Metamath Proof Explorer


Theorem ngpds3

Description: Write the distance between two points in terms of distance from zero. (Contributed by Mario Carneiro, 2-Oct-2015)

Ref Expression
Hypotheses ngpds2.x ⊢ X = Base G
ngpds2.z ⊢ 0 ˙ = 0 G
ngpds2.m ⊢ - ˙ = - G
ngpds2.d ⊢ D = dist ⁡ G
Assertion ngpds3 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A D B = 0 ˙ D A - ˙ B

Proof

Step Hyp Ref Expression
1 ngpds2.x ⊢ X = Base G
2 ngpds2.z ⊢ 0 ˙ = 0 G
3 ngpds2.m ⊢ - ˙ = - G
4 ngpds2.d ⊢ D = dist ⁡ G
5 1 2 3 4 ngpds2 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A D B = A - ˙ B D 0 ˙
6 ngpxms ⊢ G ∈ NrmGrp → G ∈ ∞MetSp
7 6 3ad2ant1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → G ∈ ∞MetSp
8 ngpgrp ⊢ G ∈ NrmGrp → G ∈ Grp
9 1 3 grpsubcl ⊢ G ∈ Grp ∧ A ∈ X ∧ B ∈ X → A - ˙ B ∈ X
10 8 9 syl3an1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A - ˙ B ∈ X
11 8 3ad2ant1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → G ∈ Grp
12 1 2 grpidcl ⊢ G ∈ Grp → 0 ˙ ∈ X
13 11 12 syl ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → 0 ˙ ∈ X
14 1 4 xmssym ⊢ G ∈ ∞MetSp ∧ A - ˙ B ∈ X ∧ 0 ˙ ∈ X → A - ˙ B D 0 ˙ = 0 ˙ D A - ˙ B
15 7 10 13 14 syl3anc ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A - ˙ B D 0 ˙ = 0 ˙ D A - ˙ B
16 5 15 eqtrd ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A D B = 0 ˙ D A - ˙ B