Metamath Proof Explorer


Theorem idlsrgmulrss2

Description: The product of two ideals is a subset of the second one. (Contributed by Thierry Arnoux, 2-Jun-2024)

Ref Expression
Hypotheses idlsrgmulrss2.1 ⊢ S = IDLsrg ⁡ R
idlsrgmulrss2.2 ⊢ B = LIdeal ⁡ R
idlsrgmulrss2.3 ⊢ ⊗ ˙ = ⋅ S
idlsrgmulrss2.5 ⊢ · ˙ = ⋅ R
idlsrgmulrss2.6 ⊢ φ → R ∈ Ring
idlsrgmulrss2.7 ⊢ φ → I ∈ B
idlsrgmulrss2.8 ⊢ φ → J ∈ B
Assertion idlsrgmulrss2 ⊢ φ → I ⊗ ˙ J ⊆ J

Proof

Step Hyp Ref Expression
1 idlsrgmulrss2.1 ⊢ S = IDLsrg ⁡ R
2 idlsrgmulrss2.2 ⊢ B = LIdeal ⁡ R
3 idlsrgmulrss2.3 ⊢ ⊗ ˙ = ⋅ S
4 idlsrgmulrss2.5 ⊢ · ˙ = ⋅ R
5 idlsrgmulrss2.6 ⊢ φ → R ∈ Ring
6 idlsrgmulrss2.7 ⊢ φ → I ∈ B
7 idlsrgmulrss2.8 ⊢ φ → J ∈ B
8 eqid ⊢ mulGrp R = mulGrp R
9 eqid ⊢ LSSum ⁡ mulGrp R = LSSum ⁡ mulGrp R
10 1 2 3 8 9 5 6 7 idlsrgmulrval ⊢ φ → I ⊗ ˙ J = RSpan ⁡ R ⁡ I LSSum ⁡ mulGrp R J
11 rlmlmod ⊢ R ∈ Ring → ringLMod ⁡ R ∈ LMod
12 5 11 syl ⊢ φ → ringLMod ⁡ R ∈ LMod
13 eqid ⊢ Base R = Base R
14 13 2 lidlss ⊢ J ∈ B → J ⊆ Base R
15 7 14 syl ⊢ φ → J ⊆ Base R
16 13 2 lidlss ⊢ I ∈ B → I ⊆ Base R
17 6 16 syl ⊢ φ → I ⊆ Base R
18 7 2 eleqtrdi ⊢ φ → J ∈ LIdeal ⁡ R
19 13 8 9 5 17 18 ringlsmss2 ⊢ φ → I LSSum ⁡ mulGrp R J ⊆ J
20 rlmbas ⊢ Base R = Base ringLMod ⁡ R
21 rspval ⊢ RSpan ⁡ R = LSpan ⁡ ringLMod ⁡ R
22 20 21 lspss ⊢ ringLMod ⁡ R ∈ LMod ∧ J ⊆ Base R ∧ I LSSum ⁡ mulGrp R J ⊆ J → RSpan ⁡ R ⁡ I LSSum ⁡ mulGrp R J ⊆ RSpan ⁡ R ⁡ J
23 12 15 19 22 syl3anc ⊢ φ → RSpan ⁡ R ⁡ I LSSum ⁡ mulGrp R J ⊆ RSpan ⁡ R ⁡ J
24 eqid ⊢ RSpan ⁡ R = RSpan ⁡ R
25 24 2 rspidlid ⊢ R ∈ Ring ∧ J ∈ B → RSpan ⁡ R ⁡ J = J
26 5 7 25 syl2anc ⊢ φ → RSpan ⁡ R ⁡ J = J
27 23 26 sseqtrd ⊢ φ → RSpan ⁡ R ⁡ I LSSum ⁡ mulGrp R J ⊆ J
28 10 27 eqsstrd ⊢ φ → I ⊗ ˙ J ⊆ J