Metamath Proof Explorer


Theorem hdmap14lem14

Description: Part of proof of part 14 in Baer p. 50 line 3. (Contributed by NM, 6-Jun-2015)

Ref Expression
Hypotheses hdmap14lem12.h ⊢ H = LHyp ⁡ K
hdmap14lem12.u ⊢ U = DVecH ⁡ K ⁡ W
hdmap14lem12.v ⊢ V = Base U
hdmap14lem12.t ⊢ · ˙ = ⋅ U
hdmap14lem12.r ⊢ R = Scalar ⁡ U
hdmap14lem12.b ⊢ B = Base R
hdmap14lem12.c ⊢ C = LCDual ⁡ K ⁡ W
hdmap14lem12.e ⊢ ∙ ˙ = ⋅ C
hdmap14lem12.s ⊢ S = HDMap ⁡ K ⁡ W
hdmap14lem12.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmap14lem12.f ⊢ φ → F ∈ B
hdmap14lem12.p ⊢ P = Scalar ⁡ C
hdmap14lem12.a ⊢ A = Base P
Assertion hdmap14lem14 ⊢ φ → ∃! g ∈ A ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x

Proof

Step Hyp Ref Expression
1 hdmap14lem12.h ⊢ H = LHyp ⁡ K
2 hdmap14lem12.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmap14lem12.v ⊢ V = Base U
4 hdmap14lem12.t ⊢ · ˙ = ⋅ U
5 hdmap14lem12.r ⊢ R = Scalar ⁡ U
6 hdmap14lem12.b ⊢ B = Base R
7 hdmap14lem12.c ⊢ C = LCDual ⁡ K ⁡ W
8 hdmap14lem12.e ⊢ ∙ ˙ = ⋅ C
9 hdmap14lem12.s ⊢ S = HDMap ⁡ K ⁡ W
10 hdmap14lem12.k ⊢ φ → K ∈ HL ∧ W ∈ H
11 hdmap14lem12.f ⊢ φ → F ∈ B
12 hdmap14lem12.p ⊢ P = Scalar ⁡ C
13 hdmap14lem12.a ⊢ A = Base P
14 eqid ⊢ 0 U = 0 U
15 1 2 3 14 10 dvh1dim ⊢ φ → ∃ y ∈ V y ≠ 0 U
16 10 3ad2ant1 ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U → K ∈ HL ∧ W ∈ H
17 3simpc ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U → y ∈ V ∧ y ≠ 0 U
18 eldifsn ⊢ y ∈ V ∖ 0 U ↔ y ∈ V ∧ y ≠ 0 U
19 17 18 sylibr ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U → y ∈ V ∖ 0 U
20 11 3ad2ant1 ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U → F ∈ B
21 1 2 3 4 14 5 6 7 8 12 13 9 16 19 20 hdmap14lem7 ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U → ∃! g ∈ A S ⁡ F · ˙ y = g ∙ ˙ S ⁡ y
22 simpl1 ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U ∧ g ∈ A → φ
23 22 10 syl ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U ∧ g ∈ A → K ∈ HL ∧ W ∈ H
24 22 11 syl ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U ∧ g ∈ A → F ∈ B
25 19 adantr ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U ∧ g ∈ A → y ∈ V ∖ 0 U
26 simpr ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U ∧ g ∈ A → g ∈ A
27 1 2 3 4 5 6 7 8 9 23 24 12 13 14 25 26 hdmap14lem13 ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U ∧ g ∈ A → S ⁡ F · ˙ y = g ∙ ˙ S ⁡ y ↔ ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
28 27 reubidva ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U → ∃! g ∈ A S ⁡ F · ˙ y = g ∙ ˙ S ⁡ y ↔ ∃! g ∈ A ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
29 21 28 mpbid ⊢ φ ∧ y ∈ V ∧ y ≠ 0 U → ∃! g ∈ A ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
30 29 rexlimdv3a ⊢ φ → ∃ y ∈ V y ≠ 0 U → ∃! g ∈ A ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
31 15 30 mpd ⊢ φ → ∃! g ∈ A ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x