Metamath Proof Explorer


Theorem mendvscafval

Description: Scalar multiplication in the module endomorphism algebra. (Contributed by Stefan O'Rear, 2-Sep-2015) (Proof shortened by AV, 31-Oct-2024)

Ref Expression
Hypotheses mendvscafval.a ⊢ A = MEndo ⁡ M
mendvscafval.v ⊢ · ˙ = ⋅ M
mendvscafval.b ⊢ B = Base A
mendvscafval.s ⊢ S = Scalar ⁡ M
mendvscafval.k ⊢ K = Base S
mendvscafval.e ⊢ E = Base M
Assertion mendvscafval ⊢ ⋅ A = x ∈ K , y ∈ B ⟼ E × x · ˙ f y

Proof

Step Hyp Ref Expression
1 mendvscafval.a ⊢ A = MEndo ⁡ M
2 mendvscafval.v ⊢ · ˙ = ⋅ M
3 mendvscafval.b ⊢ B = Base A
4 mendvscafval.s ⊢ S = Scalar ⁡ M
5 mendvscafval.k ⊢ K = Base S
6 mendvscafval.e ⊢ E = Base M
7 1 fveq2i ⊢ ⋅ A = ⋅ MEndo ⁡ M
8 1 mendbas ⊢ M LMHom M = Base A
9 3 8 eqtr4i ⊢ B = M LMHom M
10 eqid ⊢ x ∈ B , y ∈ B ⟼ x + M f y = x ∈ B , y ∈ B ⟼ x + M f y
11 eqid ⊢ x ∈ B , y ∈ B ⟼ x ∘ y = x ∈ B , y ∈ B ⟼ x ∘ y
12 eqid ⊢ B = B
13 6 xpeq1i ⊢ E × x = Base M × x
14 eqid ⊢ y = y
15 ofeq ⊢ · ˙ = ⋅ M → ∘ f ⁡ · ˙ = ∘ f ⁡ ⋅ M
16 2 15 ax-mp ⊢ ∘ f ⁡ · ˙ = ∘ f ⁡ ⋅ M
17 13 14 16 oveq123i ⊢ E × x · ˙ f y = Base M × x ⋅ M f y
18 5 12 17 mpoeq123i ⊢ x ∈ K , y ∈ B ⟼ E × x · ˙ f y = x ∈ Base S , y ∈ B ⟼ Base M × x ⋅ M f y
19 9 10 11 4 18 mendval ⊢ M ∈ V → MEndo ⁡ M = Base ndx B + ndx x ∈ B , y ∈ B ⟼ x + M f y ⋅ ndx x ∈ B , y ∈ B ⟼ x ∘ y ∪ Scalar ⁡ ndx S ⋅ ndx x ∈ K , y ∈ B ⟼ E × x · ˙ f y
20 19 fveq2d ⊢ M ∈ V → ⋅ MEndo ⁡ M = ⋅ Base ndx B + ndx x ∈ B , y ∈ B ⟼ x + M f y ⋅ ndx x ∈ B , y ∈ B ⟼ x ∘ y ∪ Scalar ⁡ ndx S ⋅ ndx x ∈ K , y ∈ B ⟼ E × x · ˙ f y
21 5 fvexi ⊢ K ∈ V
22 3 fvexi ⊢ B ∈ V
23 21 22 mpoex ⊢ x ∈ K , y ∈ B ⟼ E × x · ˙ f y ∈ V
24 eqid ⊢ Base ndx B + ndx x ∈ B , y ∈ B ⟼ x + M f y ⋅ ndx x ∈ B , y ∈ B ⟼ x ∘ y ∪ Scalar ⁡ ndx S ⋅ ndx x ∈ K , y ∈ B ⟼ E × x · ˙ f y = Base ndx B + ndx x ∈ B , y ∈ B ⟼ x + M f y ⋅ ndx x ∈ B , y ∈ B ⟼ x ∘ y ∪ Scalar ⁡ ndx S ⋅ ndx x ∈ K , y ∈ B ⟼ E × x · ˙ f y
25 24 algvsca ⊢ x ∈ K , y ∈ B ⟼ E × x · ˙ f y ∈ V → x ∈ K , y ∈ B ⟼ E × x · ˙ f y = ⋅ Base ndx B + ndx x ∈ B , y ∈ B ⟼ x + M f y ⋅ ndx x ∈ B , y ∈ B ⟼ x ∘ y ∪ Scalar ⁡ ndx S ⋅ ndx x ∈ K , y ∈ B ⟼ E × x · ˙ f y
26 23 25 mp1i ⊢ M ∈ V → x ∈ K , y ∈ B ⟼ E × x · ˙ f y = ⋅ Base ndx B + ndx x ∈ B , y ∈ B ⟼ x + M f y ⋅ ndx x ∈ B , y ∈ B ⟼ x ∘ y ∪ Scalar ⁡ ndx S ⋅ ndx x ∈ K , y ∈ B ⟼ E × x · ˙ f y
27 20 26 eqtr4d ⊢ M ∈ V → ⋅ MEndo ⁡ M = x ∈ K , y ∈ B ⟼ E × x · ˙ f y
28 fvprc ⊢ ¬ M ∈ V → MEndo ⁡ M = ∅
29 28 fveq2d ⊢ ¬ M ∈ V → ⋅ MEndo ⁡ M = ⋅ ∅
30 vscaid ⊢ ⋅ 𝑠 = Slot ⋅ ndx
31 30 str0 ⊢ ∅ = ⋅ ∅
32 29 31 eqtr4di ⊢ ¬ M ∈ V → ⋅ MEndo ⁡ M = ∅
33 fvprc ⊢ ¬ M ∈ V → Scalar ⁡ M = ∅
34 4 33 eqtrid ⊢ ¬ M ∈ V → S = ∅
35 34 fveq2d ⊢ ¬ M ∈ V → Base S = Base ∅
36 base0 ⊢ ∅ = Base ∅
37 35 5 36 3eqtr4g ⊢ ¬ M ∈ V → K = ∅
38 37 orcd ⊢ ¬ M ∈ V → K = ∅ ∨ B = ∅
39 0mpo0 ⊢ K = ∅ ∨ B = ∅ → x ∈ K , y ∈ B ⟼ E × x · ˙ f y = ∅
40 38 39 syl ⊢ ¬ M ∈ V → x ∈ K , y ∈ B ⟼ E × x · ˙ f y = ∅
41 32 40 eqtr4d ⊢ ¬ M ∈ V → ⋅ MEndo ⁡ M = x ∈ K , y ∈ B ⟼ E × x · ˙ f y
42 27 41 pm2.61i ⊢ ⋅ MEndo ⁡ M = x ∈ K , y ∈ B ⟼ E × x · ˙ f y
43 7 42 eqtri ⊢ ⋅ A = x ∈ K , y ∈ B ⟼ E × x · ˙ f y