Metamath Proof Explorer


Theorem pgnbgreunbgrlem2

Description: Lemma 2 for pgnbgreunbgr . Impossible cases. (Contributed by AV, 18-Nov-2025)

Ref Expression
Hypotheses pgnbgreunbgr.g No typesetting found for |- G = ( 5 gPetersenGr 2 ) with typecode |-
pgnbgreunbgr.v ⊢ V = Vtx ⁡ G
pgnbgreunbgr.e ⊢ E = Edg ⁡ G
pgnbgreunbgr.n ⊢ N = G NeighbVtx X
Assertion pgnbgreunbgrlem2 ⊢ L = 1 2 nd ⁡ X + 2 mod 5 ∨ L = 0 2 nd ⁡ X ∨ L = 1 2 nd ⁡ X − 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 ∨ K = 0 2 nd ⁡ X ∨ K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b

Proof

Step Hyp Ref Expression
1 pgnbgreunbgr.g Could not format G = ( 5 gPetersenGr 2 ) : No typesetting found for |- G = ( 5 gPetersenGr 2 ) with typecode |-
2 pgnbgreunbgr.v ⊢ V = Vtx ⁡ G
3 pgnbgreunbgr.e ⊢ E = Edg ⁡ G
4 pgnbgreunbgr.n ⊢ N = G NeighbVtx X
5 eqtr3 ⊢ L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 1 2 nd ⁡ X + 2 mod 5 → L = K
6 eqneqall ⊢ K = L → K ≠ L → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
7 6 impd ⊢ K = L → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
8 7 eqcoms ⊢ L = K → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
9 5 8 syl ⊢ L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 1 2 nd ⁡ X + 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
10 9 a1d ⊢ L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 1 2 nd ⁡ X + 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
11 10 ex ⊢ L = 1 2 nd ⁡ X + 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
12 1ex ⊢ 1 ∈ V
13 vex ⊢ y ∈ V
14 12 13 op2ndd ⊢ X = 1 y → 2 nd ⁡ X = y
15 oveq1 ⊢ 2 nd ⁡ X = y → 2 nd ⁡ X + 2 = y + 2
16 15 oveq1d ⊢ 2 nd ⁡ X = y → 2 nd ⁡ X + 2 mod 5 = y + 2 mod 5
17 16 opeq2d ⊢ 2 nd ⁡ X = y → 1 2 nd ⁡ X + 2 mod 5 = 1 y + 2 mod 5
18 17 eqeq2d ⊢ 2 nd ⁡ X = y → L = 1 2 nd ⁡ X + 2 mod 5 ↔ L = 1 y + 2 mod 5
19 opeq2 ⊢ 2 nd ⁡ X = y → 0 2 nd ⁡ X = 0 y
20 19 eqeq2d ⊢ 2 nd ⁡ X = y → K = 0 2 nd ⁡ X ↔ K = 0 y
21 18 20 anbi12d ⊢ 2 nd ⁡ X = y → L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 0 2 nd ⁡ X ↔ L = 1 y + 2 mod 5 ∧ K = 0 y
22 14 21 syl ⊢ X = 1 y → L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 0 2 nd ⁡ X ↔ L = 1 y + 2 mod 5 ∧ K = 0 y
23 1 2 3 4 pgnbgreunbgrlem2lem1 ⊢ L = 1 y + 2 mod 5 ∧ K = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ K 0 b ∈ E → ¬ 0 b L ∈ E
24 23 pm2.21d ⊢ L = 1 y + 2 mod 5 ∧ K = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ K 0 b ∈ E → 0 b L ∈ E → X = 0 b
25 24 expimpd ⊢ L = 1 y + 2 mod 5 ∧ K = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
26 25 ex ⊢ L = 1 y + 2 mod 5 ∧ K = 0 y → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
27 26 adantld ⊢ L = 1 y + 2 mod 5 ∧ K = 0 y → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
28 22 27 biimtrdi ⊢ X = 1 y → L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 0 2 nd ⁡ X → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
29 28 adantr ⊢ X = 1 y ∧ X ∈ V → L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 0 2 nd ⁡ X → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
