Metamath Proof Explorer


Theorem vonvolmbl2

Description: A subset X of the space of 1-dimensional Real numbers is Lebesgue measurable if and only if its projection Y on the Real numbers is Lebesgue measure. (Contributed by Glauco Siliprandi, 3-Mar-2021)

Ref Expression
Hypotheses vonvolmbl2.f ⊢ Ⅎ _ f Y
vonvolmbl2.a ⊢ φ → A ∈ V
vonvolmbl2.x ⊢ φ → X ⊆ ℝ A
vonvolmbl2.y ⊢ Y = ⋃ f ∈ X ran ⁡ f
Assertion vonvolmbl2 ⊢ φ → X ∈ dom ⁡ voln ⁡ A ↔ Y ∈ dom ⁡ vol

Proof

Step Hyp Ref Expression
1 vonvolmbl2.f ⊢ Ⅎ _ f Y
2 vonvolmbl2.a ⊢ φ → A ∈ V
3 vonvolmbl2.x ⊢ φ → X ⊆ ℝ A
4 vonvolmbl2.y ⊢ Y = ⋃ f ∈ X ran ⁡ f
5 1 2 3 4 ssmapsn ⊢ φ → X = Y A
6 5 eleq1d ⊢ φ → X ∈ dom ⁡ voln ⁡ A ↔ Y A ∈ dom ⁡ voln ⁡ A
7 3 adantr ⊢ φ ∧ f ∈ X → X ⊆ ℝ A
8 simpr ⊢ φ ∧ f ∈ X → f ∈ X
9 7 8 sseldd ⊢ φ ∧ f ∈ X → f ∈ ℝ A
10 elmapi ⊢ f ∈ ℝ A → f : A ⟶ ℝ
11 frn ⊢ f : A ⟶ ℝ → ran ⁡ f ⊆ ℝ
12 9 10 11 3syl ⊢ φ ∧ f ∈ X → ran ⁡ f ⊆ ℝ
13 12 ralrimiva ⊢ φ → ∀ f ∈ X ran ⁡ f ⊆ ℝ
14 iunss ⊢ ⋃ f ∈ X ran ⁡ f ⊆ ℝ ↔ ∀ f ∈ X ran ⁡ f ⊆ ℝ
15 13 14 sylibr ⊢ φ → ⋃ f ∈ X ran ⁡ f ⊆ ℝ
16 4 15 eqsstrid ⊢ φ → Y ⊆ ℝ
17 2 16 vonvolmbl ⊢ φ → Y A ∈ dom ⁡ voln ⁡ A ↔ Y ∈ dom ⁡ vol
18 6 17 bitrd ⊢ φ → X ∈ dom ⁡ voln ⁡ A ↔ Y ∈ dom ⁡ vol