Metamath Proof Explorer


Theorem zlmodzxzadd

Description: The addition of the ZZ-module ZZ X. ZZ . (Contributed by AV, 22-May-2019) (Revised by AV, 10-Jun-2019)

Ref Expression
Hypotheses zlmodzxz.z ⊢ Z = ℤ ring freeLMod 0 1
zlmodzxzadd.p ⊢ + ˙ = + Z
Assertion zlmodzxzadd ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C + ˙ 0 B 1 D = 0 A + B 1 C + D

Proof

Step Hyp Ref Expression
1 zlmodzxz.z ⊢ Z = ℤ ring freeLMod 0 1
2 zlmodzxzadd.p ⊢ + ˙ = + Z
3 eqid ⊢ Base Z = Base Z
4 zringring ⊢ ℤ ring ∈ Ring
5 4 a1i ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → ℤ ring ∈ Ring
6 prex ⊢ 0 1 ∈ V
7 6 a1i ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 1 ∈ V
8 simpl ⊢ A ∈ ℤ ∧ B ∈ ℤ → A ∈ ℤ
9 simpl ⊢ C ∈ ℤ ∧ D ∈ ℤ → C ∈ ℤ
10 1 zlmodzxzel ⊢ A ∈ ℤ ∧ C ∈ ℤ → 0 A 1 C ∈ Base Z
11 8 9 10 syl2an ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C ∈ Base Z
12 simpr ⊢ A ∈ ℤ ∧ B ∈ ℤ → B ∈ ℤ
13 simpr ⊢ C ∈ ℤ ∧ D ∈ ℤ → D ∈ ℤ
14 1 zlmodzxzel ⊢ B ∈ ℤ ∧ D ∈ ℤ → 0 B 1 D ∈ Base Z
15 12 13 14 syl2an ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 B 1 D ∈ Base Z
16 eqid ⊢ + ℤ ring = + ℤ ring
17 1 3 5 7 11 15 16 2 frlmplusgval ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C + ˙ 0 B 1 D = 0 A 1 C + ℤ ring f 0 B 1 D
18 c0ex ⊢ 0 ∈ V
19 1ex ⊢ 1 ∈ V
20 18 19 pm3.2i ⊢ 0 ∈ V ∧ 1 ∈ V
21 20 a1i ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 ∈ V ∧ 1 ∈ V
22 8 9 anim12i ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → A ∈ ℤ ∧ C ∈ ℤ
23 0ne1 ⊢ 0 ≠ 1
24 23 a1i ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 ≠ 1
25 fnprg ⊢ 0 ∈ V ∧ 1 ∈ V ∧ A ∈ ℤ ∧ C ∈ ℤ ∧ 0 ≠ 1 → 0 A 1 C Fn 0 1
26 21 22 24 25 syl3anc ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C Fn 0 1
27 12 13 anim12i ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → B ∈ ℤ ∧ D ∈ ℤ
28 fnprg ⊢ 0 ∈ V ∧ 1 ∈ V ∧ B ∈ ℤ ∧ D ∈ ℤ ∧ 0 ≠ 1 → 0 B 1 D Fn 0 1
29 21 27 24 28 syl3anc ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 B 1 D Fn 0 1
30 7 26 29 offvalfv ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C + ℤ ring f 0 B 1 D = x ∈ 0 1 ⟼ 0 A 1 C ⁡ x + ℤ ring 0 B 1 D ⁡ x
31 18 a1i ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 ∈ V
32 19 a1i ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 1 ∈ V
33 ovexd ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → A + ℤ ring B ∈ V
34 ovexd ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → C + ℤ ring D ∈ V
35 fveq2 ⊢ x = 0 → 0 A 1 C ⁡ x = 0 A 1 C ⁡ 0
36 fveq2 ⊢ x = 0 → 0 B 1 D ⁡ x = 0 B 1 D ⁡ 0
37 35 36 oveq12d ⊢ x = 0 → 0 A 1 C ⁡ x + ℤ ring 0 B 1 D ⁡ x = 0 A 1 C ⁡ 0 + ℤ ring 0 B 1 D ⁡ 0
38 8 adantr ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → A ∈ ℤ
39 fvpr1g ⊢ 0 ∈ V ∧ A ∈ ℤ ∧ 0 ≠ 1 → 0 A 1 C ⁡ 0 = A
40 31 38 24 39 syl3anc ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C ⁡ 0 = A
41 12 adantr ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → B ∈ ℤ
42 fvpr1g ⊢ 0 ∈ V ∧ B ∈ ℤ ∧ 0 ≠ 1 → 0 B 1 D ⁡ 0 = B
43 31 41 24 42 syl3anc ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 B 1 D ⁡ 0 = B
44 40 43 oveq12d ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C ⁡ 0 + ℤ ring 0 B 1 D ⁡ 0 = A + ℤ ring B
45 37 44 sylan9eqr ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ ∧ x = 0 → 0 A 1 C ⁡ x + ℤ ring 0 B 1 D ⁡ x = A + ℤ ring B
46 fveq2 ⊢ x = 1 → 0 A 1 C ⁡ x = 0 A 1 C ⁡ 1
47 fveq2 ⊢ x = 1 → 0 B 1 D ⁡ x = 0 B 1 D ⁡ 1
48 46 47 oveq12d ⊢ x = 1 → 0 A 1 C ⁡ x + ℤ ring 0 B 1 D ⁡ x = 0 A 1 C ⁡ 1 + ℤ ring 0 B 1 D ⁡ 1
49 9 adantl ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → C ∈ ℤ
50 fvpr2g ⊢ 1 ∈ V ∧ C ∈ ℤ ∧ 0 ≠ 1 → 0 A 1 C ⁡ 1 = C
51 32 49 24 50 syl3anc ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C ⁡ 1 = C
52 13 adantl ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → D ∈ ℤ
53 fvpr2g ⊢ 1 ∈ V ∧ D ∈ ℤ ∧ 0 ≠ 1 → 0 B 1 D ⁡ 1 = D
54 32 52 24 53 syl3anc ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 B 1 D ⁡ 1 = D
55 51 54 oveq12d ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C ⁡ 1 + ℤ ring 0 B 1 D ⁡ 1 = C + ℤ ring D
56 48 55 sylan9eqr ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ ∧ x = 1 → 0 A 1 C ⁡ x + ℤ ring 0 B 1 D ⁡ x = C + ℤ ring D
57 31 32 33 34 45 56 fmptpr ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A + ℤ ring B 1 C + ℤ ring D = x ∈ 0 1 ⟼ 0 A 1 C ⁡ x + ℤ ring 0 B 1 D ⁡ x
58 zringplusg ⊢ + = + ℤ ring
59 58 eqcomi ⊢ + ℤ ring = +
60 59 oveqi ⊢ A + ℤ ring B = A + B
61 60 opeq2i ⊢ 0 A + ℤ ring B = 0 A + B
62 59 oveqi ⊢ C + ℤ ring D = C + D
63 62 opeq2i ⊢ 1 C + ℤ ring D = 1 C + D
64 61 63 preq12i ⊢ 0 A + ℤ ring B 1 C + ℤ ring D = 0 A + B 1 C + D
65 57 64 eqtr3di ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → x ∈ 0 1 ⟼ 0 A 1 C ⁡ x + ℤ ring 0 B 1 D ⁡ x = 0 A + B 1 C + D
66 17 30 65 3eqtrd ⊢ A ∈ ℤ ∧ B ∈ ℤ ∧ C ∈ ℤ ∧ D ∈ ℤ → 0 A 1 C + ˙ 0 B 1 D = 0 A + B 1 C + D