Metamath Proof Explorer


Theorem knoppndvlem22

Description: Lemma for knoppndv . (Contributed by Asger C. Ipsen, 19-Aug-2021)

Ref Expression
Hypotheses knoppndvlem22.t ⊢ T = x ∈ ℝ ⟼ x + 1 2 − x
knoppndvlem22.f ⊢ F = y ∈ ℝ ⟼ n ∈ ℕ 0 ⟼ C n ⁢ T ⁡ 2 ⋅ N n ⁢ y
knoppndvlem22.w ⊢ W = w ∈ ℝ ⟼ ∑ i ∈ ℕ 0 F ⁡ w ⁡ i
knoppndvlem22.c ⊢ φ → C ∈ − 1 1
knoppndvlem22.d ⊢ φ → D ∈ ℝ +
knoppndvlem22.e ⊢ φ → E ∈ ℝ +
knoppndvlem22.h ⊢ φ → H ∈ ℝ
knoppndvlem22.n ⊢ φ → N ∈ ℕ
knoppndvlem22.1 ⊢ φ → 1 < N ⁢ C
Assertion knoppndvlem22 ⊢ φ → ∃ a ∈ ℝ ∃ b ∈ ℝ a ≤ H ∧ H ≤ b ∧ b − a < D ∧ a ≠ b ∧ E ≤ W ⁡ b − W ⁡ a b − a

Proof

Step Hyp Ref Expression
1 knoppndvlem22.t ⊢ T = x ∈ ℝ ⟼ x + 1 2 − x
2 knoppndvlem22.f ⊢ F = y ∈ ℝ ⟼ n ∈ ℕ 0 ⟼ C n ⁢ T ⁡ 2 ⋅ N n ⁢ y
3 knoppndvlem22.w ⊢ W = w ∈ ℝ ⟼ ∑ i ∈ ℕ 0 F ⁡ w ⁡ i
4 knoppndvlem22.c ⊢ φ → C ∈ − 1 1
5 knoppndvlem22.d ⊢ φ → D ∈ ℝ +
6 knoppndvlem22.e ⊢ φ → E ∈ ℝ +
7 knoppndvlem22.h ⊢ φ → H ∈ ℝ
8 knoppndvlem22.n ⊢ φ → N ∈ ℕ
9 knoppndvlem22.1 ⊢ φ → 1 < N ⁢ C
10 4 8 9 knoppndvlem20 ⊢ φ → 1 − 1 2 ⋅ N ⁢ C − 1 ∈ ℝ +
11 4 8 5 6 10 9 knoppndvlem18 ⊢ φ → ∃ j ∈ ℕ 0 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1
12 eqid ⊢ 1 − 1 2 ⋅ N ⁢ C − 1 = 1 − 1 2 ⋅ N ⁢ C − 1
13 4 adantr ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → C ∈ − 1 1
14 5 adantr ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → D ∈ ℝ +
15 6 adantr ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → E ∈ ℝ +
16 7 adantr ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → H ∈ ℝ
17 simprl ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → j ∈ ℕ 0
18 8 adantr ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → N ∈ ℕ
19 9 adantr ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → 1 < N ⁢ C
20 simprrl ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → 2 ⋅ N − j 2 < D
21 simprrr ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1
22 1 2 3 12 13 14 15 16 17 18 19 20 21 knoppndvlem21 ⊢ φ ∧ j ∈ ℕ 0 ∧ 2 ⋅ N − j 2 < D ∧ E ≤ 2 ⋅ N ⁢ C j ⁢ 1 − 1 2 ⋅ N ⁢ C − 1 → ∃ a ∈ ℝ ∃ b ∈ ℝ a ≤ H ∧ H ≤ b ∧ b − a < D ∧ a ≠ b ∧ E ≤ W ⁡ b − W ⁡ a b − a
23 11 22 rexlimddv ⊢ φ → ∃ a ∈ ℝ ∃ b ∈ ℝ a ≤ H ∧ H ≤ b ∧ b − a < D ∧ a ≠ b ∧ E ≤ W ⁡ b − W ⁡ a b − a