Metamath Proof Explorer


Theorem hgmapvs

Description: Part 15 of Baer p. 50 line 6. Also line 15 in Holland95 p. 14. (Contributed by NM, 6-Jun-2015)

Ref Expression
Hypotheses hgmapvs.h ⊢ H = LHyp ⁡ K
hgmapvs.u ⊢ U = DVecH ⁡ K ⁡ W
hgmapvs.v ⊢ V = Base U
hgmapvs.t ⊢ · ˙ = ⋅ U
hgmapvs.r ⊢ R = Scalar ⁡ U
hgmapvs.b ⊢ B = Base R
hgmapvs.c ⊢ C = LCDual ⁡ K ⁡ W
hgmapvs.e ⊢ ∙ ˙ = ⋅ C
hgmapvs.s ⊢ S = HDMap ⁡ K ⁡ W
hgmapvs.g ⊢ G = HGMap ⁡ K ⁡ W
hgmapvs.k ⊢ φ → K ∈ HL ∧ W ∈ H
hgmapvs.x ⊢ φ → X ∈ V
hgmapvs.f ⊢ φ → F ∈ B
Assertion hgmapvs ⊢ φ → S ⁡ F · ˙ X = G ⁡ F ∙ ˙ S ⁡ X

Proof

Step Hyp Ref Expression
1 hgmapvs.h ⊢ H = LHyp ⁡ K
2 hgmapvs.u ⊢ U = DVecH ⁡ K ⁡ W
3 hgmapvs.v ⊢ V = Base U
4 hgmapvs.t ⊢ · ˙ = ⋅ U
5 hgmapvs.r ⊢ R = Scalar ⁡ U
6 hgmapvs.b ⊢ B = Base R
7 hgmapvs.c ⊢ C = LCDual ⁡ K ⁡ W
8 hgmapvs.e ⊢ ∙ ˙ = ⋅ C
9 hgmapvs.s ⊢ S = HDMap ⁡ K ⁡ W
10 hgmapvs.g ⊢ G = HGMap ⁡ K ⁡ W
11 hgmapvs.k ⊢ φ → K ∈ HL ∧ W ∈ H
12 hgmapvs.x ⊢ φ → X ∈ V
13 hgmapvs.f ⊢ φ → F ∈ B
14 1 2 3 4 5 6 7 8 9 10 11 13 hgmapval ⊢ φ → G ⁡ F = ι g ∈ B | ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
15 14 eqcomd ⊢ φ → ι g ∈ B | ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x = G ⁡ F
16 1 2 5 6 10 11 13 hgmapcl ⊢ φ → G ⁡ F ∈ B
17 1 2 3 4 5 6 7 8 9 11 13 hdmap14lem15 ⊢ φ → ∃! g ∈ B ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
18 oveq1 ⊢ g = G ⁡ F → g ∙ ˙ S ⁡ x = G ⁡ F ∙ ˙ S ⁡ x
19 18 eqeq2d ⊢ g = G ⁡ F → S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x ↔ S ⁡ F · ˙ x = G ⁡ F ∙ ˙ S ⁡ x
20 19 ralbidv ⊢ g = G ⁡ F → ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x ↔ ∀ x ∈ V S ⁡ F · ˙ x = G ⁡ F ∙ ˙ S ⁡ x
21 20 riota2 ⊢ G ⁡ F ∈ B ∧ ∃! g ∈ B ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x → ∀ x ∈ V S ⁡ F · ˙ x = G ⁡ F ∙ ˙ S ⁡ x ↔ ι g ∈ B | ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x = G ⁡ F
22 16 17 21 syl2anc ⊢ φ → ∀ x ∈ V S ⁡ F · ˙ x = G ⁡ F ∙ ˙ S ⁡ x ↔ ι g ∈ B | ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x = G ⁡ F
23 15 22 mpbird ⊢ φ → ∀ x ∈ V S ⁡ F · ˙ x = G ⁡ F ∙ ˙ S ⁡ x
24 oveq2 ⊢ x = X → F · ˙ x = F · ˙ X
25 24 fveq2d ⊢ x = X → S ⁡ F · ˙ x = S ⁡ F · ˙ X
26 fveq2 ⊢ x = X → S ⁡ x = S ⁡ X
27 26 oveq2d ⊢ x = X → G ⁡ F ∙ ˙ S ⁡ x = G ⁡ F ∙ ˙ S ⁡ X
28 25 27 eqeq12d ⊢ x = X → S ⁡ F · ˙ x = G ⁡ F ∙ ˙ S ⁡ x ↔ S ⁡ F · ˙ X = G ⁡ F ∙ ˙ S ⁡ X
29 28 rspcva ⊢ X ∈ V ∧ ∀ x ∈ V S ⁡ F · ˙ x = G ⁡ F ∙ ˙ S ⁡ x → S ⁡ F · ˙ X = G ⁡ F ∙ ˙ S ⁡ X
30 12 23 29 syl2anc ⊢ φ → S ⁡ F · ˙ X = G ⁡ F ∙ ˙ S ⁡ X