Metamath Proof Explorer


Theorem fperiodmul

Description: A function with period T is also periodic with period multiple of T. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypotheses fperiodmul.f ⊢ φ → F : ℝ ⟶ ℂ
fperiodmul.t ⊢ φ → T ∈ ℝ
fperiodmul.n ⊢ φ → N ∈ ℤ
fperiodmul.x ⊢ φ → X ∈ ℝ
fperiodmul.per ⊢ φ ∧ x ∈ ℝ → F ⁡ x + T = F ⁡ x
Assertion fperiodmul ⊢ φ → F ⁡ X + N ⁢ T = F ⁡ X

Proof

Step Hyp Ref Expression
1 fperiodmul.f ⊢ φ → F : ℝ ⟶ ℂ
2 fperiodmul.t ⊢ φ → T ∈ ℝ
3 fperiodmul.n ⊢ φ → N ∈ ℤ
4 fperiodmul.x ⊢ φ → X ∈ ℝ
5 fperiodmul.per ⊢ φ ∧ x ∈ ℝ → F ⁡ x + T = F ⁡ x
6 1 adantr ⊢ φ ∧ N ∈ ℕ 0 → F : ℝ ⟶ ℂ
7 2 adantr ⊢ φ ∧ N ∈ ℕ 0 → T ∈ ℝ
8 simpr ⊢ φ ∧ N ∈ ℕ 0 → N ∈ ℕ 0
9 4 adantr ⊢ φ ∧ N ∈ ℕ 0 → X ∈ ℝ
10 5 adantlr ⊢ φ ∧ N ∈ ℕ 0 ∧ x ∈ ℝ → F ⁡ x + T = F ⁡ x
11 6 7 8 9 10 fperiodmullem ⊢ φ ∧ N ∈ ℕ 0 → F ⁡ X + N ⁢ T = F ⁡ X
12 4 recnd ⊢ φ → X ∈ ℂ
13 3 zcnd ⊢ φ → N ∈ ℂ
14 2 recnd ⊢ φ → T ∈ ℂ
15 13 14 mulcld ⊢ φ → N ⁢ T ∈ ℂ
16 12 15 subnegd ⊢ φ → X − − N ⁢ T = X + N ⁢ T
17 13 14 mulneg1d ⊢ φ → -N ⁢ T = − N ⁢ T
18 17 eqcomd ⊢ φ → − N ⁢ T = -N ⁢ T
19 18 oveq2d ⊢ φ → X − − N ⁢ T = X − -N ⁢ T
20 16 19 eqtr3d ⊢ φ → X + N ⁢ T = X − -N ⁢ T
21 20 fveq2d ⊢ φ → F ⁡ X + N ⁢ T = F ⁡ X − -N ⁢ T
22 21 adantr ⊢ φ ∧ ¬ N ∈ ℕ 0 → F ⁡ X + N ⁢ T = F ⁡ X − -N ⁢ T
23 1 adantr ⊢ φ ∧ ¬ N ∈ ℕ 0 → F : ℝ ⟶ ℂ
24 2 adantr ⊢ φ ∧ ¬ N ∈ ℕ 0 → T ∈ ℝ
25 znnn0nn ⊢ N ∈ ℤ ∧ ¬ N ∈ ℕ 0 → − N ∈ ℕ
26 3 25 sylan ⊢ φ ∧ ¬ N ∈ ℕ 0 → − N ∈ ℕ
27 26 nnnn0d ⊢ φ ∧ ¬ N ∈ ℕ 0 → − N ∈ ℕ 0
28 4 adantr ⊢ φ ∧ ¬ N ∈ ℕ 0 → X ∈ ℝ
29 3 adantr ⊢ φ ∧ ¬ N ∈ ℕ 0 → N ∈ ℤ
30 29 zred ⊢ φ ∧ ¬ N ∈ ℕ 0 → N ∈ ℝ
31 30 renegcld ⊢ φ ∧ ¬ N ∈ ℕ 0 → − N ∈ ℝ
32 31 24 remulcld ⊢ φ ∧ ¬ N ∈ ℕ 0 → -N ⁢ T ∈ ℝ
33 28 32 resubcld ⊢ φ ∧ ¬ N ∈ ℕ 0 → X − -N ⁢ T ∈ ℝ
34 5 adantlr ⊢ φ ∧ ¬ N ∈ ℕ 0 ∧ x ∈ ℝ → F ⁡ x + T = F ⁡ x
35 23 24 27 33 34 fperiodmullem ⊢ φ ∧ ¬ N ∈ ℕ 0 → F ⁡ X - -N ⁢ T + -N ⁢ T = F ⁡ X − -N ⁢ T
36 28 recnd ⊢ φ ∧ ¬ N ∈ ℕ 0 → X ∈ ℂ
37 30 recnd ⊢ φ ∧ ¬ N ∈ ℕ 0 → N ∈ ℂ
38 37 negcld ⊢ φ ∧ ¬ N ∈ ℕ 0 → − N ∈ ℂ
39 24 recnd ⊢ φ ∧ ¬ N ∈ ℕ 0 → T ∈ ℂ
40 38 39 mulcld ⊢ φ ∧ ¬ N ∈ ℕ 0 → -N ⁢ T ∈ ℂ
41 36 40 npcand ⊢ φ ∧ ¬ N ∈ ℕ 0 → X - -N ⁢ T + -N ⁢ T = X
42 41 fveq2d ⊢ φ ∧ ¬ N ∈ ℕ 0 → F ⁡ X - -N ⁢ T + -N ⁢ T = F ⁡ X
43 22 35 42 3eqtr2d ⊢ φ ∧ ¬ N ∈ ℕ 0 → F ⁡ X + N ⁢ T = F ⁡ X
44 11 43 pm2.61dan ⊢ φ → F ⁡ X + N ⁢ T = F ⁡ X