Metamath Proof Explorer


Theorem invrpropd

Description: The ring inverse function depends only on the ring's base set and multiplication operation. (Contributed by Mario Carneiro, 26-Dec-2014) (Revised by Mario Carneiro, 5-Oct-2015)

Ref Expression
Hypotheses rngidpropd.1 ⊢ φ → B = Base K
rngidpropd.2 ⊢ φ → B = Base L
rngidpropd.3 ⊢ φ ∧ x ∈ B ∧ y ∈ B → x ⋅ K y = x ⋅ L y
Assertion invrpropd ⊢ φ → inv r ⁡ K = inv r ⁡ L

Proof

Step Hyp Ref Expression
1 rngidpropd.1 ⊢ φ → B = Base K
2 rngidpropd.2 ⊢ φ → B = Base L
3 rngidpropd.3 ⊢ φ ∧ x ∈ B ∧ y ∈ B → x ⋅ K y = x ⋅ L y
4 eqid ⊢ Unit ⁡ K = Unit ⁡ K
5 eqid ⊢ mulGrp K ↾ 𝑠 Unit ⁡ K = mulGrp K ↾ 𝑠 Unit ⁡ K
6 4 5 unitgrpbas ⊢ Unit ⁡ K = Base mulGrp K ↾ 𝑠 Unit ⁡ K
7 6 a1i ⊢ φ → Unit ⁡ K = Base mulGrp K ↾ 𝑠 Unit ⁡ K
8 1 2 3 unitpropd ⊢ φ → Unit ⁡ K = Unit ⁡ L
9 eqid ⊢ Unit ⁡ L = Unit ⁡ L
10 eqid ⊢ mulGrp L ↾ 𝑠 Unit ⁡ L = mulGrp L ↾ 𝑠 Unit ⁡ L
11 9 10 unitgrpbas ⊢ Unit ⁡ L = Base mulGrp L ↾ 𝑠 Unit ⁡ L
12 8 11 eqtrdi ⊢ φ → Unit ⁡ K = Base mulGrp L ↾ 𝑠 Unit ⁡ L
13 eqid ⊢ Base K = Base K
14 13 4 unitss ⊢ Unit ⁡ K ⊆ Base K
15 14 1 sseqtrrid ⊢ φ → Unit ⁡ K ⊆ B
16 15 sselda ⊢ φ ∧ x ∈ Unit ⁡ K → x ∈ B
17 15 sselda ⊢ φ ∧ y ∈ Unit ⁡ K → y ∈ B
18 16 17 anim12dan ⊢ φ ∧ x ∈ Unit ⁡ K ∧ y ∈ Unit ⁡ K → x ∈ B ∧ y ∈ B
19 18 3 syldan ⊢ φ ∧ x ∈ Unit ⁡ K ∧ y ∈ Unit ⁡ K → x ⋅ K y = x ⋅ L y
20 fvex ⊢ Unit ⁡ K ∈ V
21 eqid ⊢ mulGrp K = mulGrp K
22 eqid ⊢ ⋅ K = ⋅ K
23 21 22 mgpplusg ⊢ ⋅ K = + mulGrp K
24 5 23 ressplusg ⊢ Unit ⁡ K ∈ V → ⋅ K = + mulGrp K ↾ 𝑠 Unit ⁡ K
25 20 24 ax-mp ⊢ ⋅ K = + mulGrp K ↾ 𝑠 Unit ⁡ K
26 25 oveqi ⊢ x ⋅ K y = x + mulGrp K ↾ 𝑠 Unit ⁡ K y
27 fvex ⊢ Unit ⁡ L ∈ V
28 eqid ⊢ mulGrp L = mulGrp L
29 eqid ⊢ ⋅ L = ⋅ L
30 28 29 mgpplusg ⊢ ⋅ L = + mulGrp L
31 10 30 ressplusg ⊢ Unit ⁡ L ∈ V → ⋅ L = + mulGrp L ↾ 𝑠 Unit ⁡ L
32 27 31 ax-mp ⊢ ⋅ L = + mulGrp L ↾ 𝑠 Unit ⁡ L
33 32 oveqi ⊢ x ⋅ L y = x + mulGrp L ↾ 𝑠 Unit ⁡ L y
34 19 26 33 3eqtr3g ⊢ φ ∧ x ∈ Unit ⁡ K ∧ y ∈ Unit ⁡ K → x + mulGrp K ↾ 𝑠 Unit ⁡ K y = x + mulGrp L ↾ 𝑠 Unit ⁡ L y
35 7 12 34 grpinvpropd ⊢ φ → inv g ⁡ mulGrp K ↾ 𝑠 Unit ⁡ K = inv g ⁡ mulGrp L ↾ 𝑠 Unit ⁡ L
36 eqid ⊢ inv r ⁡ K = inv r ⁡ K
37 4 5 36 invrfval ⊢ inv r ⁡ K = inv g ⁡ mulGrp K ↾ 𝑠 Unit ⁡ K
38 eqid ⊢ inv r ⁡ L = inv r ⁡ L
39 9 10 38 invrfval ⊢ inv r ⁡ L = inv g ⁡ mulGrp L ↾ 𝑠 Unit ⁡ L
40 35 37 39 3eqtr4g ⊢ φ → inv r ⁡ K = inv r ⁡ L