Metamath Proof Explorer


Theorem binom3

Description: The cube of a binomial. (Contributed by Mario Carneiro, 24-Apr-2015)

Ref Expression
Assertion binom3 ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 3 = A 3 + 3 ⁢ A 2 ⁢ B + 3 ⁢ A ⁢ B 2 + B 3

Proof

Step Hyp Ref Expression
1 df-3 ⊢ 3 = 2 + 1
2 1 oveq2i ⊢ A + B 3 = A + B 2 + 1
3 addcl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ∈ ℂ
4 2nn0 ⊢ 2 ∈ ℕ 0
5 expp1 ⊢ A + B ∈ ℂ ∧ 2 ∈ ℕ 0 → A + B 2 + 1 = A + B 2 ⁢ A + B
6 3 4 5 sylancl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 + 1 = A + B 2 ⁢ A + B
7 2 6 eqtrid ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 3 = A + B 2 ⁢ A + B
8 sqcl ⊢ A + B ∈ ℂ → A + B 2 ∈ ℂ
9 3 8 syl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 ∈ ℂ
10 simpl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ∈ ℂ
11 simpr ⊢ A ∈ ℂ ∧ B ∈ ℂ → B ∈ ℂ
12 9 10 11 adddid ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 ⁢ A + B = A + B 2 ⁢ A + A + B 2 ⁢ B
13 binom2 ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 = A 2 + 2 ⁢ A ⁢ B + B 2
14 13 oveq1d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 ⁢ A = A 2 + 2 ⁢ A ⁢ B + B 2 ⁢ A
15 sqcl ⊢ A ∈ ℂ → A 2 ∈ ℂ
16 10 15 syl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 ∈ ℂ
17 2cn ⊢ 2 ∈ ℂ
18 mulcl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B ∈ ℂ
19 mulcl ⊢ 2 ∈ ℂ ∧ A ⁢ B ∈ ℂ → 2 ⁢ A ⁢ B ∈ ℂ
20 17 18 19 sylancr ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A ⁢ B ∈ ℂ
21 16 20 addcld ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 2 ⁢ A ⁢ B ∈ ℂ
22 sqcl ⊢ B ∈ ℂ → B 2 ∈ ℂ
23 11 22 syl ⊢ A ∈ ℂ ∧ B ∈ ℂ → B 2 ∈ ℂ
24 21 23 10 adddird ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 2 ⁢ A ⁢ B + B 2 ⁢ A = A 2 + 2 ⁢ A ⁢ B ⁢ A + B 2 ⁢ A
25 16 20 10 adddird ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 2 ⁢ A ⁢ B ⁢ A = A 2 ⁢ A + 2 ⁢ A ⁢ B ⁢ A
26 1 oveq2i ⊢ A 3 = A 2 + 1
27 expp1 ⊢ A ∈ ℂ ∧ 2 ∈ ℕ 0 → A 2 + 1 = A 2 ⁢ A
28 10 4 27 sylancl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 1 = A 2 ⁢ A
29 26 28 eqtrid ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 = A 2 ⁢ A
30 sqval ⊢ A ∈ ℂ → A 2 = A ⁢ A
31 10 30 syl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 = A ⁢ A
32 31 oveq1d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 ⁢ B = A ⁢ A ⁢ B
33 10 10 11 mul32d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ A ⁢ B = A ⁢ B ⁢ A
34 32 33 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 ⁢ B = A ⁢ B ⁢ A
35 34 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A 2 ⁢ B = 2 ⁢ A ⁢ B ⁢ A
36 2cnd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ∈ ℂ
37 36 18 10 mulassd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A ⁢ B ⁢ A = 2 ⁢ A ⁢ B ⁢ A
38 35 37 eqtr4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A 2 ⁢ B = 2 ⁢ A ⁢ B ⁢ A