30 29 expdcom ⊢ L = 1 2 nd ⁡ X + 2 mod 5 → K = 0 2 nd ⁡ X → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
31 oveq1 ⊢ 2 nd ⁡ X = y → 2 nd ⁡ X − 2 = y − 2
32 31 oveq1d ⊢ 2 nd ⁡ X = y → 2 nd ⁡ X − 2 mod 5 = y − 2 mod 5
33 32 opeq2d ⊢ 2 nd ⁡ X = y → 1 2 nd ⁡ X − 2 mod 5 = 1 y − 2 mod 5
34 33 eqeq2d ⊢ 2 nd ⁡ X = y → K = 1 2 nd ⁡ X − 2 mod 5 ↔ K = 1 y − 2 mod 5
35 18 34 anbi12d ⊢ 2 nd ⁡ X = y → L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 1 2 nd ⁡ X − 2 mod 5 ↔ L = 1 y + 2 mod 5 ∧ K = 1 y − 2 mod 5
36 14 35 syl ⊢ X = 1 y → L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 1 2 nd ⁡ X − 2 mod 5 ↔ L = 1 y + 2 mod 5 ∧ K = 1 y − 2 mod 5
37 1 2 3 4 pgnbgreunbgrlem2lem3 ⊢ L = 1 y + 2 mod 5 ∧ K = 1 y − 2 mod 5 ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ K 0 b ∈ E → ¬ 0 b L ∈ E
38 37 pm2.21d ⊢ L = 1 y + 2 mod 5 ∧ K = 1 y − 2 mod 5 ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ K 0 b ∈ E → 0 b L ∈ E → X = 0 b
39 38 expimpd ⊢ L = 1 y + 2 mod 5 ∧ K = 1 y − 2 mod 5 ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
40 39 ex ⊢ L = 1 y + 2 mod 5 ∧ K = 1 y − 2 mod 5 → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
41 40 adantld ⊢ L = 1 y + 2 mod 5 ∧ K = 1 y − 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
42 36 41 biimtrdi ⊢ X = 1 y → L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 1 2 nd ⁡ X − 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
43 42 adantr ⊢ X = 1 y ∧ X ∈ V → L = 1 2 nd ⁡ X + 2 mod 5 ∧ K = 1 2 nd ⁡ X − 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
44 43 expdcom ⊢ L = 1 2 nd ⁡ X + 2 mod 5 → K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
45 11 30 44 3jaod ⊢ L = 1 2 nd ⁡ X + 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 ∨ K = 0 2 nd ⁡ X ∨ K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
46 14 adantr ⊢ X = 1 y ∧ X ∈ V → 2 nd ⁡ X = y
47 19 eqeq2d ⊢ 2 nd ⁡ X = y → L = 0 2 nd ⁡ X ↔ L = 0 y
48 17 eqeq2d ⊢ 2 nd ⁡ X = y → K = 1 2 nd ⁡ X + 2 mod 5 ↔ K = 1 y + 2 mod 5
49 47 48 anbi12d ⊢ 2 nd ⁡ X = y → L = 0 2 nd ⁡ X ∧ K = 1 2 nd ⁡ X + 2 mod 5 ↔ L = 0 y ∧ K = 1 y + 2 mod 5
50 46 49 syl ⊢ X = 1 y ∧ X ∈ V → L = 0 2 nd ⁡ X ∧ K = 1 2 nd ⁡ X + 2 mod 5 ↔ L = 0 y ∧ K = 1 y + 2 mod 5
51 prcom ⊢ 0 b L = L 0 b
52 51 eleq1i ⊢ 0 b L ∈ E ↔ L 0 b ∈ E
53 1 2 3 4 pgnbgreunbgrlem2lem1 ⊢ K = 1 y + 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ L 0 b ∈ E → ¬ 0 b K ∈ E
54 prcom ⊢ K 0 b = 0 b K
55 54 eleq1i ⊢ K 0 b ∈ E ↔ 0 b K ∈ E
56 pm2.21 ⊢ ¬ 0 b K ∈ E → 0 b K ∈ E → X = 0 b
57 55 56 biimtrid ⊢ ¬ 0 b K ∈ E → K 0 b ∈ E → X = 0 b
58 53 57 syl ⊢ K = 1 y + 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ L 0 b ∈ E → K 0 b ∈ E → X = 0 b
59 58 ex ⊢ K = 1 y + 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → L 0 b ∈ E → K 0 b ∈ E → X = 0 b
60 52 59 biimtrid ⊢ K = 1 y + 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → 0 b L ∈ E → K 0 b ∈ E → X = 0 b
61 60 impcomd ⊢ K = 1 y + 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
62 61 ex ⊢ K = 1 y + 2 mod 5 ∧ L = 0 y → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
