Metamath Proof Explorer


Theorem taupi

Description: Relationship between _tau and _pi . This can be seen as connecting the ratio of a circle's circumference to its radius and the ratio of a circle's circumference to its diameter. (Contributed by Jim Kingdon, 19-Feb-2019) (Revised by AV, 1-Oct-2020)

Ref Expression
Assertion taupi ⊢ τ = 2 ⁢ π

Proof

Step Hyp Ref Expression
1 taupilem2 ⊢ τ ≤ 2 ⁢ π
2 inss1 ⊢ ℝ + ∩ cos -1 1 ⊆ ℝ +
3 rpssre ⊢ ℝ + ⊆ ℝ
4 2 3 sstri ⊢ ℝ + ∩ cos -1 1 ⊆ ℝ
5 2rp ⊢ 2 ∈ ℝ +
6 pirp ⊢ π ∈ ℝ +
7 rpmulcl ⊢ 2 ∈ ℝ + ∧ π ∈ ℝ + → 2 ⁢ π ∈ ℝ +
8 5 6 7 mp2an ⊢ 2 ⁢ π ∈ ℝ +
9 cos2pi ⊢ cos ⁡ 2 ⁢ π = 1
10 taupilem3 ⊢ 2 ⁢ π ∈ ℝ + ∩ cos -1 1 ↔ 2 ⁢ π ∈ ℝ + ∧ cos ⁡ 2 ⁢ π = 1
11 8 9 10 mpbir2an ⊢ 2 ⁢ π ∈ ℝ + ∩ cos -1 1
12 11 ne0ii ⊢ ℝ + ∩ cos -1 1 ≠ ∅
13 taupilemrplb ⊢ ∃ x ∈ ℝ ∀ y ∈ ℝ + ∩ cos -1 1 x ≤ y
14 4 12 13 3pm3.2i ⊢ ℝ + ∩ cos -1 1 ⊆ ℝ ∧ ℝ + ∩ cos -1 1 ≠ ∅ ∧ ∃ x ∈ ℝ ∀ y ∈ ℝ + ∩ cos -1 1 x ≤ y
15 2re ⊢ 2 ∈ ℝ
16 pire ⊢ π ∈ ℝ
17 15 16 remulcli ⊢ 2 ⁢ π ∈ ℝ
18 infregelb ⊢ ℝ + ∩ cos -1 1 ⊆ ℝ ∧ ℝ + ∩ cos -1 1 ≠ ∅ ∧ ∃ x ∈ ℝ ∀ y ∈ ℝ + ∩ cos -1 1 x ≤ y ∧ 2 ⁢ π ∈ ℝ → 2 ⁢ π ≤ inf ℝ + ∩ cos -1 1 ℝ < ↔ ∀ x ∈ ℝ + ∩ cos -1 1 2 ⁢ π ≤ x
19 14 17 18 mp2an ⊢ 2 ⁢ π ≤ inf ℝ + ∩ cos -1 1 ℝ < ↔ ∀ x ∈ ℝ + ∩ cos -1 1 2 ⁢ π ≤ x
20 taupilem3 ⊢ x ∈ ℝ + ∩ cos -1 1 ↔ x ∈ ℝ + ∧ cos ⁡ x = 1
21 taupilem1 ⊢ x ∈ ℝ + ∧ cos ⁡ x = 1 → 2 ⁢ π ≤ x
22 20 21 sylbi ⊢ x ∈ ℝ + ∩ cos -1 1 → 2 ⁢ π ≤ x
23 19 22 mprgbir ⊢ 2 ⁢ π ≤ inf ℝ + ∩ cos -1 1 ℝ <
24 df-tau ⊢ τ = inf ℝ + ∩ cos -1 1 ℝ <
25 23 24 breqtrri ⊢ 2 ⁢ π ≤ τ
26 infrecl ⊢ ℝ + ∩ cos -1 1 ⊆ ℝ ∧ ℝ + ∩ cos -1 1 ≠ ∅ ∧ ∃ x ∈ ℝ ∀ y ∈ ℝ + ∩ cos -1 1 x ≤ y → inf ℝ + ∩ cos -1 1 ℝ < ∈ ℝ
27 14 26 ax-mp ⊢ inf ℝ + ∩ cos -1 1 ℝ < ∈ ℝ
28 24 27 eqeltri ⊢ τ ∈ ℝ
29 28 17 letri3i ⊢ τ = 2 ⁢ π ↔ τ ≤ 2 ⁢ π ∧ 2 ⁢ π ≤ τ
30 1 25 29 mpbir2an ⊢ τ = 2 ⁢ π