Metamath Proof Explorer


Theorem cru

Description: The representation of complex numbers in terms of real and imaginary parts is unique. Proposition 10-1.3 of Gleason p. 130. (Contributed by NM, 9-May-1999) (Proof shortened by Mario Carneiro, 27-May-2016)

Ref Expression
Assertion cru ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B = C + i ⁢ D ↔ A = C ∧ B = D

Proof

Step Hyp Ref Expression
1 simplrl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → C ∈ ℝ
2 1 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → C ∈ ℂ
3 simplll ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → A ∈ ℝ
4 3 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → A ∈ ℂ
5 simpr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → A + i ⁢ B = C + i ⁢ D
6 ax-icn ⊢ i ∈ ℂ
7 6 a1i ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ∈ ℂ
8 simpllr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → B ∈ ℝ
9 8 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → B ∈ ℂ
10 7 9 mulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ⁢ B ∈ ℂ
11 simplrr ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → D ∈ ℝ
12 11 recnd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → D ∈ ℂ
13 7 12 mulcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ⁢ D ∈ ℂ
14 4 10 2 13 addsubeq4d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → A + i ⁢ B = C + i ⁢ D ↔ C − A = i ⁢ B − i ⁢ D
15 5 14 mpbid ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → C − A = i ⁢ B − i ⁢ D
16 8 11 resubcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → B − D ∈ ℝ
17 7 9 12 subdid ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ⁢ B − D = i ⁢ B − i ⁢ D
18 17 15 eqtr4d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ⁢ B − D = C − A
19 1 3 resubcld ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → C − A ∈ ℝ
20 18 19 eqeltrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ⁢ B − D ∈ ℝ
21 rimul ⊢ B − D ∈ ℝ ∧ i ⁢ B − D ∈ ℝ → B − D = 0
22 16 20 21 syl2anc ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → B − D = 0
23 9 12 22 subeq0d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → B = D
24 23 oveq2d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ⁢ B = i ⁢ D
25 24 oveq1d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ⁢ B − i ⁢ D = i ⁢ D − i ⁢ D
26 13 subidd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → i ⁢ D − i ⁢ D = 0
27 15 25 26 3eqtrd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → C − A = 0
28 2 4 27 subeq0d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → C = A
29 28 eqcomd ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → A = C
30 29 23 jca ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ ∧ A + i ⁢ B = C + i ⁢ D → A = C ∧ B = D
31 30 ex ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B = C + i ⁢ D → A = C ∧ B = D
32 oveq2 ⊢ B = D → i ⁢ B = i ⁢ D
33 oveq12 ⊢ A = C ∧ i ⁢ B = i ⁢ D → A + i ⁢ B = C + i ⁢ D
34 32 33 sylan2 ⊢ A = C ∧ B = D → A + i ⁢ B = C + i ⁢ D
35 31 34 impbid1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ C ∈ ℝ ∧ D ∈ ℝ → A + i ⁢ B = C + i ⁢ D ↔ A = C ∧ B = D