Metamath Proof Explorer


Theorem lcfrlem7

Description: Lemma for lcfr . Closure of vector sum when one vector is zero. TODO: share hypotheses with others. (Contributed by NM, 11-Mar-2015)

Ref Expression
Hypotheses lcfrlem7.h ⊢ H = LHyp ⁡ K
lcfrlem7.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lcfrlem7.u ⊢ U = DVecH ⁡ K ⁡ W
lcfrlem7.p ⊢ + ˙ = + U
lcfrlem7.l ⊢ L = LKer ⁡ U
lcfrlem7.d ⊢ D = LDual ⁡ U
lcfrlem7.q ⊢ Q = LSubSp ⁡ D
lcfrlem7.k ⊢ φ → K ∈ HL ∧ W ∈ H
lcfrlem7.g ⊢ φ → G ∈ Q
lcfrlem7.e ⊢ E = ⋃ g ∈ G ⊥ ˙ ⁡ L ⁡ g
lcfrlem7.x ⊢ φ → X ∈ E
lcfrlem7.z ⊢ 0 ˙ = 0 U
lcfrlem7.y ⊢ φ → Y = 0 ˙
Assertion lcfrlem7 ⊢ φ → X + ˙ Y ∈ E

Proof

Step Hyp Ref Expression
1 lcfrlem7.h ⊢ H = LHyp ⁡ K
2 lcfrlem7.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 lcfrlem7.u ⊢ U = DVecH ⁡ K ⁡ W
4 lcfrlem7.p ⊢ + ˙ = + U
5 lcfrlem7.l ⊢ L = LKer ⁡ U
6 lcfrlem7.d ⊢ D = LDual ⁡ U
7 lcfrlem7.q ⊢ Q = LSubSp ⁡ D
8 lcfrlem7.k ⊢ φ → K ∈ HL ∧ W ∈ H
9 lcfrlem7.g ⊢ φ → G ∈ Q
10 lcfrlem7.e ⊢ E = ⋃ g ∈ G ⊥ ˙ ⁡ L ⁡ g
11 lcfrlem7.x ⊢ φ → X ∈ E
12 lcfrlem7.z ⊢ 0 ˙ = 0 U
13 lcfrlem7.y ⊢ φ → Y = 0 ˙
14 13 oveq2d ⊢ φ → X + ˙ Y = X + ˙ 0 ˙
15 1 3 8 dvhlmod ⊢ φ → U ∈ LMod
16 eqid ⊢ Base U = Base U
17 1 2 3 16 5 6 7 10 8 9 11 lcfrlem4 ⊢ φ → X ∈ Base U
18 16 4 12 lmod0vrid ⊢ U ∈ LMod ∧ X ∈ Base U → X + ˙ 0 ˙ = X
19 15 17 18 syl2anc ⊢ φ → X + ˙ 0 ˙ = X
20 14 19 eqtrd ⊢ φ → X + ˙ Y = X
21 20 11 eqeltrd ⊢ φ → X + ˙ Y ∈ E