Metamath Proof Explorer


Theorem logfac

Description: The logarithm of a factorial can be expressed as a finite sum of logs. (Contributed by Mario Carneiro, 17-Apr-2015)

Ref Expression
Assertion logfac ⊢ N ∈ ℕ 0 → log ⁡ N ! = ∑ k = 1 N log ⁡ k

Proof

Step Hyp Ref Expression
1 elnn0 ⊢ N ∈ ℕ 0 ↔ N ∈ ℕ ∨ N = 0
2 rpmulcl ⊢ k ∈ ℝ + ∧ n ∈ ℝ + → k ⁢ n ∈ ℝ +
3 2 adantl ⊢ N ∈ ℕ ∧ k ∈ ℝ + ∧ n ∈ ℝ + → k ⁢ n ∈ ℝ +
4 fvi ⊢ k ∈ V → I ⁡ k = k
5 4 elv ⊢ I ⁡ k = k
6 elfznn ⊢ k ∈ 1 … N → k ∈ ℕ
7 6 adantl ⊢ N ∈ ℕ ∧ k ∈ 1 … N → k ∈ ℕ
8 7 nnrpd ⊢ N ∈ ℕ ∧ k ∈ 1 … N → k ∈ ℝ +
9 5 8 eqeltrid ⊢ N ∈ ℕ ∧ k ∈ 1 … N → I ⁡ k ∈ ℝ +
10 elnnuz ⊢ N ∈ ℕ ↔ N ∈ ℤ ≥ 1
11 10 biimpi ⊢ N ∈ ℕ → N ∈ ℤ ≥ 1
12 relogmul ⊢ k ∈ ℝ + ∧ n ∈ ℝ + → log ⁡ k ⁢ n = log ⁡ k + log ⁡ n
13 12 adantl ⊢ N ∈ ℕ ∧ k ∈ ℝ + ∧ n ∈ ℝ + → log ⁡ k ⁢ n = log ⁡ k + log ⁡ n
14 5 fveq2i ⊢ log ⁡ I ⁡ k = log ⁡ k
15 14 a1i ⊢ N ∈ ℕ ∧ k ∈ 1 … N → log ⁡ I ⁡ k = log ⁡ k
16 3 9 11 13 15 seqhomo ⊢ N ∈ ℕ → log ⁡ seq 1 × I ⁡ N = seq 1 + log ⁡ N
17 facnn ⊢ N ∈ ℕ → N ! = seq 1 × I ⁡ N
18 17 fveq2d ⊢ N ∈ ℕ → log ⁡ N ! = log ⁡ seq 1 × I ⁡ N
19 eqidd ⊢ N ∈ ℕ ∧ k ∈ 1 … N → log ⁡ k = log ⁡ k
20 relogcl ⊢ k ∈ ℝ + → log ⁡ k ∈ ℝ
21 8 20 syl ⊢ N ∈ ℕ ∧ k ∈ 1 … N → log ⁡ k ∈ ℝ
22 21 recnd ⊢ N ∈ ℕ ∧ k ∈ 1 … N → log ⁡ k ∈ ℂ
23 19 11 22 fsumser ⊢ N ∈ ℕ → ∑ k = 1 N log ⁡ k = seq 1 + log ⁡ N
24 16 18 23 3eqtr4d ⊢ N ∈ ℕ → log ⁡ N ! = ∑ k = 1 N log ⁡ k
25 log1 ⊢ log ⁡ 1 = 0
26 sum0 ⊢ ∑ k ∈ ∅ log ⁡ k = 0
27 25 26 eqtr4i ⊢ log ⁡ 1 = ∑ k ∈ ∅ log ⁡ k
28 fveq2 ⊢ N = 0 → N ! = 0 !
29 fac0 ⊢ 0 ! = 1
30 28 29 eqtrdi ⊢ N = 0 → N ! = 1
31 30 fveq2d ⊢ N = 0 → log ⁡ N ! = log ⁡ 1
32 oveq2 ⊢ N = 0 → 1 … N = 1 … 0
33 fz10 ⊢ 1 … 0 = ∅
34 32 33 eqtrdi ⊢ N = 0 → 1 … N = ∅
35 34 sumeq1d ⊢ N = 0 → ∑ k = 1 N log ⁡ k = ∑ k ∈ ∅ log ⁡ k
36 27 31 35 3eqtr4a ⊢ N = 0 → log ⁡ N ! = ∑ k = 1 N log ⁡ k
37 24 36 jaoi ⊢ N ∈ ℕ ∨ N = 0 → log ⁡ N ! = ∑ k = 1 N log ⁡ k
38 1 37 sylbi ⊢ N ∈ ℕ 0 → log ⁡ N ! = ∑ k = 1 N log ⁡ k