Metamath Proof Explorer


Theorem cvmliftlem1

Description: Lemma for cvmlift . In cvmliftlem15 , we picked an N large enough so that the sections ( G " [ ( k - 1 ) / N , k / N ] ) are all contained in an even covering, and the function T enumerates these even coverings. So 1st( TM ) is a neighborhood of ( G " [ ( M - 1 ) / N , M / N ] ) , and 2nd( TM ) is an even covering of 1st( TM ) , which is to say a disjoint union of open sets in C whose image is 1st( TM ) . (Contributed by Mario Carneiro, 14-Feb-2015)

Ref Expression
Hypotheses cvmliftlem.1 ⊢ S = k ∈ J ⟼ s ∈ 𝒫 C ∖ ∅ | ⋃ s = F -1 k ∧ ∀ u ∈ s ∀ v ∈ s ∖ u u ∩ v = ∅ ∧ F ↾ u ∈ C ↾ 𝑡 u Homeo J ↾ 𝑡 k
cvmliftlem.b ⊢ B = ⋃ C
cvmliftlem.x ⊢ X = ⋃ J
cvmliftlem.f ⊢ φ → F ∈ C CovMap J
cvmliftlem.g ⊢ φ → G ∈ II Cn J
cvmliftlem.p ⊢ φ → P ∈ B
cvmliftlem.e ⊢ φ → F ⁡ P = G ⁡ 0
cvmliftlem.n ⊢ φ → N ∈ ℕ
cvmliftlem.t ⊢ φ → T : 1 … N ⟶ ⋃ j ∈ J j × S ⁡ j
cvmliftlem.a ⊢ φ → ∀ k ∈ 1 … N G k − 1 N k N ⊆ 1 st ⁡ T ⁡ k
cvmliftlem.l ⊢ L = topGen ⁡ ran ⁡ .
cvmliftlem1.m ⊢ φ ∧ ψ → M ∈ 1 … N
Assertion cvmliftlem1 ⊢ φ ∧ ψ → 2 nd ⁡ T ⁡ M ∈ S ⁡ 1 st ⁡ T ⁡ M

Proof

Step Hyp Ref Expression
1 cvmliftlem.1 ⊢ S = k ∈ J ⟼ s ∈ 𝒫 C ∖ ∅ | ⋃ s = F -1 k ∧ ∀ u ∈ s ∀ v ∈ s ∖ u u ∩ v = ∅ ∧ F ↾ u ∈ C ↾ 𝑡 u Homeo J ↾ 𝑡 k
2 cvmliftlem.b ⊢ B = ⋃ C
3 cvmliftlem.x ⊢ X = ⋃ J
4 cvmliftlem.f ⊢ φ → F ∈ C CovMap J
5 cvmliftlem.g ⊢ φ → G ∈ II Cn J
6 cvmliftlem.p ⊢ φ → P ∈ B
7 cvmliftlem.e ⊢ φ → F ⁡ P = G ⁡ 0
8 cvmliftlem.n ⊢ φ → N ∈ ℕ
9 cvmliftlem.t ⊢ φ → T : 1 … N ⟶ ⋃ j ∈ J j × S ⁡ j
10 cvmliftlem.a ⊢ φ → ∀ k ∈ 1 … N G k − 1 N k N ⊆ 1 st ⁡ T ⁡ k
11 cvmliftlem.l ⊢ L = topGen ⁡ ran ⁡ .
12 cvmliftlem1.m ⊢ φ ∧ ψ → M ∈ 1 … N
13 relxp ⊢ Rel ⁡ j × S ⁡ j
14 13 rgenw ⊢ ∀ j ∈ J Rel ⁡ j × S ⁡ j
15 reliun ⊢ Rel ⁡ ⋃ j ∈ J j × S ⁡ j ↔ ∀ j ∈ J Rel ⁡ j × S ⁡ j
16 14 15 mpbir ⊢ Rel ⁡ ⋃ j ∈ J j × S ⁡ j
17 9 adantr ⊢ φ ∧ ψ → T : 1 … N ⟶ ⋃ j ∈ J j × S ⁡ j
18 17 12 ffvelcdmd ⊢ φ ∧ ψ → T ⁡ M ∈ ⋃ j ∈ J j × S ⁡ j
19 1st2nd ⊢ Rel ⁡ ⋃ j ∈ J j × S ⁡ j ∧ T ⁡ M ∈ ⋃ j ∈ J j × S ⁡ j → T ⁡ M = 1 st ⁡ T ⁡ M 2 nd ⁡ T ⁡ M
20 16 18 19 sylancr ⊢ φ ∧ ψ → T ⁡ M = 1 st ⁡ T ⁡ M 2 nd ⁡ T ⁡ M
21 20 18 eqeltrrd ⊢ φ ∧ ψ → 1 st ⁡ T ⁡ M 2 nd ⁡ T ⁡ M ∈ ⋃ j ∈ J j × S ⁡ j
22 fveq2 ⊢ j = 1 st ⁡ T ⁡ M → S ⁡ j = S ⁡ 1 st ⁡ T ⁡ M
23 22 opeliunxp2 ⊢ 1 st ⁡ T ⁡ M 2 nd ⁡ T ⁡ M ∈ ⋃ j ∈ J j × S ⁡ j ↔ 1 st ⁡ T ⁡ M ∈ J ∧ 2 nd ⁡ T ⁡ M ∈ S ⁡ 1 st ⁡ T ⁡ M
24 23 simprbi ⊢ 1 st ⁡ T ⁡ M 2 nd ⁡ T ⁡ M ∈ ⋃ j ∈ J j × S ⁡ j → 2 nd ⁡ T ⁡ M ∈ S ⁡ 1 st ⁡ T ⁡ M
25 21 24 syl ⊢ φ ∧ ψ → 2 nd ⁡ T ⁡ M ∈ S ⁡ 1 st ⁡ T ⁡ M