Metamath Proof Explorer


Theorem seposep

Description: If two sets are separated by (open) neighborhoods, then they are separated subsets of the underlying set. Note that separatedness by open neighborhoods is equivalent to separatedness by neighborhoods. See sepnsepo . The relationship between separatedness and closure is also seen in isnrm , isnrm2 , isnrm3 . (Contributed by Zhi Wang, 7-Sep-2024)

Ref Expression
Hypotheses sepdisj.1 ⊢ φ → J ∈ Top
seposep.2 ⊢ φ → ∃ n ∈ J ∃ m ∈ J S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅
Assertion seposep ⊢ φ → S ⊆ ⋃ J ∧ T ⊆ ⋃ J ∧ S ∩ cls ⁡ J ⁡ T = ∅ ∧ cls ⁡ J ⁡ S ∩ T = ∅

Proof

Step Hyp Ref Expression
1 sepdisj.1 ⊢ φ → J ∈ Top
2 seposep.2 ⊢ φ → ∃ n ∈ J ∃ m ∈ J S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅
3 simp31 ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ⊆ n
4 simp1 ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → J ∈ Top
5 simp2l ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → n ∈ J
6 eqid ⊢ ⋃ J = ⋃ J
7 6 eltopss ⊢ J ∈ Top ∧ n ∈ J → n ⊆ ⋃ J
8 4 5 7 syl2anc ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → n ⊆ ⋃ J
9 3 8 sstrd ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ⊆ ⋃ J
10 simp32 ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → T ⊆ m
11 simp2r ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → m ∈ J
12 6 eltopss ⊢ J ∈ Top ∧ m ∈ J → m ⊆ ⋃ J
13 4 11 12 syl2anc ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → m ⊆ ⋃ J
14 10 13 sstrd ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → T ⊆ ⋃ J
15 6 opncld ⊢ J ∈ Top ∧ n ∈ J → ⋃ J ∖ n ∈ Clsd ⁡ J
16 4 5 15 syl2anc ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → ⋃ J ∖ n ∈ Clsd ⁡ J
17 incom ⊢ n ∩ m = m ∩ n
18 simp33 ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → n ∩ m = ∅
19 17 18 eqtr3id ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → m ∩ n = ∅
20 reldisj ⊢ m ⊆ ⋃ J → m ∩ n = ∅ ↔ m ⊆ ⋃ J ∖ n
21 20 biimpd ⊢ m ⊆ ⋃ J → m ∩ n = ∅ → m ⊆ ⋃ J ∖ n
22 13 19 21 sylc ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → m ⊆ ⋃ J ∖ n
23 10 22 sstrd ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → T ⊆ ⋃ J ∖ n
24 6 clsss2 ⊢ ⋃ J ∖ n ∈ Clsd ⁡ J ∧ T ⊆ ⋃ J ∖ n → cls ⁡ J ⁡ T ⊆ ⋃ J ∖ n
25 16 23 24 syl2anc ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → cls ⁡ J ⁡ T ⊆ ⋃ J ∖ n
26 3 sscond ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → ⋃ J ∖ n ⊆ ⋃ J ∖ S
27 25 26 sstrd ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → cls ⁡ J ⁡ T ⊆ ⋃ J ∖ S
28 disjdif ⊢ S ∩ ⋃ J ∖ S = ∅
29 28 a1i ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ∩ ⋃ J ∖ S = ∅
30 27 29 ssdisjdr ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ∩ cls ⁡ J ⁡ T = ∅
31 6 opncld ⊢ J ∈ Top ∧ m ∈ J → ⋃ J ∖ m ∈ Clsd ⁡ J
32 4 11 31 syl2anc ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → ⋃ J ∖ m ∈ Clsd ⁡ J
33 reldisj ⊢ n ⊆ ⋃ J → n ∩ m = ∅ ↔ n ⊆ ⋃ J ∖ m
34 33 biimpd ⊢ n ⊆ ⋃ J → n ∩ m = ∅ → n ⊆ ⋃ J ∖ m
35 8 18 34 sylc ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → n ⊆ ⋃ J ∖ m
36 3 35 sstrd ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ⊆ ⋃ J ∖ m
37 6 clsss2 ⊢ ⋃ J ∖ m ∈ Clsd ⁡ J ∧ S ⊆ ⋃ J ∖ m → cls ⁡ J ⁡ S ⊆ ⋃ J ∖ m
38 32 36 37 syl2anc ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → cls ⁡ J ⁡ S ⊆ ⋃ J ∖ m
39 10 sscond ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → ⋃ J ∖ m ⊆ ⋃ J ∖ T
40 38 39 sstrd ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → cls ⁡ J ⁡ S ⊆ ⋃ J ∖ T
41 disjdifr ⊢ ⋃ J ∖ T ∩ T = ∅
42 41 a1i ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → ⋃ J ∖ T ∩ T = ∅
43 40 42 ssdisjd ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → cls ⁡ J ⁡ S ∩ T = ∅
44 30 43 jca ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ∩ cls ⁡ J ⁡ T = ∅ ∧ cls ⁡ J ⁡ S ∩ T = ∅
45 9 14 44 jca31 ⊢ J ∈ Top ∧ n ∈ J ∧ m ∈ J ∧ S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ⊆ ⋃ J ∧ T ⊆ ⋃ J ∧ S ∩ cls ⁡ J ⁡ T = ∅ ∧ cls ⁡ J ⁡ S ∩ T = ∅
46 45 3exp ⊢ J ∈ Top → n ∈ J ∧ m ∈ J → S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ⊆ ⋃ J ∧ T ⊆ ⋃ J ∧ S ∩ cls ⁡ J ⁡ T = ∅ ∧ cls ⁡ J ⁡ S ∩ T = ∅
47 46 rexlimdvv ⊢ J ∈ Top → ∃ n ∈ J ∃ m ∈ J S ⊆ n ∧ T ⊆ m ∧ n ∩ m = ∅ → S ⊆ ⋃ J ∧ T ⊆ ⋃ J ∧ S ∩ cls ⁡ J ⁡ T = ∅ ∧ cls ⁡ J ⁡ S ∩ T = ∅
48 1 2 47 sylc ⊢ φ → S ⊆ ⋃ J ∧ T ⊆ ⋃ J ∧ S ∩ cls ⁡ J ⁡ T = ∅ ∧ cls ⁡ J ⁡ S ∩ T = ∅