Metamath Proof Explorer


Theorem mapdheq

Description: Lemmma for ~? mapdh . The defining equation for h(x,x',y)=y' in part (2) in Baer p. 45 line 24. (Contributed by NM, 4-Apr-2015)

Ref Expression
Hypotheses mapdh.q ⊢ Q = 0 C
mapdh.i ⊢ I = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h
mapdh.h ⊢ H = LHyp ⁡ K
mapdh.m ⊢ M = mapd ⁡ K ⁡ W
mapdh.u ⊢ U = DVecH ⁡ K ⁡ W
mapdh.v ⊢ V = Base U
mapdh.s ⊢ - ˙ = - U
mapdhc.o ⊢ 0 ˙ = 0 U
mapdh.n ⊢ N = LSpan ⁡ U
mapdh.c ⊢ C = LCDual ⁡ K ⁡ W
mapdh.d ⊢ D = Base C
mapdh.r ⊢ R = - C
mapdh.j ⊢ J = LSpan ⁡ C
mapdh.k ⊢ φ → K ∈ HL ∧ W ∈ H
mapdhc.f ⊢ φ → F ∈ D
mapdh.mn ⊢ φ → M ⁡ N ⁡ X = J ⁡ F
mapdhcl.x ⊢ φ → X ∈ V ∖ 0 ˙
mapdhe.y ⊢ φ → Y ∈ V ∖ 0 ˙
mapdhe.g ⊢ φ → G ∈ D
mapdh.ne2 ⊢ φ → N ⁡ X ≠ N ⁡ Y
Assertion mapdheq ⊢ φ → I ⁡ X F Y = G ↔ M ⁡ N ⁡ Y = J ⁡ G ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R G

Proof

Step Hyp Ref Expression
1 mapdh.q ⊢ Q = 0 C
2 mapdh.i ⊢ I = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h
3 mapdh.h ⊢ H = LHyp ⁡ K
4 mapdh.m ⊢ M = mapd ⁡ K ⁡ W
5 mapdh.u ⊢ U = DVecH ⁡ K ⁡ W
6 mapdh.v ⊢ V = Base U
7 mapdh.s ⊢ - ˙ = - U
8 mapdhc.o ⊢ 0 ˙ = 0 U
9 mapdh.n ⊢ N = LSpan ⁡ U
10 mapdh.c ⊢ C = LCDual ⁡ K ⁡ W
11 mapdh.d ⊢ D = Base C
12 mapdh.r ⊢ R = - C
13 mapdh.j ⊢ J = LSpan ⁡ C
14 mapdh.k ⊢ φ → K ∈ HL ∧ W ∈ H
15 mapdhc.f ⊢ φ → F ∈ D
16 mapdh.mn ⊢ φ → M ⁡ N ⁡ X = J ⁡ F
17 mapdhcl.x ⊢ φ → X ∈ V ∖ 0 ˙
18 mapdhe.y ⊢ φ → Y ∈ V ∖ 0 ˙
19 mapdhe.g ⊢ φ → G ∈ D
20 mapdh.ne2 ⊢ φ → N ⁡ X ≠ N ⁡ Y
21 1 2 17 15 18 mapdhval2 ⊢ φ → I ⁡ X F Y = ι h ∈ D | M ⁡ N ⁡ Y = J ⁡ h ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h
22 21 eqeq1d ⊢ φ → I ⁡ X F Y = G ↔ ι h ∈ D | M ⁡ N ⁡ Y = J ⁡ h ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h = G
23 3 4 5 6 7 8 9 10 11 12 13 14 17 18 15 20 16 mapdpg ⊢ φ → ∃! h ∈ D M ⁡ N ⁡ Y = J ⁡ h ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h
24 nfv ⊢ Ⅎ h φ
25 nfcvd ⊢ φ → Ⅎ _ h G
26 nfvd ⊢ φ → Ⅎ h M ⁡ N ⁡ Y = J ⁡ G ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R G
27 sneq ⊢ h = G → h = G
28 27 fveq2d ⊢ h = G → J ⁡ h = J ⁡ G
29 28 eqeq2d ⊢ h = G → M ⁡ N ⁡ Y = J ⁡ h ↔ M ⁡ N ⁡ Y = J ⁡ G
30 oveq2 ⊢ h = G → F R h = F R G
31 30 sneqd ⊢ h = G → F R h = F R G
32 31 fveq2d ⊢ h = G → J ⁡ F R h = J ⁡ F R G
33 32 eqeq2d ⊢ h = G → M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h ↔ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R G
34 29 33 anbi12d ⊢ h = G → M ⁡ N ⁡ Y = J ⁡ h ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h ↔ M ⁡ N ⁡ Y = J ⁡ G ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R G
35 34 adantl ⊢ φ ∧ h = G → M ⁡ N ⁡ Y = J ⁡ h ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h ↔ M ⁡ N ⁡ Y = J ⁡ G ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R G
36 24 25 26 19 35 riota2df ⊢ φ ∧ ∃! h ∈ D M ⁡ N ⁡ Y = J ⁡ h ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h → M ⁡ N ⁡ Y = J ⁡ G ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R G ↔ ι h ∈ D | M ⁡ N ⁡ Y = J ⁡ h ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h = G
37 23 36 mpdan ⊢ φ → M ⁡ N ⁡ Y = J ⁡ G ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R G ↔ ι h ∈ D | M ⁡ N ⁡ Y = J ⁡ h ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R h = G
38 22 37 bitr4d ⊢ φ → I ⁡ X F Y = G ↔ M ⁡ N ⁡ Y = J ⁡ G ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R G