Metamath Proof Explorer


Theorem elflim2

Description: The predicate "is a limit point of a filter." (Contributed by Mario Carneiro, 9-Apr-2015) (Revised by Stefan O'Rear, 6-Aug-2015)

Ref Expression
Hypothesis flimval.1 ⊢ X = ⋃ J
Assertion elflim2 ⊢ A ∈ J fLim F ↔ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F

Proof

Step Hyp Ref Expression
1 flimval.1 ⊢ X = ⋃ J
2 anass ⊢ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F ↔ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F
3 df-3an ⊢ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X ↔ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X
4 3 anbi1i ⊢ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F ↔ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F
5 df-flim ⊢ fLim = j ∈ Top , f ∈ ⋃ ran ⁡ Fil ⟼ x ∈ ⋃ j | nei ⁡ j ⁡ x ⊆ f ∧ f ⊆ 𝒫 ⋃ j
6 5 elmpocl ⊢ A ∈ J fLim F → J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil
7 1 flimval ⊢ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil → J fLim F = x ∈ X | nei ⁡ J ⁡ x ⊆ F ∧ F ⊆ 𝒫 X
8 7 eleq2d ⊢ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil → A ∈ J fLim F ↔ A ∈ x ∈ X | nei ⁡ J ⁡ x ⊆ F ∧ F ⊆ 𝒫 X
9 sneq ⊢ x = A → x = A
10 9 fveq2d ⊢ x = A → nei ⁡ J ⁡ x = nei ⁡ J ⁡ A
11 10 sseq1d ⊢ x = A → nei ⁡ J ⁡ x ⊆ F ↔ nei ⁡ J ⁡ A ⊆ F
12 11 anbi1d ⊢ x = A → nei ⁡ J ⁡ x ⊆ F ∧ F ⊆ 𝒫 X ↔ nei ⁡ J ⁡ A ⊆ F ∧ F ⊆ 𝒫 X
13 12 biancomd ⊢ x = A → nei ⁡ J ⁡ x ⊆ F ∧ F ⊆ 𝒫 X ↔ F ⊆ 𝒫 X ∧ nei ⁡ J ⁡ A ⊆ F
14 13 elrab ⊢ A ∈ x ∈ X | nei ⁡ J ⁡ x ⊆ F ∧ F ⊆ 𝒫 X ↔ A ∈ X ∧ F ⊆ 𝒫 X ∧ nei ⁡ J ⁡ A ⊆ F
15 an12 ⊢ A ∈ X ∧ F ⊆ 𝒫 X ∧ nei ⁡ J ⁡ A ⊆ F ↔ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F
16 14 15 bitri ⊢ A ∈ x ∈ X | nei ⁡ J ⁡ x ⊆ F ∧ F ⊆ 𝒫 X ↔ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F
17 8 16 bitrdi ⊢ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil → A ∈ J fLim F ↔ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F
18 6 17 biadanii ⊢ A ∈ J fLim F ↔ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F
19 2 4 18 3bitr4ri ⊢ A ∈ J fLim F ↔ J ∈ Top ∧ F ∈ ⋃ ran ⁡ Fil ∧ F ⊆ 𝒫 X ∧ A ∈ X ∧ nei ⁡ J ⁡ A ⊆ F