Metamath Proof Explorer


Theorem rrxmetlem

Description: Lemma for rrxmet . (Contributed by Thierry Arnoux, 5-Jul-2019)

Ref Expression
Hypotheses rrxmval.1 ⊢ X = h ∈ ℝ I | finSupp 0 ⁡ h
rrxmval.d ⊢ D = dist ⁡ I
rrxmetlem.1 ⊢ φ → I ∈ V
rrxmetlem.2 ⊢ φ → F ∈ X
rrxmetlem.3 ⊢ φ → G ∈ X
rrxmetlem.4 ⊢ φ → A ⊆ I
rrxmetlem.5 ⊢ φ → A ∈ Fin
rrxmetlem.6 ⊢ φ → supp 0 ⁡ F ∪ supp 0 ⁡ G ⊆ A
Assertion rrxmetlem ⊢ φ → ∑ k ∈ supp 0 ⁡ F ∪ supp 0 ⁡ G F ⁡ k − G ⁡ k 2 = ∑ k ∈ A F ⁡ k − G ⁡ k 2

Proof

Step Hyp Ref Expression
1 rrxmval.1 ⊢ X = h ∈ ℝ I | finSupp 0 ⁡ h
2 rrxmval.d ⊢ D = dist ⁡ I
3 rrxmetlem.1 ⊢ φ → I ∈ V
4 rrxmetlem.2 ⊢ φ → F ∈ X
5 rrxmetlem.3 ⊢ φ → G ∈ X
6 rrxmetlem.4 ⊢ φ → A ⊆ I
7 rrxmetlem.5 ⊢ φ → A ∈ Fin
8 rrxmetlem.6 ⊢ φ → supp 0 ⁡ F ∪ supp 0 ⁡ G ⊆ A
9 8 6 sstrd ⊢ φ → supp 0 ⁡ F ∪ supp 0 ⁡ G ⊆ I
10 9 sselda ⊢ φ ∧ k ∈ supp 0 ⁡ F ∪ supp 0 ⁡ G → k ∈ I
11 1 4 rrxf ⊢ φ → F : I ⟶ ℝ
12 11 ffvelcdmda ⊢ φ ∧ k ∈ I → F ⁡ k ∈ ℝ
13 12 recnd ⊢ φ ∧ k ∈ I → F ⁡ k ∈ ℂ
14 10 13 syldan ⊢ φ ∧ k ∈ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k ∈ ℂ
15 1 5 rrxf ⊢ φ → G : I ⟶ ℝ
16 15 ffvelcdmda ⊢ φ ∧ k ∈ I → G ⁡ k ∈ ℝ
17 16 recnd ⊢ φ ∧ k ∈ I → G ⁡ k ∈ ℂ
18 10 17 syldan ⊢ φ ∧ k ∈ supp 0 ⁡ F ∪ supp 0 ⁡ G → G ⁡ k ∈ ℂ
19 14 18 subcld ⊢ φ ∧ k ∈ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k − G ⁡ k ∈ ℂ
20 19 sqcld ⊢ φ ∧ k ∈ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k − G ⁡ k 2 ∈ ℂ
21 6 ssdifd ⊢ φ → A ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G ⊆ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G
22 21 sselda ⊢ φ ∧ k ∈ A ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G
23 simpr ⊢ φ ∧ k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G
24 23 eldifad ⊢ φ ∧ k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → k ∈ I
25 24 13 syldan ⊢ φ ∧ k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k ∈ ℂ
26 ssun1 ⊢ F supp 0 ⊆ supp 0 ⁡ F ∪ supp 0 ⁡ G
27 26 a1i ⊢ φ → F supp 0 ⊆ supp 0 ⁡ F ∪ supp 0 ⁡ G
28 0red ⊢ φ → 0 ∈ ℝ
29 11 27 3 28 suppssr ⊢ φ ∧ k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k = 0
30 ssun2 ⊢ G supp 0 ⊆ supp 0 ⁡ F ∪ supp 0 ⁡ G
31 30 a1i ⊢ φ → G supp 0 ⊆ supp 0 ⁡ F ∪ supp 0 ⁡ G
32 15 31 3 28 suppssr ⊢ φ ∧ k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → G ⁡ k = 0
33 29 32 eqtr4d ⊢ φ ∧ k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k = G ⁡ k
34 25 33 subeq0bd ⊢ φ ∧ k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k − G ⁡ k = 0
35 34 sq0id ⊢ φ ∧ k ∈ I ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k − G ⁡ k 2 = 0
36 22 35 syldan ⊢ φ ∧ k ∈ A ∖ supp 0 ⁡ F ∪ supp 0 ⁡ G → F ⁡ k − G ⁡ k 2 = 0
37 8 20 36 7 fsumss ⊢ φ → ∑ k ∈ supp 0 ⁡ F ∪ supp 0 ⁡ G F ⁡ k − G ⁡ k 2 = ∑ k ∈ A F ⁡ k − G ⁡ k 2