Metamath Proof Explorer


Theorem hlhilsrnglem

Description: Lemma for hlhilsrng . (Contributed by NM, 21-Jun-2015) (Revised by Mario Carneiro, 28-Jun-2015)

Ref Expression
Hypotheses hlhillvec.h ⊢ H = LHyp ⁡ K
hlhillvec.u ⊢ U = HLHil ⁡ K ⁡ W
hlhillvec.k ⊢ φ → K ∈ HL ∧ W ∈ H
hlhildrng.r ⊢ R = Scalar ⁡ U
hlhilsrng.l ⊢ L = DVecH ⁡ K ⁡ W
hlhilsrng.s ⊢ S = Scalar ⁡ L
hlhilsrng.b ⊢ B = Base S
hlhilsrng.p ⊢ + ˙ = + S
hlhilsrng.t ⊢ · ˙ = ⋅ S
hlhilsrng.g ⊢ G = HGMap ⁡ K ⁡ W
Assertion hlhilsrnglem ⊢ φ → R ∈ *-Ring

Proof

Step Hyp Ref Expression
1 hlhillvec.h ⊢ H = LHyp ⁡ K
2 hlhillvec.u ⊢ U = HLHil ⁡ K ⁡ W
3 hlhillvec.k ⊢ φ → K ∈ HL ∧ W ∈ H
4 hlhildrng.r ⊢ R = Scalar ⁡ U
5 hlhilsrng.l ⊢ L = DVecH ⁡ K ⁡ W
6 hlhilsrng.s ⊢ S = Scalar ⁡ L
7 hlhilsrng.b ⊢ B = Base S
8 hlhilsrng.p ⊢ + ˙ = + S
9 hlhilsrng.t ⊢ · ˙ = ⋅ S
10 hlhilsrng.g ⊢ G = HGMap ⁡ K ⁡ W
11 1 5 6 2 4 3 7 hlhilsbase2 ⊢ φ → B = Base R
12 1 5 6 2 4 3 8 hlhilsplus2 ⊢ φ → + ˙ = + R
13 1 5 6 2 4 3 9 hlhilsmul2 ⊢ φ → · ˙ = ⋅ R
14 1 2 4 10 3 hlhilnvl ⊢ φ → G = * R
15 1 2 3 4 hlhildrng ⊢ φ → R ∈ DivRing
16 drngring ⊢ R ∈ DivRing → R ∈ Ring
17 15 16 syl ⊢ φ → R ∈ Ring
18 3 adantr ⊢ φ ∧ x ∈ B → K ∈ HL ∧ W ∈ H
19 simpr ⊢ φ ∧ x ∈ B → x ∈ B
20 1 5 6 7 10 18 19 hgmapcl ⊢ φ ∧ x ∈ B → G ⁡ x ∈ B
21 3 3ad2ant1 ⊢ φ ∧ x ∈ B ∧ y ∈ B → K ∈ HL ∧ W ∈ H
22 simp2 ⊢ φ ∧ x ∈ B ∧ y ∈ B → x ∈ B
23 simp3 ⊢ φ ∧ x ∈ B ∧ y ∈ B → y ∈ B
24 1 5 6 7 8 10 21 22 23 hgmapadd ⊢ φ ∧ x ∈ B ∧ y ∈ B → G ⁡ x + ˙ y = G ⁡ x + ˙ G ⁡ y
25 1 5 6 7 9 10 21 22 23 hgmapmul ⊢ φ ∧ x ∈ B ∧ y ∈ B → G ⁡ x · ˙ y = G ⁡ y · ˙ G ⁡ x
26 1 5 6 7 10 18 19 hgmapvv ⊢ φ ∧ x ∈ B → G ⁡ G ⁡ x = x
27 11 12 13 14 17 20 24 25 26 issrngd ⊢ φ → R ∈ *-Ring