Metamath Proof Explorer


Theorem lsatel

Description: A nonzero vector in an atom determines the atom. (Contributed by NM, 25-Aug-2014)

Ref Expression
Hypotheses lsatel.o ⊢ 0 ˙ = 0 W
lsatel.n ⊢ N = LSpan ⁡ W
lsatel.a ⊢ A = LSAtoms ⁡ W
lsatel.w ⊢ φ → W ∈ LVec
lsatel.u ⊢ φ → U ∈ A
lsatel.x ⊢ φ → X ∈ U
lsatel.e ⊢ φ → X ≠ 0 ˙
Assertion lsatel ⊢ φ → U = N ⁡ X

Proof

Step Hyp Ref Expression
1 lsatel.o ⊢ 0 ˙ = 0 W
2 lsatel.n ⊢ N = LSpan ⁡ W
3 lsatel.a ⊢ A = LSAtoms ⁡ W
4 lsatel.w ⊢ φ → W ∈ LVec
5 lsatel.u ⊢ φ → U ∈ A
6 lsatel.x ⊢ φ → X ∈ U
7 lsatel.e ⊢ φ → X ≠ 0 ˙
8 eqid ⊢ LSubSp ⁡ W = LSubSp ⁡ W
9 lveclmod ⊢ W ∈ LVec → W ∈ LMod
10 4 9 syl ⊢ φ → W ∈ LMod
11 8 3 10 5 lsatlssel ⊢ φ → U ∈ LSubSp ⁡ W
12 8 2 10 11 6 ellspsn5 ⊢ φ → N ⁡ X ⊆ U
13 eqid ⊢ Base W = Base W
14 13 8 lssel ⊢ U ∈ LSubSp ⁡ W ∧ X ∈ U → X ∈ Base W
15 11 6 14 syl2anc ⊢ φ → X ∈ Base W
16 13 2 1 3 lsatlspsn2 ⊢ W ∈ LMod ∧ X ∈ Base W ∧ X ≠ 0 ˙ → N ⁡ X ∈ A
17 10 15 7 16 syl3anc ⊢ φ → N ⁡ X ∈ A
18 3 4 17 5 lsatcmp ⊢ φ → N ⁡ X ⊆ U ↔ N ⁡ X = U
19 12 18 mpbid ⊢ φ → N ⁡ X = U
20 19 eqcomd ⊢ φ → U = N ⁡ X