39 29 38 oveq12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 + 2 ⁢ A 2 ⁢ B = A 2 ⁢ A + 2 ⁢ A ⁢ B ⁢ A
40 25 39 eqtr4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 2 ⁢ A ⁢ B ⁢ A = A 3 + 2 ⁢ A 2 ⁢ B
41 23 10 mulcomd ⊢ A ∈ ℂ ∧ B ∈ ℂ → B 2 ⁢ A = A ⁢ B 2
42 40 41 oveq12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 2 ⁢ A ⁢ B ⁢ A + B 2 ⁢ A = A 3 + 2 ⁢ A 2 ⁢ B + A ⁢ B 2
43 14 24 42 3eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 ⁢ A = A 3 + 2 ⁢ A 2 ⁢ B + A ⁢ B 2
44 13 oveq1d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 ⁢ B = A 2 + 2 ⁢ A ⁢ B + B 2 ⁢ B
45 21 23 11 adddird ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 2 ⁢ A ⁢ B + B 2 ⁢ B = A 2 + 2 ⁢ A ⁢ B ⁢ B + B 2 ⁢ B
46 sqval ⊢ B ∈ ℂ → B 2 = B ⁢ B
47 11 46 syl ⊢ A ∈ ℂ ∧ B ∈ ℂ → B 2 = B ⁢ B
48 47 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B 2 = A ⁢ B ⁢ B
49 10 11 11 mulassd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B ⁢ B = A ⁢ B ⁢ B
50 48 49 eqtr4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B 2 = A ⁢ B ⁢ B
51 50 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A ⁢ B 2 = 2 ⁢ A ⁢ B ⁢ B
52 36 18 11 mulassd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A ⁢ B ⁢ B = 2 ⁢ A ⁢ B ⁢ B
53 51 52 eqtr4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A ⁢ B 2 = 2 ⁢ A ⁢ B ⁢ B
54 53 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 ⁢ B + 2 ⁢ A ⁢ B 2 = A 2 ⁢ B + 2 ⁢ A ⁢ B ⁢ B
55 16 20 11 adddird ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 2 ⁢ A ⁢ B ⁢ B = A 2 ⁢ B + 2 ⁢ A ⁢ B ⁢ B
56 54 55 eqtr4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 ⁢ B + 2 ⁢ A ⁢ B 2 = A 2 + 2 ⁢ A ⁢ B ⁢ B
57 1 oveq2i ⊢ B 3 = B 2 + 1
58 expp1 ⊢ B ∈ ℂ ∧ 2 ∈ ℕ 0 → B 2 + 1 = B 2 ⁢ B
59 11 4 58 sylancl ⊢ A ∈ ℂ ∧ B ∈ ℂ → B 2 + 1 = B 2 ⁢ B
60 57 59 eqtrid ⊢ A ∈ ℂ ∧ B ∈ ℂ → B 3 = B 2 ⁢ B
61 56 60 oveq12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 ⁢ B + 2 ⁢ A ⁢ B 2 + B 3 = A 2 + 2 ⁢ A ⁢ B ⁢ B + B 2 ⁢ B
62 16 11 mulcld ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 ⁢ B ∈ ℂ
63 10 23 mulcld ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B 2 ∈ ℂ
64 mulcl ⊢ 2 ∈ ℂ ∧ A ⁢ B 2 ∈ ℂ → 2 ⁢ A ⁢ B 2 ∈ ℂ
65 17 63 64 sylancr ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A ⁢ B 2 ∈ ℂ
66 3nn0 ⊢ 3 ∈ ℕ 0
67 expcl ⊢ B ∈ ℂ ∧ 3 ∈ ℕ 0 → B 3 ∈ ℂ
68 11 66 67 sylancl ⊢ A ∈ ℂ ∧ B ∈ ℂ → B 3 ∈ ℂ
69 62 65 68 addassd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 ⁢ B + 2 ⁢ A ⁢ B 2 + B 3 = A 2 ⁢ B + 2 ⁢ A ⁢ B 2 + B 3
70 61 69 eqtr3d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 2 + 2 ⁢ A ⁢ B ⁢ B + B 2 ⁢ B = A 2 ⁢ B + 2 ⁢ A ⁢ B 2 + B 3
71 44 45 70 3eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 ⁢ B = A 2 ⁢ B + 2 ⁢ A ⁢ B 2 + B 3
72 43 71 oveq12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 ⁢ A + A + B 2 ⁢ B = A 3 + 2 ⁢ A 2 ⁢ B + A ⁢ B 2 + A 2 ⁢ B + 2 ⁢ A ⁢ B 2 + B 3
