Metamath Proof Explorer


Theorem noinfepfnregs

Description: There are no infinite descending e. -chains, proven using ax-regs . (Contributed by BTernaryTau, 18-Feb-2026)

Ref Expression
Assertion noinfepfnregs F Fn ω x ω F suc x F x

Proof

Step Hyp Ref Expression
1 peano1 ω
2 1 n0ii ¬ ω =
3 ssid ω ω
4 fnimaeq0 F Fn ω ω ω F ω = ω =
5 3 4 mpan2 F Fn ω F ω = ω =
6 2 5 mtbiri F Fn ω ¬ F ω =
7 6 neqned F Fn ω F ω
8 axregszf F ω y F ω y F ω =
9 7 8 syl F Fn ω y F ω y F ω =
10 fvelimab F Fn ω ω ω y F ω x ω F x = y
11 3 10 mpan2 F Fn ω y F ω x ω F x = y
12 11 adantr F Fn ω y F ω = y F ω x ω F x = y
13 simprl F Fn ω y F ω = x ω F x = y x ω
14 peano2 x ω suc x ω
15 fnfvima F Fn ω ω ω suc x ω F suc x F ω
16 3 15 mp3an2 F Fn ω suc x ω F suc x F ω
17 14 16 sylan2 F Fn ω x ω F suc x F ω
18 17 ad2ant2r F Fn ω y F ω = x ω F x = y F suc x F ω
19 ineq1 F x = y F x F ω = y F ω
20 19 eqeq1d F x = y F x F ω = y F ω =
21 20 biimparc y F ω = F x = y F x F ω =
22 21 ad2ant2l F Fn ω y F ω = x ω F x = y F x F ω =
23 minel F suc x F ω F x F ω = ¬ F suc x F x
24 18 22 23 syl2anc F Fn ω y F ω = x ω F x = y ¬ F suc x F x
25 df-nel F suc x F x ¬ F suc x F x
26 24 25 sylibr F Fn ω y F ω = x ω F x = y F suc x F x
27 13 26 jca F Fn ω y F ω = x ω F x = y x ω F suc x F x
28 27 ex F Fn ω y F ω = x ω F x = y x ω F suc x F x
29 28 reximdv2 F Fn ω y F ω = x ω F x = y x ω F suc x F x
30 12 29 sylbid F Fn ω y F ω = y F ω x ω F suc x F x
31 30 expimpd F Fn ω y F ω = y F ω x ω F suc x F x
32 31 ancomsd F Fn ω y F ω y F ω = x ω F suc x F x
33 32 imp F Fn ω y F ω y F ω = x ω F suc x F x
34 9 33 rexlimddv F Fn ω x ω F suc x F x