Metamath Proof Explorer


Theorem ofresid

Description: Applying an operation restricted to the range of the functions does not change the function operation. (Contributed by Thierry Arnoux, 14-Feb-2018)

Ref Expression
Hypotheses ofresid.1 ⊢ φ → F : A ⟶ B
ofresid.2 ⊢ φ → G : A ⟶ B
ofresid.3 ⊢ φ → A ∈ V
Assertion ofresid ⊢ φ → F R f G = F R ↾ B × B f G

Proof

Step Hyp Ref Expression
1 ofresid.1 ⊢ φ → F : A ⟶ B
2 ofresid.2 ⊢ φ → G : A ⟶ B
3 ofresid.3 ⊢ φ → A ∈ V
4 1 ffvelcdmda ⊢ φ ∧ x ∈ A → F ⁡ x ∈ B
5 2 ffvelcdmda ⊢ φ ∧ x ∈ A → G ⁡ x ∈ B
6 4 5 opelxpd ⊢ φ ∧ x ∈ A → F ⁡ x G ⁡ x ∈ B × B
7 6 fvresd ⊢ φ ∧ x ∈ A → R ↾ B × B ⁡ F ⁡ x G ⁡ x = R ⁡ F ⁡ x G ⁡ x
8 7 eqcomd ⊢ φ ∧ x ∈ A → R ⁡ F ⁡ x G ⁡ x = R ↾ B × B ⁡ F ⁡ x G ⁡ x
9 df-ov ⊢ F ⁡ x R G ⁡ x = R ⁡ F ⁡ x G ⁡ x
10 df-ov ⊢ F ⁡ x R ↾ B × B G ⁡ x = R ↾ B × B ⁡ F ⁡ x G ⁡ x
11 8 9 10 3eqtr4g ⊢ φ ∧ x ∈ A → F ⁡ x R G ⁡ x = F ⁡ x R ↾ B × B G ⁡ x
12 11 mpteq2dva ⊢ φ → x ∈ A ⟼ F ⁡ x R G ⁡ x = x ∈ A ⟼ F ⁡ x R ↾ B × B G ⁡ x
13 1 ffnd ⊢ φ → F Fn A
14 2 ffnd ⊢ φ → G Fn A
15 inidm ⊢ A ∩ A = A
16 eqidd ⊢ φ ∧ x ∈ A → F ⁡ x = F ⁡ x
17 eqidd ⊢ φ ∧ x ∈ A → G ⁡ x = G ⁡ x
18 13 14 3 3 15 16 17 offval ⊢ φ → F R f G = x ∈ A ⟼ F ⁡ x R G ⁡ x
19 13 14 3 3 15 16 17 offval ⊢ φ → F R ↾ B × B f G = x ∈ A ⟼ F ⁡ x R ↾ B × B G ⁡ x
20 12 18 19 3eqtr4d ⊢ φ → F R f G = F R ↾ B × B f G