Metamath Proof Explorer


Theorem pzriprngALT

Description: The non-unital ring ( ZZring Xs. ZZring ) is unital because it has the two-sided ideal ( ZZ X. { 0 } ) , which is unital, and the quotient of the ring and the ideal is also unital (using ring2idlqusb ). (Contributed by AV, 23-Mar-2025) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion pzriprngALT ⊢ ℤ ring × 𝑠 ℤ ring ∈ Ring

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ i = ℤ × 0 → ℤ ring × 𝑠 ℤ ring ↾ 𝑠 i = ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0
2 1 eleq1d ⊢ i = ℤ × 0 → ℤ ring × 𝑠 ℤ ring ↾ 𝑠 i ∈ Ring ↔ ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0 ∈ Ring
3 oveq2 ⊢ i = ℤ × 0 → ℤ ring × 𝑠 ℤ ring ~ QG i = ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0
4 3 oveq2d ⊢ i = ℤ × 0 → ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG i = ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0
5 4 eleq1d ⊢ i = ℤ × 0 → ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG i ∈ Ring ↔ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0 ∈ Ring
6 2 5 anbi12d ⊢ i = ℤ × 0 → ℤ ring × 𝑠 ℤ ring ↾ 𝑠 i ∈ Ring ∧ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG i ∈ Ring ↔ ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0 ∈ Ring ∧ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0 ∈ Ring
7 eqid ⊢ ℤ ring × 𝑠 ℤ ring = ℤ ring × 𝑠 ℤ ring
8 eqid ⊢ ℤ × 0 = ℤ × 0
9 eqid ⊢ ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0 = ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0
10 7 8 9 pzriprnglem8 ⊢ ℤ × 0 ∈ 2Ideal ⁡ ℤ ring × 𝑠 ℤ ring
11 10 a1i ⊢ ⊤ → ℤ × 0 ∈ 2Ideal ⁡ ℤ ring × 𝑠 ℤ ring
12 7 8 9 pzriprnglem7 ⊢ ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0 ∈ Ring
13 12 a1i ⊢ ⊤ → ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0 ∈ Ring
14 eqid ⊢ 1 ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0 = 1 ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0
15 eqid ⊢ ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0 = ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0
16 eqid ⊢ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0 = ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0
17 7 8 9 14 15 16 pzriprnglem13 ⊢ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0 ∈ Ring
18 13 17 jctir ⊢ ⊤ → ℤ ring × 𝑠 ℤ ring ↾ 𝑠 ℤ × 0 ∈ Ring ∧ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG ℤ × 0 ∈ Ring
19 6 11 18 rspcedvdw ⊢ ⊤ → ∃ i ∈ 2Ideal ⁡ ℤ ring × 𝑠 ℤ ring ℤ ring × 𝑠 ℤ ring ↾ 𝑠 i ∈ Ring ∧ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG i ∈ Ring
20 19 mptru ⊢ ∃ i ∈ 2Ideal ⁡ ℤ ring × 𝑠 ℤ ring ℤ ring × 𝑠 ℤ ring ↾ 𝑠 i ∈ Ring ∧ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG i ∈ Ring
21 7 pzriprnglem1 ⊢ ℤ ring × 𝑠 ℤ ring ∈ Rng
22 ring2idlqusb ⊢ ℤ ring × 𝑠 ℤ ring ∈ Rng → ℤ ring × 𝑠 ℤ ring ∈ Ring ↔ ∃ i ∈ 2Ideal ⁡ ℤ ring × 𝑠 ℤ ring ℤ ring × 𝑠 ℤ ring ↾ 𝑠 i ∈ Ring ∧ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG i ∈ Ring
23 21 22 ax-mp ⊢ ℤ ring × 𝑠 ℤ ring ∈ Ring ↔ ∃ i ∈ 2Ideal ⁡ ℤ ring × 𝑠 ℤ ring ℤ ring × 𝑠 ℤ ring ↾ 𝑠 i ∈ Ring ∧ ℤ ring × 𝑠 ℤ ring / 𝑠 ℤ ring × 𝑠 ℤ ring ~ QG i ∈ Ring
24 20 23 mpbir ⊢ ℤ ring × 𝑠 ℤ ring ∈ Ring