Metamath Proof Explorer


Theorem sn-1ne2

Description: A proof of 1ne2 without using ax-mulcom , ax-mulass , ax-pre-mulgt0 . Based on mul02lem2 . (Contributed by SN, 13-Dec-2023)

Ref Expression
Assertion sn-1ne2 ⊢ 1 ≠ 2

Proof

Step Hyp Ref Expression
1 0ne1 ⊢ 0 ≠ 1
2 ax-icn ⊢ i ∈ ℂ
3 2 2 mulcli ⊢ i ⁢ i ∈ ℂ
4 ax-1cn ⊢ 1 ∈ ℂ
5 3 4 4 addassi ⊢ i ⁢ i + 1 + 1 = i ⁢ i + 1 + 1
6 5 a1i ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → i ⁢ i + 1 + 1 = i ⁢ i + 1 + 1
7 simpr ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → 1 = 1 + 1
8 7 oveq2d ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → i ⁢ i + 1 = i ⁢ i + 1 + 1
9 ax-i2m1 ⊢ i ⁢ i + 1 = 0
10 9 a1i ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → i ⁢ i + 1 = 0
11 6 8 10 3eqtr2rd ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → 0 = i ⁢ i + 1 + 1
12 simpl ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → 0 = 0 + 0
13 10 oveq1d ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → i ⁢ i + 1 + 1 = 0 + 1
14 11 12 13 3eqtr3d ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → 0 + 0 = 0 + 1
15 0red ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → 0 ∈ ℝ
16 1red ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → 1 ∈ ℝ
17 readdcan ⊢ 0 ∈ ℝ ∧ 1 ∈ ℝ ∧ 0 ∈ ℝ → 0 + 0 = 0 + 1 ↔ 0 = 1
18 15 16 15 17 syl3anc ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → 0 + 0 = 0 + 1 ↔ 0 = 1
19 14 18 mpbid ⊢ 0 = 0 + 0 ∧ 1 = 1 + 1 → 0 = 1
20 19 ex ⊢ 0 = 0 + 0 → 1 = 1 + 1 → 0 = 1
21 20 necon3d ⊢ 0 = 0 + 0 → 0 ≠ 1 → 1 ≠ 1 + 1
22 1 21 mpi ⊢ 0 = 0 + 0 → 1 ≠ 1 + 1
23 oveq2 ⊢ 1 = 1 + 1 → 0 ⋅ 1 = 0 ⋅ 1 + 1
24 0re ⊢ 0 ∈ ℝ
25 ax-1rid ⊢ 0 ∈ ℝ → 0 ⋅ 1 = 0
26 24 25 ax-mp ⊢ 0 ⋅ 1 = 0
27 0cn ⊢ 0 ∈ ℂ
28 27 4 4 adddii ⊢ 0 ⋅ 1 + 1 = 0 ⋅ 1 + 0 ⋅ 1
29 26 26 oveq12i ⊢ 0 ⋅ 1 + 0 ⋅ 1 = 0 + 0
30 28 29 eqtri ⊢ 0 ⋅ 1 + 1 = 0 + 0
31 23 26 30 3eqtr3g ⊢ 1 = 1 + 1 → 0 = 0 + 0
32 31 necon3i ⊢ 0 ≠ 0 + 0 → 1 ≠ 1 + 1
33 22 32 pm2.61ine ⊢ 1 ≠ 1 + 1
34 df-2 ⊢ 2 = 1 + 1
35 33 34 neeqtrri ⊢ 1 ≠ 2