Metamath Proof Explorer


Theorem funcringcsetcALTV2lem7

Description: Lemma 7 for funcringcsetcALTV2 . (Contributed by AV, 15-Feb-2020) (New usage is discouraged.)

Ref Expression
Hypotheses funcringcsetcALTV2.r ⊢ R = RingCat ⁡ U
funcringcsetcALTV2.s ⊢ S = SetCat ⁡ U
funcringcsetcALTV2.b ⊢ B = Base R
funcringcsetcALTV2.c ⊢ C = Base S
funcringcsetcALTV2.u ⊢ φ → U ∈ WUni
funcringcsetcALTV2.f ⊢ φ → F = x ∈ B ⟼ Base x
funcringcsetcALTV2.g ⊢ φ → G = x ∈ B , y ∈ B ⟼ I ↾ x RingHom y
Assertion funcringcsetcALTV2lem7 ⊢ φ ∧ X ∈ B → X G X ⁡ Id ⁡ R ⁡ X = Id ⁡ S ⁡ F ⁡ X

Proof

Step Hyp Ref Expression
1 funcringcsetcALTV2.r ⊢ R = RingCat ⁡ U
2 funcringcsetcALTV2.s ⊢ S = SetCat ⁡ U
3 funcringcsetcALTV2.b ⊢ B = Base R
4 funcringcsetcALTV2.c ⊢ C = Base S
5 funcringcsetcALTV2.u ⊢ φ → U ∈ WUni
6 funcringcsetcALTV2.f ⊢ φ → F = x ∈ B ⟼ Base x
7 funcringcsetcALTV2.g ⊢ φ → G = x ∈ B , y ∈ B ⟼ I ↾ x RingHom y
8 1 2 3 4 5 6 7 funcringcsetcALTV2lem5 ⊢ φ ∧ X ∈ B ∧ X ∈ B → X G X = I ↾ X RingHom X
9 8 anabsan2 ⊢ φ ∧ X ∈ B → X G X = I ↾ X RingHom X
10 eqid ⊢ Id ⁡ R = Id ⁡ R
11 5 adantr ⊢ φ ∧ X ∈ B → U ∈ WUni
12 simpr ⊢ φ ∧ X ∈ B → X ∈ B
13 eqid ⊢ Base X = Base X
14 1 3 10 11 12 13 ringcid ⊢ φ ∧ X ∈ B → Id ⁡ R ⁡ X = I ↾ Base X
15 9 14 fveq12d ⊢ φ ∧ X ∈ B → X G X ⁡ Id ⁡ R ⁡ X = I ↾ X RingHom X ⁡ I ↾ Base X
16 1 3 5 ringcbas ⊢ φ → B = U ∩ Ring
17 16 eleq2d ⊢ φ → X ∈ B ↔ X ∈ U ∩ Ring
18 elin ⊢ X ∈ U ∩ Ring ↔ X ∈ U ∧ X ∈ Ring
19 18 simprbi ⊢ X ∈ U ∩ Ring → X ∈ Ring
20 17 19 biimtrdi ⊢ φ → X ∈ B → X ∈ Ring
21 20 imp ⊢ φ ∧ X ∈ B → X ∈ Ring
22 13 idrhm ⊢ X ∈ Ring → I ↾ Base X ∈ X RingHom X
23 fvresi ⊢ I ↾ Base X ∈ X RingHom X → I ↾ X RingHom X ⁡ I ↾ Base X = I ↾ Base X
24 21 22 23 3syl ⊢ φ ∧ X ∈ B → I ↾ X RingHom X ⁡ I ↾ Base X = I ↾ Base X
25 1 2 3 4 5 6 funcringcsetcALTV2lem1 ⊢ φ ∧ X ∈ B → F ⁡ X = Base X
26 25 fveq2d ⊢ φ ∧ X ∈ B → Id ⁡ S ⁡ F ⁡ X = Id ⁡ S ⁡ Base X
27 eqid ⊢ Id ⁡ S = Id ⁡ S
28 1 3 5 ringcbasbas ⊢ φ ∧ X ∈ B → Base X ∈ U
29 2 27 11 28 setcid ⊢ φ ∧ X ∈ B → Id ⁡ S ⁡ Base X = I ↾ Base X
30 26 29 eqtr2d ⊢ φ ∧ X ∈ B → I ↾ Base X = Id ⁡ S ⁡ F ⁡ X
31 15 24 30 3eqtrd ⊢ φ ∧ X ∈ B → X G X ⁡ Id ⁡ R ⁡ X = Id ⁡ S ⁡ F ⁡ X