Metamath Proof Explorer


Theorem dig1

Description: All but one digits of 1 are 0. (Contributed by AV, 24-May-2020)

Ref Expression
Assertion dig1 ⊢ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K digit ⁡ B 1 = if K = 0 1 0

Proof

Step Hyp Ref Expression
1 eluzelcn ⊢ B ∈ ℤ ≥ 2 → B ∈ ℂ
2 1 exp0d ⊢ B ∈ ℤ ≥ 2 → B 0 = 1
3 2 eqcomd ⊢ B ∈ ℤ ≥ 2 → 1 = B 0
4 3 ad2antrl ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → 1 = B 0
5 4 oveq2d ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K digit ⁡ B 1 = K digit ⁡ B B 0
6 simprl ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → B ∈ ℤ ≥ 2
7 simpr ⊢ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K ∈ ℤ
8 7 anim2i ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → 0 ≤ K ∧ K ∈ ℤ
9 8 ancomd ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K ∈ ℤ ∧ 0 ≤ K
10 elnn0z ⊢ K ∈ ℕ 0 ↔ K ∈ ℤ ∧ 0 ≤ K
11 9 10 sylibr ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K ∈ ℕ 0
12 0nn0 ⊢ 0 ∈ ℕ 0
13 12 a1i ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → 0 ∈ ℕ 0
14 digexp ⊢ B ∈ ℤ ≥ 2 ∧ K ∈ ℕ 0 ∧ 0 ∈ ℕ 0 → K digit ⁡ B B 0 = if K = 0 1 0
15 6 11 13 14 syl3anc ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K digit ⁡ B B 0 = if K = 0 1 0
16 5 15 eqtrd ⊢ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K digit ⁡ B 1 = if K = 0 1 0
17 eluz2nn ⊢ B ∈ ℤ ≥ 2 → B ∈ ℕ
18 17 ad2antrl ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → B ∈ ℕ
19 simprr ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K ∈ ℤ
20 nn0ge0 ⊢ K ∈ ℕ 0 → 0 ≤ K
21 20 a1i ⊢ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K ∈ ℕ 0 → 0 ≤ K
22 21 con3d ⊢ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → ¬ 0 ≤ K → ¬ K ∈ ℕ 0
23 22 impcom ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → ¬ K ∈ ℕ 0
24 19 23 eldifd ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K ∈ ℤ ∖ ℕ 0
25 1nn0 ⊢ 1 ∈ ℕ 0
26 25 a1i ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → 1 ∈ ℕ 0
27 dignn0fr ⊢ B ∈ ℕ ∧ K ∈ ℤ ∖ ℕ 0 ∧ 1 ∈ ℕ 0 → K digit ⁡ B 1 = 0
28 18 24 26 27 syl3anc ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K digit ⁡ B 1 = 0
29 0le0 ⊢ 0 ≤ 0
30 breq2 ⊢ K = 0 → 0 ≤ K ↔ 0 ≤ 0
31 29 30 mpbiri ⊢ K = 0 → 0 ≤ K
32 31 a1i ⊢ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K = 0 → 0 ≤ K
33 32 con3d ⊢ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → ¬ 0 ≤ K → ¬ K = 0
34 33 impcom ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → ¬ K = 0
35 34 iffalsed ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → if K = 0 1 0 = 0
36 28 35 eqtr4d ⊢ ¬ 0 ≤ K ∧ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K digit ⁡ B 1 = if K = 0 1 0
37 16 36 pm2.61ian ⊢ B ∈ ℤ ≥ 2 ∧ K ∈ ℤ → K digit ⁡ B 1 = if K = 0 1 0