73 expcl ⊢ A ∈ ℂ ∧ 3 ∈ ℕ 0 → A 3 ∈ ℂ
74 10 66 73 sylancl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 ∈ ℂ
75 mulcl ⊢ 2 ∈ ℂ ∧ A 2 ⁢ B ∈ ℂ → 2 ⁢ A 2 ⁢ B ∈ ℂ
76 17 62 75 sylancr ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A 2 ⁢ B ∈ ℂ
77 74 76 addcld ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 + 2 ⁢ A 2 ⁢ B ∈ ℂ
78 65 68 addcld ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A ⁢ B 2 + B 3 ∈ ℂ
79 77 63 62 78 add4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 + 2 ⁢ A 2 ⁢ B + A ⁢ B 2 + A 2 ⁢ B + 2 ⁢ A ⁢ B 2 + B 3 = A 3 + 2 ⁢ A 2 ⁢ B + A 2 ⁢ B + A ⁢ B 2 + 2 ⁢ A ⁢ B 2 + B 3
80 12 72 79 3eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 2 ⁢ A + B = A 3 + 2 ⁢ A 2 ⁢ B + A 2 ⁢ B + A ⁢ B 2 + 2 ⁢ A ⁢ B 2 + B 3
81 74 76 62 addassd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 + 2 ⁢ A 2 ⁢ B + A 2 ⁢ B = A 3 + 2 ⁢ A 2 ⁢ B + A 2 ⁢ B
82 1 oveq1i ⊢ 3 ⁢ A 2 ⁢ B = 2 + 1 ⁢ A 2 ⁢ B
83 1cnd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 1 ∈ ℂ
84 36 83 62 adddird ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 + 1 ⁢ A 2 ⁢ B = 2 ⁢ A 2 ⁢ B + 1 ⁢ A 2 ⁢ B
85 82 84 eqtrid ⊢ A ∈ ℂ ∧ B ∈ ℂ → 3 ⁢ A 2 ⁢ B = 2 ⁢ A 2 ⁢ B + 1 ⁢ A 2 ⁢ B
86 62 mullidd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 1 ⁢ A 2 ⁢ B = A 2 ⁢ B
87 86 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 2 ⁢ A 2 ⁢ B + 1 ⁢ A 2 ⁢ B = 2 ⁢ A 2 ⁢ B + A 2 ⁢ B
88 85 87 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 3 ⁢ A 2 ⁢ B = 2 ⁢ A 2 ⁢ B + A 2 ⁢ B
89 88 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 + 3 ⁢ A 2 ⁢ B = A 3 + 2 ⁢ A 2 ⁢ B + A 2 ⁢ B
90 81 89 eqtr4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 + 2 ⁢ A 2 ⁢ B + A 2 ⁢ B = A 3 + 3 ⁢ A 2 ⁢ B
91 1p2e3 ⊢ 1 + 2 = 3
92 91 oveq1i ⊢ 1 + 2 ⁢ A ⁢ B 2 = 3 ⁢ A ⁢ B 2
93 83 36 63 adddird ⊢ A ∈ ℂ ∧ B ∈ ℂ → 1 + 2 ⁢ A ⁢ B 2 = 1 ⁢ A ⁢ B 2 + 2 ⁢ A ⁢ B 2
94 92 93 eqtr3id ⊢ A ∈ ℂ ∧ B ∈ ℂ → 3 ⁢ A ⁢ B 2 = 1 ⁢ A ⁢ B 2 + 2 ⁢ A ⁢ B 2
95 63 mullidd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 1 ⁢ A ⁢ B 2 = A ⁢ B 2
96 95 oveq1d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 1 ⁢ A ⁢ B 2 + 2 ⁢ A ⁢ B 2 = A ⁢ B 2 + 2 ⁢ A ⁢ B 2
97 94 96 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → 3 ⁢ A ⁢ B 2 = A ⁢ B 2 + 2 ⁢ A ⁢ B 2
98 97 oveq1d ⊢ A ∈ ℂ ∧ B ∈ ℂ → 3 ⁢ A ⁢ B 2 + B 3 = A ⁢ B 2 + 2 ⁢ A ⁢ B 2 + B 3
99 63 65 68 addassd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B 2 + 2 ⁢ A ⁢ B 2 + B 3 = A ⁢ B 2 + 2 ⁢ A ⁢ B 2 + B 3
100 98 99 eqtr2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ⁢ B 2 + 2 ⁢ A ⁢ B 2 + B 3 = 3 ⁢ A ⁢ B 2 + B 3
101 90 100 oveq12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A 3 + 2 ⁢ A 2 ⁢ B + A 2 ⁢ B + A ⁢ B 2 + 2 ⁢ A ⁢ B 2 + B 3 = A 3 + 3 ⁢ A 2 ⁢ B + 3 ⁢ A ⁢ B 2 + B 3
102 7 80 101 3eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B 3 = A 3 + 3 ⁢ A 2 ⁢ B + 3 ⁢ A ⁢ B 2 + B 3