ 1 − 1 = 2 ⁢ sin ⁡ A 2 2
18 14 17 syl ⊢ A ∈ ℂ → 1 − 2 ⁢ sin ⁡ A 2 2 = 1 ↔ 1 − 1 = 2 ⁢ sin ⁡ A 2 2
19 eqcom ⊢ 1 − 1 = 2 ⁢ sin ⁡ A 2 2 ↔ 2 ⁢ sin ⁡ A 2 2 = 1 − 1
20 1m1e0 ⊢ 1 − 1 = 0
21 20 eqeq2i ⊢ 2 ⁢ sin ⁡ A 2 2 = 1 − 1 ↔ 2 ⁢ sin ⁡ A 2 2 = 0
22 19 21 bitri ⊢ 1 − 1 = 2 ⁢ sin ⁡ A 2 2 ↔ 2 ⁢ sin ⁡ A 2 2 = 0
23 18 22 bitrdi ⊢ A ∈ ℂ → 1 − 2 ⁢ sin ⁡ A 2 2 = 1 ↔ 2 ⁢ sin ⁡ A 2 2 = 0
24 10 23 bitrd ⊢ A ∈ ℂ → cos ⁡ A = 1 ↔ 2 ⁢ sin ⁡ A 2 2 = 0
25 mul0or ⊢ 2 ∈ ℂ ∧ sin ⁡ A 2 2 ∈ ℂ → 2 ⁢ sin ⁡ A 2 2 = 0 ↔ 2 = 0 ∨ sin ⁡ A 2 2 = 0
26 1 12 25 sylancr ⊢ A ∈ ℂ → 2 ⁢ sin ⁡ A 2 2 = 0 ↔ 2 = 0 ∨ sin ⁡ A 2 2 = 0
27 2 neii ⊢ ¬ 2 = 0
28 biorf ⊢ ¬ 2 = 0 → sin ⁡ A 2 2 = 0 ↔ 2 = 0 ∨ sin ⁡ A 2 2 = 0
29 27 28 ax-mp ⊢ sin ⁡ A 2 2 = 0 ↔ 2 = 0 ∨ sin ⁡ A 2 2 = 0
30 26 29 bitr4di ⊢ A ∈ ℂ → 2 ⁢ sin ⁡ A 2 2 = 0 ↔ sin ⁡ A 2 2 = 0
31 sqeq0 ⊢ sin ⁡ A 2 ∈ ℂ → sin ⁡ A 2 2 = 0 ↔ sin ⁡ A 2 = 0
32 11 31 syl ⊢ A ∈ ℂ → sin ⁡ A 2 2 = 0 ↔ sin ⁡ A 2 = 0
33 24 30 32 3bitrd ⊢ A ∈ ℂ → cos ⁡ A = 1 ↔ sin ⁡ A 2 = 0
34 sineq0 ⊢ A 2 ∈ ℂ → sin ⁡ A 2 = 0 ↔ A 2 π ∈ ℤ
35 6 34 syl ⊢ A ∈ ℂ → sin ⁡ A 2 = 0 ↔ A 2 π ∈ ℤ
36 1 2 pm3.2i ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
37 picn ⊢ π ∈ ℂ
38 pire ⊢ π ∈ ℝ
39 pipos ⊢ 0 < π
40 38 39 gt0ne0ii ⊢ π ≠ 0
41 37 40 pm3.2i ⊢ π ∈ ℂ ∧ π ≠ 0
42 divdiv1 ⊢ A ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ π ∈ ℂ ∧ π ≠ 0 → A 2 π = A 2 ⁢ π
43 36 41 42 mp3an23 ⊢ A ∈ ℂ → A 2 π = A 2 ⁢ π
44 43 eleq1d ⊢ A ∈ ℂ → A 2 π ∈ ℤ ↔ A 2 ⁢ π ∈ ℤ
45 33 35 44 3bitrd ⊢ A ∈ ℂ → cos ⁡ A = 1 ↔ A 2 ⁢ π ∈ ℤ