Metamath Proof Explorer


Theorem nrmsep

Description: In a normal space, disjoint closed sets are separated by open sets. (Contributed by Jeff Hankins, 1-Feb-2010)

Ref Expression
Assertion nrmsep ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ → ∃ x ∈ J ∃ y ∈ J C ⊆ x ∧ D ⊆ y ∧ x ∩ y = ∅

Proof

Step Hyp Ref Expression
1 nrmtop ⊢ J ∈ Nrm → J ∈ Top
2 1 ad2antrr ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → J ∈ Top
3 elssuni ⊢ x ∈ J → x ⊆ ⋃ J
4 3 ad2antrl ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → x ⊆ ⋃ J
5 eqid ⊢ ⋃ J = ⋃ J
6 5 clscld ⊢ J ∈ Top ∧ x ⊆ ⋃ J → cls ⁡ J ⁡ x ∈ Clsd ⁡ J
7 2 4 6 syl2anc ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → cls ⁡ J ⁡ x ∈ Clsd ⁡ J
8 5 cldopn ⊢ cls ⁡ J ⁡ x ∈ Clsd ⁡ J → ⋃ J ∖ cls ⁡ J ⁡ x ∈ J
9 7 8 syl ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → ⋃ J ∖ cls ⁡ J ⁡ x ∈ J
10 simprrl ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → C ⊆ x
11 incom ⊢ D ∩ cls ⁡ J ⁡ x = cls ⁡ J ⁡ x ∩ D
12 simprrr ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → cls ⁡ J ⁡ x ∩ D = ∅
13 11 12 eqtrid ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → D ∩ cls ⁡ J ⁡ x = ∅
14 simplr2 ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → D ∈ Clsd ⁡ J
15 5 cldss ⊢ D ∈ Clsd ⁡ J → D ⊆ ⋃ J
16 reldisj ⊢ D ⊆ ⋃ J → D ∩ cls ⁡ J ⁡ x = ∅ ↔ D ⊆ ⋃ J ∖ cls ⁡ J ⁡ x
17 14 15 16 3syl ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → D ∩ cls ⁡ J ⁡ x = ∅ ↔ D ⊆ ⋃ J ∖ cls ⁡ J ⁡ x
18 13 17 mpbid ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → D ⊆ ⋃ J ∖ cls ⁡ J ⁡ x
19 5 sscls ⊢ J ∈ Top ∧ x ⊆ ⋃ J → x ⊆ cls ⁡ J ⁡ x
20 2 4 19 syl2anc ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → x ⊆ cls ⁡ J ⁡ x
21 20 ssrind ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → x ∩ ⋃ J ∖ cls ⁡ J ⁡ x ⊆ cls ⁡ J ⁡ x ∩ ⋃ J ∖ cls ⁡ J ⁡ x
22 disjdif ⊢ cls ⁡ J ⁡ x ∩ ⋃ J ∖ cls ⁡ J ⁡ x = ∅
23 sseq0 ⊢ x ∩ ⋃ J ∖ cls ⁡ J ⁡ x ⊆ cls ⁡ J ⁡ x ∩ ⋃ J ∖ cls ⁡ J ⁡ x ∧ cls ⁡ J ⁡ x ∩ ⋃ J ∖ cls ⁡ J ⁡ x = ∅ → x ∩ ⋃ J ∖ cls ⁡ J ⁡ x = ∅
24 21 22 23 sylancl ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → x ∩ ⋃ J ∖ cls ⁡ J ⁡ x = ∅
25 sseq2 ⊢ y = ⋃ J ∖ cls ⁡ J ⁡ x → D ⊆ y ↔ D ⊆ ⋃ J ∖ cls ⁡ J ⁡ x
26 ineq2 ⊢ y = ⋃ J ∖ cls ⁡ J ⁡ x → x ∩ y = x ∩ ⋃ J ∖ cls ⁡ J ⁡ x
27 26 eqeq1d ⊢ y = ⋃ J ∖ cls ⁡ J ⁡ x → x ∩ y = ∅ ↔ x ∩ ⋃ J ∖ cls ⁡ J ⁡ x = ∅
28 25 27 3anbi23d ⊢ y = ⋃ J ∖ cls ⁡ J ⁡ x → C ⊆ x ∧ D ⊆ y ∧ x ∩ y = ∅ ↔ C ⊆ x ∧ D ⊆ ⋃ J ∖ cls ⁡ J ⁡ x ∧ x ∩ ⋃ J ∖ cls ⁡ J ⁡ x = ∅
29 28 rspcev ⊢ ⋃ J ∖ cls ⁡ J ⁡ x ∈ J ∧ C ⊆ x ∧ D ⊆ ⋃ J ∖ cls ⁡ J ⁡ x ∧ x ∩ ⋃ J ∖ cls ⁡ J ⁡ x = ∅ → ∃ y ∈ J C ⊆ x ∧ D ⊆ y ∧ x ∩ y = ∅
30 9 10 18 24 29 syl13anc ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ ∧ x ∈ J ∧ C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅ → ∃ y ∈ J C ⊆ x ∧ D ⊆ y ∧ x ∩ y = ∅
31 nrmsep2 ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ → ∃ x ∈ J C ⊆ x ∧ cls ⁡ J ⁡ x ∩ D = ∅
32 30 31 reximddv ⊢ J ∈ Nrm ∧ C ∈ Clsd ⁡ J ∧ D ∈ Clsd ⁡ J ∧ C ∩ D = ∅ → ∃ x ∈ J ∃ y ∈ J C ⊆ x ∧ D ⊆ y ∧ x ∩ y = ∅