Metamath Proof Explorer


Theorem fsuppco2

Description: The composition of a function which maps the zero to zero with a finitely supported function is finitely supported. This is not only a special case of fsuppcor because it does not require that the "zero" is an element of the range of the finitely supported function. (Contributed by AV, 6-Jun-2019)

Ref Expression
Hypotheses fsuppco2.z ⊢ φ → Z ∈ W
fsuppco2.f ⊢ φ → F : A ⟶ B
fsuppco2.g ⊢ φ → G : B ⟶ B
fsuppco2.a ⊢ φ → A ∈ U
fsuppco2.b ⊢ φ → B ∈ V
fsuppco2.n ⊢ φ → finSupp Z⁡ F
fsuppco2.i ⊢ φ → G ⁡ Z = Z
Assertion fsuppco2 ⊢ φ → finSupp Z⁡ G ∘ F

Proof

Step Hyp Ref Expression
1 fsuppco2.z ⊢ φ → Z ∈ W
2 fsuppco2.f ⊢ φ → F : A ⟶ B
3 fsuppco2.g ⊢ φ → G : B ⟶ B
4 fsuppco2.a ⊢ φ → A ∈ U
5 fsuppco2.b ⊢ φ → B ∈ V
6 fsuppco2.n ⊢ φ → finSupp Z⁡ F
7 fsuppco2.i ⊢ φ → G ⁡ Z = Z
8 3 ffund ⊢ φ → Fun ⁡ G
9 2 ffund ⊢ φ → Fun ⁡ F
10 funco ⊢ Fun ⁡ G ∧ Fun ⁡ F → Fun ⁡ G ∘ F
11 8 9 10 syl2anc ⊢ φ → Fun ⁡ G ∘ F
12 6 fsuppimpd ⊢ φ → F supp Z ∈ Fin
13 fco ⊢ G : B ⟶ B ∧ F : A ⟶ B → G ∘ F : A ⟶ B
14 3 2 13 syl2anc ⊢ φ → G ∘ F : A ⟶ B
15 eldifi ⊢ x ∈ A ∖ supp Z⁡ F → x ∈ A
16 fvco3 ⊢ F : A ⟶ B ∧ x ∈ A → G ∘ F ⁡ x = G ⁡ F ⁡ x
17 2 15 16 syl2an ⊢ φ ∧ x ∈ A ∖ supp Z⁡ F → G ∘ F ⁡ x = G ⁡ F ⁡ x
18 ssidd ⊢ φ → F supp Z ⊆ F supp Z
19 2 18 4 1 suppssr ⊢ φ ∧ x ∈ A ∖ supp Z⁡ F → F ⁡ x = Z
20 19 fveq2d ⊢ φ ∧ x ∈ A ∖ supp Z⁡ F → G ⁡ F ⁡ x = G ⁡ Z
21 7 adantr ⊢ φ ∧ x ∈ A ∖ supp Z⁡ F → G ⁡ Z = Z
22 17 20 21 3eqtrd ⊢ φ ∧ x ∈ A ∖ supp Z⁡ F → G ∘ F ⁡ x = Z
23 14 22 suppss ⊢ φ → G ∘ F supp Z ⊆ F supp Z
24 12 23 ssfid ⊢ φ → G ∘ F supp Z ∈ Fin
25 3 5 fexd ⊢ φ → G ∈ V
26 2 4 fexd ⊢ φ → F ∈ V
27 coexg ⊢ G ∈ V ∧ F ∈ V → G ∘ F ∈ V
28 25 26 27 syl2anc ⊢ φ → G ∘ F ∈ V
29 isfsupp ⊢ G ∘ F ∈ V ∧ Z ∈ W → finSupp Z⁡ G ∘ F ↔ Fun ⁡ G ∘ F ∧ G ∘ F supp Z ∈ Fin
30 28 1 29 syl2anc ⊢ φ → finSupp Z⁡ G ∘ F ↔ Fun ⁡ G ∘ F ∧ G ∘ F supp Z ∈ Fin
31 11 24 30 mpbir2and ⊢ φ → finSupp Z⁡ G ∘ F