63 62 ancoms ⊢ L = 0 y ∧ K = 1 y + 2 mod 5 → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
64 63 adantld ⊢ L = 0 y ∧ K = 1 y + 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
65 50 64 biimtrdi ⊢ X = 1 y ∧ X ∈ V → L = 0 2 nd ⁡ X ∧ K = 1 2 nd ⁡ X + 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
66 65 expdcom ⊢ L = 0 2 nd ⁡ X → K = 1 2 nd ⁡ X + 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
67 eqtr3 ⊢ K = 0 2 nd ⁡ X ∧ L = 0 2 nd ⁡ X → K = L
68 67 ancoms ⊢ L = 0 2 nd ⁡ X ∧ K = 0 2 nd ⁡ X → K = L
69 68 6 syl ⊢ L = 0 2 nd ⁡ X ∧ K = 0 2 nd ⁡ X → K ≠ L → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
70 69 impd ⊢ L = 0 2 nd ⁡ X ∧ K = 0 2 nd ⁡ X → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
71 70 a1d ⊢ L = 0 2 nd ⁡ X ∧ K = 0 2 nd ⁡ X → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
72 71 ex ⊢ L = 0 2 nd ⁡ X → K = 0 2 nd ⁡ X → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
73 47 34 anbi12d ⊢ 2 nd ⁡ X = y → L = 0 2 nd ⁡ X ∧ K = 1 2 nd ⁡ X − 2 mod 5 ↔ L = 0 y ∧ K = 1 y − 2 mod 5
74 46 73 syl ⊢ X = 1 y ∧ X ∈ V → L = 0 2 nd ⁡ X ∧ K = 1 2 nd ⁡ X − 2 mod 5 ↔ L = 0 y ∧ K = 1 y − 2 mod 5
75 1 2 3 4 pgnbgreunbgrlem2lem2 ⊢ K = 1 y − 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ L 0 b ∈ E → ¬ 0 b K ∈ E
76 75 57 syl ⊢ K = 1 y − 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ L 0 b ∈ E → K 0 b ∈ E → X = 0 b
77 76 ex ⊢ K = 1 y − 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → L 0 b ∈ E → K 0 b ∈ E → X = 0 b
78 52 77 biimtrid ⊢ K = 1 y − 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → 0 b L ∈ E → K 0 b ∈ E → X = 0 b
79 78 impcomd ⊢ K = 1 y − 2 mod 5 ∧ L = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
80 79 ex ⊢ K = 1 y − 2 mod 5 ∧ L = 0 y → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
81 80 ancoms ⊢ L = 0 y ∧ K = 1 y − 2 mod 5 → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
82 81 adantld ⊢ L = 0 y ∧ K = 1 y − 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
83 74 82 biimtrdi ⊢ X = 1 y ∧ X ∈ V → L = 0 2 nd ⁡ X ∧ K = 1 2 nd ⁡ X − 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
84 83 expdcom ⊢ L = 0 2 nd ⁡ X → K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
85 66 72 84 3jaod ⊢ L = 0 2 nd ⁡ X → K = 1 2 nd ⁡ X + 2 mod 5 ∨ K = 0 2 nd ⁡ X ∨ K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
86 33 eqeq2d ⊢ 2 nd ⁡ X = y → L = 1 2 nd ⁡ X − 2 mod 5 ↔ L = 1 y − 2 mod 5
87 86 48 anbi12d ⊢ 2 nd ⁡ X = y → L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 1 2 nd ⁡ X + 2 mod 5 ↔ L = 1 y − 2 mod 5 ∧ K = 1 y + 2 mod 5
88 46 87 syl ⊢ X = 1 y ∧ X ∈ V → L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 1 2 nd ⁡ X + 2 mod 5 ↔ L = 1 y − 2 mod 5 ∧ K = 1 y + 2 mod 5
89 1 2 3 4 pgnbgreunbgrlem2lem3 ⊢ K = 1 y + 2 mod 5 ∧ L = 1 y − 2 mod 5 ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ L 0 b ∈ E → ¬ 0 b K ∈ E
90 89 57 syl ⊢ K = 1 y + 2 mod 5 ∧ L = 1 y − 2 mod 5 ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ L 0 b ∈ E → K 0 b ∈ E → X = 0 b
