Metamath Proof Explorer


Theorem vtsval

Description: Value of the Vinogradov trigonometric sums. (Contributed by Thierry Arnoux, 1-Dec-2021)

Ref Expression
Hypotheses vtsval.n ⊢ φ → N ∈ ℕ 0
vtsval.x ⊢ φ → X ∈ ℂ
vtsval.l ⊢ φ → L : ℕ ⟶ ℂ
Assertion vtsval ⊢ φ → L vts N ⁡ X = ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ X

Proof

Step Hyp Ref Expression
1 vtsval.n ⊢ φ → N ∈ ℕ 0
2 vtsval.x ⊢ φ → X ∈ ℂ
3 vtsval.l ⊢ φ → L : ℕ ⟶ ℂ
4 cnex ⊢ ℂ ∈ V
5 nnex ⊢ ℕ ∈ V
6 4 5 elmap ⊢ L ∈ ℂ ℕ ↔ L : ℕ ⟶ ℂ
7 3 6 sylibr ⊢ φ → L ∈ ℂ ℕ
8 fveq1 ⊢ l = L → l ⁡ a = L ⁡ a
9 8 oveq1d ⊢ l = L → l ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x = L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x
10 9 sumeq2sdv ⊢ l = L → ∑ a = 1 n l ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x = ∑ a = 1 n L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x
11 10 mpteq2dv ⊢ l = L → x ∈ ℂ ⟼ ∑ a = 1 n l ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x = x ∈ ℂ ⟼ ∑ a = 1 n L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x
12 oveq2 ⊢ n = N → 1 … n = 1 … N
13 12 sumeq1d ⊢ n = N → ∑ a = 1 n L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x = ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x
14 13 mpteq2dv ⊢ n = N → x ∈ ℂ ⟼ ∑ a = 1 n L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x = x ∈ ℂ ⟼ ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x
15 df-vts ⊢ vts = l ∈ ℂ ℕ , n ∈ ℕ 0 ⟼ x ∈ ℂ ⟼ ∑ a = 1 n l ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x
16 4 mptex ⊢ x ∈ ℂ ⟼ ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x ∈ V
17 11 14 15 16 ovmpo ⊢ L ∈ ℂ ℕ ∧ N ∈ ℕ 0 → L vts N = x ∈ ℂ ⟼ ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x
18 7 1 17 syl2anc ⊢ φ → L vts N = x ∈ ℂ ⟼ ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x
19 oveq2 ⊢ x = X → a ⁢ x = a ⁢ X
20 19 oveq2d ⊢ x = X → i ⁢ 2 ⁢ π ⁢ a ⁢ x = i ⁢ 2 ⁢ π ⁢ a ⁢ X
21 20 fveq2d ⊢ x = X → e i ⁢ 2 ⁢ π ⁢ a ⁢ x = e i ⁢ 2 ⁢ π ⁢ a ⁢ X
22 21 oveq2d ⊢ x = X → L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x = L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ X
23 22 sumeq2sdv ⊢ x = X → ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x = ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ X
24 23 adantl ⊢ φ ∧ x = X → ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ x = ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ X
25 sumex ⊢ ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ X ∈ V
26 25 a1i ⊢ φ → ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ X ∈ V
27 18 24 2 26 fvmptd ⊢ φ → L vts N ⁡ X = ∑ a = 1 N L ⁡ a ⁢ e i ⁢ 2 ⁢ π ⁢ a ⁢ X