Metamath Proof Explorer


Theorem sin5tlem1

Description: Lemma 1 for quintupled angle sine calculation, expanding triple-angle sine times double-angle cosine. (Contributed by Ender Ting, 16-Mar-2026)

Ref Expression
Assertion sin5tlem1 ⊢ N ∈ ℂ → 3 ⋅ N − 4 ⁢ N 3 ⁢ 1 − 2 ⁢ N 2 = 8 ⁢ N 5 - 10 ⁢ N 3 + 3 ⋅ N

Proof

Step Hyp Ref Expression
1 3cn ⊢ 3 ∈ ℂ
2 1 a1i ⊢ N ∈ ℂ → 3 ∈ ℂ
3 id ⊢ N ∈ ℂ → N ∈ ℂ
4 2 3 mulcld ⊢ N ∈ ℂ → 3 ⋅ N ∈ ℂ
5 4cn ⊢ 4 ∈ ℂ
6 5 a1i ⊢ N ∈ ℂ → 4 ∈ ℂ
7 3nn0 ⊢ 3 ∈ ℕ 0
8 7 a1i ⊢ N ∈ ℂ → 3 ∈ ℕ 0
9 3 8 expcld ⊢ N ∈ ℂ → N 3 ∈ ℂ
10 6 9 mulcld ⊢ N ∈ ℂ → 4 ⁢ N 3 ∈ ℂ
11 1cnd ⊢ N ∈ ℂ → 1 ∈ ℂ
12 2cnd ⊢ N ∈ ℂ → 2 ∈ ℂ
13 sqcl ⊢ N ∈ ℂ → N 2 ∈ ℂ
14 12 13 mulcld ⊢ N ∈ ℂ → 2 ⁢ N 2 ∈ ℂ
15 4 10 11 14 mulsubd ⊢ N ∈ ℂ → 3 ⋅ N − 4 ⁢ N 3 ⁢ 1 − 2 ⁢ N 2 = 3 ⋅ N ⋅ 1 + 2 ⁢ N 2 ⁢ 4 ⁢ N 3 - 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3
16 4 11 mulcld ⊢ N ∈ ℂ → 3 ⋅ N ⋅ 1 ∈ ℂ
17 14 10 mulcld ⊢ N ∈ ℂ → 2 ⁢ N 2 ⁢ 4 ⁢ N 3 ∈ ℂ
18 16 17 addcomd ⊢ N ∈ ℂ → 3 ⋅ N ⋅ 1 + 2 ⁢ N 2 ⁢ 4 ⁢ N 3 = 2 ⁢ N 2 ⁢ 4 ⁢ N 3 + 3 ⋅ N ⋅ 1
19 18 oveq1d ⊢ N ∈ ℂ → 3 ⋅ N ⋅ 1 + 2 ⁢ N 2 ⁢ 4 ⁢ N 3 - 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 = 2 ⁢ N 2 ⁢ 4 ⁢ N 3 + 3 ⋅ N ⋅ 1 - 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3
20 4 14 mulcld ⊢ N ∈ ℂ → 3 ⋅ N ⁢ 2 ⁢ N 2 ∈ ℂ
21 11 10 mulcld ⊢ N ∈ ℂ → 1 ⁢ 4 ⁢ N 3 ∈ ℂ
22 20 21 addcld ⊢ N ∈ ℂ → 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 ∈ ℂ
23 17 16 22 addsubd ⊢ N ∈ ℂ → 2 ⁢ N 2 ⁢ 4 ⁢ N 3 + 3 ⋅ N ⋅ 1 - 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 = 2 ⁢ N 2 ⁢ 4 ⁢ N 3 - 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 + 3 ⋅ N ⋅ 1
24 19 23 eqtrd ⊢ N ∈ ℂ → 3 ⋅ N ⋅ 1 + 2 ⁢ N 2 ⁢ 4 ⁢ N 3 - 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 = 2 ⁢ N 2 ⁢ 4 ⁢ N 3 - 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 + 3 ⋅ N ⋅ 1
