Metamath Proof Explorer


Theorem dmmpossx2

Description: The domain of a mapping is a subset of its base classes expressed as union of Cartesian products over its second component, analogous to dmmpossx . (Contributed by AV, 30-Mar-2019)

Ref Expression
Hypothesis dmmpossx2.1 ⊢ F = x ∈ A , y ∈ B ⟼ C
Assertion dmmpossx2 ⊢ dom ⁡ F ⊆ ⋃ y ∈ B A × y

Proof

Step Hyp Ref Expression
1 dmmpossx2.1 ⊢ F = x ∈ A , y ∈ B ⟼ C
2 nfcv ⊢ Ⅎ _ u A
3 nfcsb1v ⊢ Ⅎ _ y ⦋ u / y⦌ A
4 nfcv ⊢ Ⅎ _ u C
5 nfcv ⊢ Ⅎ _ v C
6 nfcv ⊢ Ⅎ _ x u
7 nfcsb1v ⊢ Ⅎ _ x ⦋ v / x⦌ C
8 6 7 nfcsbw ⊢ Ⅎ _ x ⦋ u / y⦌ ⦋ v / x⦌ C
9 nfcsb1v ⊢ Ⅎ _ y ⦋ u / y⦌ ⦋ v / x⦌ C
10 csbeq1a ⊢ y = u → A = ⦋ u / y⦌ A
11 csbeq1a ⊢ x = v → C = ⦋ v / x⦌ C
12 csbeq1a ⊢ y = u → ⦋ v / x⦌ C = ⦋ u / y⦌ ⦋ v / x⦌ C
13 11 12 sylan9eqr ⊢ y = u ∧ x = v → C = ⦋ u / y⦌ ⦋ v / x⦌ C
14 2 3 4 5 8 9 10 13 cbvmpox2 ⊢ x ∈ A , y ∈ B ⟼ C = v ∈ ⦋ u / y⦌ A , u ∈ B ⟼ ⦋ u / y⦌ ⦋ v / x⦌ C
15 vex ⊢ v ∈ V
16 vex ⊢ u ∈ V
17 15 16 op2ndd ⊢ t = v u → 2 nd ⁡ t = u
18 17 csbeq1d ⊢ t = v u → ⦋ 2 nd ⁡ t / y⦌ ⦋ 1 st ⁡ t / x⦌ C = ⦋ u / y⦌ ⦋ 1 st ⁡ t / x⦌ C
19 15 16 op1std ⊢ t = v u → 1 st ⁡ t = v
20 19 csbeq1d ⊢ t = v u → ⦋ 1 st ⁡ t / x⦌ C = ⦋ v / x⦌ C
21 20 csbeq2dv ⊢ t = v u → ⦋ u / y⦌ ⦋ 1 st ⁡ t / x⦌ C = ⦋ u / y⦌ ⦋ v / x⦌ C
22 18 21 eqtrd ⊢ t = v u → ⦋ 2 nd ⁡ t / y⦌ ⦋ 1 st ⁡ t / x⦌ C = ⦋ u / y⦌ ⦋ v / x⦌ C
23 22 mpomptx2 ⊢ t ∈ ⋃ u ∈ B ⦋ u / y⦌ A × u ⟼ ⦋ 2 nd ⁡ t / y⦌ ⦋ 1 st ⁡ t / x⦌ C = v ∈ ⦋ u / y⦌ A , u ∈ B ⟼ ⦋ u / y⦌ ⦋ v / x⦌ C
24 14 1 23 3eqtr4i ⊢ F = t ∈ ⋃ u ∈ B ⦋ u / y⦌ A × u ⟼ ⦋ 2 nd ⁡ t / y⦌ ⦋ 1 st ⁡ t / x⦌ C
25 24 dmmptss ⊢ dom ⁡ F ⊆ ⋃ u ∈ B ⦋ u / y⦌ A × u
26 nfcv ⊢ Ⅎ _ u A × y
27 nfcv ⊢ Ⅎ _ y u
28 3 27 nfxp ⊢ Ⅎ _ y ⦋ u / y⦌ A × u
29 sneq ⊢ y = u → y = u
30 10 29 xpeq12d ⊢ y = u → A × y = ⦋ u / y⦌ A × u
31 26 28 30 cbviun ⊢ ⋃ y ∈ B A × y = ⋃ u ∈ B ⦋ u / y⦌ A × u
32 25 31 sseqtrri ⊢ dom ⁡ F ⊆ ⋃ y ∈ B A × y