Metamath Proof Explorer


Theorem recexpr

Description: The reciprocal of a positive real exists. Part of Proposition 9-3.7(v) of Gleason p. 124. (Contributed by NM, 15-May-1996) (Revised by Mario Carneiro, 12-Jun-2013) (New usage is discouraged.)

Ref Expression
Assertion recexpr ⊢ A ∈ 𝑷 → ∃ x ∈ 𝑷 A ⋅ 𝑷 x = 1 𝑷

Proof

Step Hyp Ref Expression
1 breq1 ⊢ z = w → z < 𝑸 y ↔ w < 𝑸 y
2 1 anbi1d ⊢ z = w → z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A ↔ w < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A
3 2 exbidv ⊢ z = w → ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A ↔ ∃ y w < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A
4 3 cbvabv ⊢ z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A = w | ∃ y w < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A
5 4 reclem2pr ⊢ A ∈ 𝑷 → z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A ∈ 𝑷
6 4 reclem4pr ⊢ A ∈ 𝑷 → A ⋅ 𝑷 z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A = 1 𝑷
7 oveq2 ⊢ x = z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A → A ⋅ 𝑷 x = A ⋅ 𝑷 z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A
8 7 eqeq1d ⊢ x = z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A → A ⋅ 𝑷 x = 1 𝑷 ↔ A ⋅ 𝑷 z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A = 1 𝑷
9 8 rspcev ⊢ z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A ∈ 𝑷 ∧ A ⋅ 𝑷 z | ∃ y z < 𝑸 y ∧ ¬ * 𝑸 ⁡ y ∈ A = 1 𝑷 → ∃ x ∈ 𝑷 A ⋅ 𝑷 x = 1 𝑷
10 5 6 9 syl2anc ⊢ A ∈ 𝑷 → ∃ x ∈ 𝑷 A ⋅ 𝑷 x = 1 𝑷