25 12 13 6 9 mul4d ⊢ N ∈ ℂ → 2 ⁢ N 2 ⁢ 4 ⁢ N 3 = 2 ⋅ 4 ⁢ N 2 ⁢ N 3
26 2t4e8 ⊢ 2 ⋅ 4 = 8
27 26 a1i ⊢ N ∈ ℂ → 2 ⋅ 4 = 8
28 2nn0 ⊢ 2 ∈ ℕ 0
29 28 a1i ⊢ N ∈ ℂ → 2 ∈ ℕ 0
30 3 8 29 expaddd ⊢ N ∈ ℂ → N 2 + 3 = N 2 ⁢ N 3
31 2cn ⊢ 2 ∈ ℂ
32 3p2e5 ⊢ 3 + 2 = 5
33 1 31 32 addcomli ⊢ 2 + 3 = 5
34 33 oveq2i ⊢ N 2 + 3 = N 5
35 30 34 eqtr3di ⊢ N ∈ ℂ → N 2 ⁢ N 3 = N 5
36 27 35 oveq12d ⊢ N ∈ ℂ → 2 ⋅ 4 ⁢ N 2 ⁢ N 3 = 8 ⁢ N 5
37 25 36 eqtrd ⊢ N ∈ ℂ → 2 ⁢ N 2 ⁢ 4 ⁢ N 3 = 8 ⁢ N 5
38 2 3 12 13 mul4d ⊢ N ∈ ℂ → 3 ⋅ N ⁢ 2 ⁢ N 2 = 3 ⋅ 2 ⁢ N ⁢ N 2
39 3t2e6 ⊢ 3 ⋅ 2 = 6
40 39 a1i ⊢ N ∈ ℂ → 3 ⋅ 2 = 6
41 df-3 ⊢ 3 = 2 + 1
42 41 oveq2i ⊢ N 3 = N 2 + 1
43 3 29 expp1d ⊢ N ∈ ℂ → N 2 + 1 = N 2 ⋅ N
44 13 3 mulcomd ⊢ N ∈ ℂ → N 2 ⋅ N = N ⁢ N 2
45 43 44 eqtrd ⊢ N ∈ ℂ → N 2 + 1 = N ⁢ N 2
46 42 45 eqtr2id ⊢ N ∈ ℂ → N ⁢ N 2 = N 3
47 40 46 oveq12d ⊢ N ∈ ℂ → 3 ⋅ 2 ⁢ N ⁢ N 2 = 6 ⁢ N 3
48 38 47 eqtrd ⊢ N ∈ ℂ → 3 ⋅ N ⁢ 2 ⁢ N 2 = 6 ⁢ N 3
49 10 mullidd ⊢ N ∈ ℂ → 1 ⁢ 4 ⁢ N 3 = 4 ⁢ N 3
50 48 49 oveq12d ⊢ N ∈ ℂ → 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 = 6 ⁢ N 3 + 4 ⁢ N 3
51 6cn ⊢ 6 ∈ ℂ
52 51 a1i ⊢ N ∈ ℂ → 6 ∈ ℂ
53 52 6 9 adddird ⊢ N ∈ ℂ → 6 + 4 ⁢ N 3 = 6 ⁢ N 3 + 4 ⁢ N 3
54 6p4e10 ⊢ 6 + 4 = 10
55 54 a1i ⊢ N ∈ ℂ → 6 + 4 = 10
56 55 oveq1d ⊢ N ∈ ℂ → 6 + 4 ⁢ N 3 = 10 ⁢ N 3
57 50 53 56 3eqtr2d ⊢ N ∈ ℂ → 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 = 10 ⁢ N 3
58 37 57 oveq12d ⊢ N ∈ ℂ → 2 ⁢ N 2 ⁢ 4 ⁢ N 3 − 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 = 8 ⁢ N 5 − 10 ⁢ N 3
59 4 mulridd ⊢ N ∈ ℂ → 3 ⋅ N ⋅ 1 = 3 ⋅ N
60 58 59 oveq12d ⊢ N ∈ ℂ → 2 ⁢ N 2 ⁢ 4 ⁢ N 3 - 3 ⋅ N ⁢ 2 ⁢ N 2 + 1 ⁢ 4 ⁢ N 3 + 3 ⋅ N ⋅ 1 = 8 ⁢ N 5 - 10 ⁢ N 3 + 3 ⋅ N
61 15 24 60 3eqtrd ⊢ N ∈ ℂ → 3 ⋅ N − 4 ⁢ N 3 ⁢ 1 − 2 ⁢ N 2 = 8 ⁢ N 5 - 10 ⁢ N 3 + 3 ⋅ N