91 90 ex ⊢ K = 1 y + 2 mod 5 ∧ L = 1 y − 2 mod 5 ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → L 0 b ∈ E → K 0 b ∈ E → X = 0 b
92 52 91 biimtrid ⊢ K = 1 y + 2 mod 5 ∧ L = 1 y − 2 mod 5 ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → 0 b L ∈ E → K 0 b ∈ E → X = 0 b
93 92 impcomd ⊢ K = 1 y + 2 mod 5 ∧ L = 1 y − 2 mod 5 ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
94 93 ex ⊢ K = 1 y + 2 mod 5 ∧ L = 1 y − 2 mod 5 → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
95 94 ancoms ⊢ L = 1 y − 2 mod 5 ∧ K = 1 y + 2 mod 5 → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
96 95 adantld ⊢ L = 1 y − 2 mod 5 ∧ K = 1 y + 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
97 88 96 biimtrdi ⊢ X = 1 y ∧ X ∈ V → L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 1 2 nd ⁡ X + 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
98 97 expdcom ⊢ L = 1 2 nd ⁡ X − 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
99 86 20 anbi12d ⊢ 2 nd ⁡ X = y → L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 0 2 nd ⁡ X ↔ L = 1 y − 2 mod 5 ∧ K = 0 y
100 46 99 syl ⊢ X = 1 y ∧ X ∈ V → L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 0 2 nd ⁡ X ↔ L = 1 y − 2 mod 5 ∧ K = 0 y
101 1 2 3 4 pgnbgreunbgrlem2lem2 ⊢ L = 1 y − 2 mod 5 ∧ K = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ K 0 b ∈ E → ¬ 0 b L ∈ E
102 101 pm2.21d ⊢ L = 1 y − 2 mod 5 ∧ K = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 ∧ K 0 b ∈ E → 0 b L ∈ E → X = 0 b
103 102 expimpd ⊢ L = 1 y − 2 mod 5 ∧ K = 0 y ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
104 103 ex ⊢ L = 1 y − 2 mod 5 ∧ K = 0 y → b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
105 104 adantld ⊢ L = 1 y − 2 mod 5 ∧ K = 0 y → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
106 100 105 biimtrdi ⊢ X = 1 y ∧ X ∈ V → L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 0 2 nd ⁡ X → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
107 106 expdcom ⊢ L = 1 2 nd ⁡ X − 2 mod 5 → K = 0 2 nd ⁡ X → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
108 eqtr3 ⊢ L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 1 2 nd ⁡ X − 2 mod 5 → L = K
109 108 eqcomd ⊢ L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 1 2 nd ⁡ X − 2 mod 5 → K = L
110 109 7 syl ⊢ L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 1 2 nd ⁡ X − 2 mod 5 → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
111 110 a1d ⊢ L = 1 2 nd ⁡ X − 2 mod 5 ∧ K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
112 111 ex ⊢ L = 1 2 nd ⁡ X − 2 mod 5 → K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
113 98 107 112 3jaod ⊢ L = 1 2 nd ⁡ X − 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 ∨ K = 0 2 nd ⁡ X ∨ K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b
114 45 85 113 3jaoi ⊢ L = 1 2 nd ⁡ X + 2 mod 5 ∨ L = 0 2 nd ⁡ X ∨ L = 1 2 nd ⁡ X − 2 mod 5 → K = 1 2 nd ⁡ X + 2 mod 5 ∨ K = 0 2 nd ⁡ X ∨ K = 1 2 nd ⁡ X − 2 mod 5 → X = 1 y ∧ X ∈ V → K ≠ L ∧ b ∈ 0 ..^ 5 ∧ y ∈ 0 ..^ 5 → K 0 b ∈ E ∧ 0 b L ∈ E → X = 0 b