Metamath Proof Explorer


Theorem qcvs

Description: The field of rational numbers as left module over itself is a subcomplex vector space. The vector operation is + , and the scalar product is x. . (Contributed by AV, 22-Oct-2021)

Ref Expression
Hypothesis qcvs.q ⊢ Q = ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ
Assertion qcvs ⊢ Q ∈ ℂVec

Proof

Step Hyp Ref Expression
1 qcvs.q ⊢ Q = ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ
2 qsubdrg ⊢ ℚ ∈ SubRing ⁡ ℂ fld ∧ ℂ fld ↾ 𝑠 ℚ ∈ DivRing
3 drngring ⊢ ℂ fld ↾ 𝑠 ℚ ∈ DivRing → ℂ fld ↾ 𝑠 ℚ ∈ Ring
4 3 adantl ⊢ ℚ ∈ SubRing ⁡ ℂ fld ∧ ℂ fld ↾ 𝑠 ℚ ∈ DivRing → ℂ fld ↾ 𝑠 ℚ ∈ Ring
5 2 4 ax-mp ⊢ ℂ fld ↾ 𝑠 ℚ ∈ Ring
6 rlmlmod ⊢ ℂ fld ↾ 𝑠 ℚ ∈ Ring → ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ ∈ LMod
7 5 6 ax-mp ⊢ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ ∈ LMod
8 2 simpri ⊢ ℂ fld ↾ 𝑠 ℚ ∈ DivRing
9 rlmsca ⊢ ℂ fld ↾ 𝑠 ℚ ∈ DivRing → ℂ fld ↾ 𝑠 ℚ = Scalar ⁡ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ
10 9 eqcomd ⊢ ℂ fld ↾ 𝑠 ℚ ∈ DivRing → Scalar ⁡ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ = ℂ fld ↾ 𝑠 ℚ
11 8 10 ax-mp ⊢ Scalar ⁡ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ = ℂ fld ↾ 𝑠 ℚ
12 2 simpli ⊢ ℚ ∈ SubRing ⁡ ℂ fld
13 eqid ⊢ Scalar ⁡ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ = Scalar ⁡ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ
14 13 isclmi ⊢ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ ∈ LMod ∧ Scalar ⁡ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ = ℂ fld ↾ 𝑠 ℚ ∧ ℚ ∈ SubRing ⁡ ℂ fld → ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ ∈ CMod
15 7 11 12 14 mp3an ⊢ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ ∈ CMod
16 rlmlvec ⊢ ℂ fld ↾ 𝑠 ℚ ∈ DivRing → ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ ∈ LVec
17 8 16 ax-mp ⊢ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ ∈ LVec
18 15 17 elini ⊢ ringLMod ⁡ ℂ fld ↾ 𝑠 ℚ ∈ CMod ∩ LVec
19 df-cvs ⊢ ℂVec = CMod ∩ LVec
20 18 1 19 3eltr4i ⊢ Q ∈ ℂVec