Metamath Proof Explorer


Theorem pj1rid

Description: The left projection function is the zero operator on the right subspace. (Contributed by Mario Carneiro, 15-Oct-2015)

Ref Expression
Hypotheses pj1eu.a ⊢ + ˙ = + G
pj1eu.s ⊢ ⊕ ˙ = LSSum ⁡ G
pj1eu.o ⊢ 0 ˙ = 0 G
pj1eu.z ⊢ Z = Cntz ⁡ G
pj1eu.2 ⊢ φ → T ∈ SubGrp ⁡ G
pj1eu.3 ⊢ φ → U ∈ SubGrp ⁡ G
pj1eu.4 ⊢ φ → T ∩ U = 0 ˙
pj1eu.5 ⊢ φ → T ⊆ Z ⁡ U
pj1f.p ⊢ P = proj 1 ⁡ G
Assertion pj1rid ⊢ φ ∧ X ∈ U → T P U ⁡ X = 0 ˙

Proof

Step Hyp Ref Expression
1 pj1eu.a ⊢ + ˙ = + G
2 pj1eu.s ⊢ ⊕ ˙ = LSSum ⁡ G
3 pj1eu.o ⊢ 0 ˙ = 0 G
4 pj1eu.z ⊢ Z = Cntz ⁡ G
5 pj1eu.2 ⊢ φ → T ∈ SubGrp ⁡ G
6 pj1eu.3 ⊢ φ → U ∈ SubGrp ⁡ G
7 pj1eu.4 ⊢ φ → T ∩ U = 0 ˙
8 pj1eu.5 ⊢ φ → T ⊆ Z ⁡ U
9 pj1f.p ⊢ P = proj 1 ⁡ G
10 5 adantr ⊢ φ ∧ X ∈ U → T ∈ SubGrp ⁡ G
11 subgrcl ⊢ T ∈ SubGrp ⁡ G → G ∈ Grp
12 10 11 syl ⊢ φ ∧ X ∈ U → G ∈ Grp
13 eqid ⊢ Base G = Base G
14 13 subgss ⊢ U ∈ SubGrp ⁡ G → U ⊆ Base G
15 6 14 syl ⊢ φ → U ⊆ Base G
16 15 sselda ⊢ φ ∧ X ∈ U → X ∈ Base G
17 13 1 3 grplid ⊢ G ∈ Grp ∧ X ∈ Base G → 0 ˙ + ˙ X = X
18 12 16 17 syl2anc ⊢ φ ∧ X ∈ U → 0 ˙ + ˙ X = X
19 18 eqcomd ⊢ φ ∧ X ∈ U → X = 0 ˙ + ˙ X
20 6 adantr ⊢ φ ∧ X ∈ U → U ∈ SubGrp ⁡ G
21 7 adantr ⊢ φ ∧ X ∈ U → T ∩ U = 0 ˙
22 8 adantr ⊢ φ ∧ X ∈ U → T ⊆ Z ⁡ U
23 2 lsmub2 ⊢ T ∈ SubGrp ⁡ G ∧ U ∈ SubGrp ⁡ G → U ⊆ T ⊕ ˙ U
24 5 6 23 syl2anc ⊢ φ → U ⊆ T ⊕ ˙ U
25 24 sselda ⊢ φ ∧ X ∈ U → X ∈ T ⊕ ˙ U
26 3 subg0cl ⊢ T ∈ SubGrp ⁡ G → 0 ˙ ∈ T
27 10 26 syl ⊢ φ ∧ X ∈ U → 0 ˙ ∈ T
28 simpr ⊢ φ ∧ X ∈ U → X ∈ U
29 1 2 3 4 10 20 21 22 9 25 27 28 pj1eq ⊢ φ ∧ X ∈ U → X = 0 ˙ + ˙ X ↔ T P U ⁡ X = 0 ˙ ∧ U P T ⁡ X = X
30 19 29 mpbid ⊢ φ ∧ X ∈ U → T P U ⁡ X = 0 ˙ ∧ U P T ⁡ X = X
31 30 simpld ⊢ φ ∧ X ∈ U → T P U ⁡ X = 0 ˙