Metamath Proof Explorer


Theorem indval2

Description: Alternate value of the indicator function generator. (Contributed by Thierry Arnoux, 2-Feb-2017)

Ref Expression
Assertion indval2 ⊢ O ∈ V ∧ A ⊆ O → 𝟙 O ⁡ A = A × 1 ∪ O ∖ A × 0

Proof

Step Hyp Ref Expression
1 dfmpt3 ⊢ x ∈ O ⟼ if x ∈ A 1 0 = ⋃ x ∈ O x × if x ∈ A 1 0
2 indval ⊢ O ∈ V ∧ A ⊆ O → 𝟙 O ⁡ A = x ∈ O ⟼ if x ∈ A 1 0
3 undif ⊢ A ⊆ O ↔ A ∪ O ∖ A = O
4 3 bilani ⊢ O ∈ V ∧ A ⊆ O → A ∪ O ∖ A = O
5 4 iuneq1d ⊢ O ∈ V ∧ A ⊆ O → ⋃ x ∈ A ∪ O ∖ A x × if x ∈ A 1 0 = ⋃ x ∈ O x × if x ∈ A 1 0
6 1 2 5 3eqtr4a ⊢ O ∈ V ∧ A ⊆ O → 𝟙 O ⁡ A = ⋃ x ∈ A ∪ O ∖ A x × if x ∈ A 1 0
7 iunxun ⊢ ⋃ x ∈ A ∪ O ∖ A x × if x ∈ A 1 0 = ⋃ x ∈ A x × if x ∈ A 1 0 ∪ ⋃ x ∈ O ∖ A x × if x ∈ A 1 0
8 6 7 eqtrdi ⊢ O ∈ V ∧ A ⊆ O → 𝟙 O ⁡ A = ⋃ x ∈ A x × if x ∈ A 1 0 ∪ ⋃ x ∈ O ∖ A x × if x ∈ A 1 0
9 iftrue ⊢ x ∈ A → if x ∈ A 1 0 = 1
10 9 sneqd ⊢ x ∈ A → if x ∈ A 1 0 = 1
11 10 xpeq2d ⊢ x ∈ A → x × if x ∈ A 1 0 = x × 1
12 11 iuneq2i ⊢ ⋃ x ∈ A x × if x ∈ A 1 0 = ⋃ x ∈ A x × 1
13 iunxpconst ⊢ ⋃ x ∈ A x × 1 = A × 1
14 12 13 eqtri ⊢ ⋃ x ∈ A x × if x ∈ A 1 0 = A × 1
15 eldifn ⊢ x ∈ O ∖ A → ¬ x ∈ A
16 iffalse ⊢ ¬ x ∈ A → if x ∈ A 1 0 = 0
17 16 sneqd ⊢ ¬ x ∈ A → if x ∈ A 1 0 = 0
18 15 17 syl ⊢ x ∈ O ∖ A → if x ∈ A 1 0 = 0
19 18 xpeq2d ⊢ x ∈ O ∖ A → x × if x ∈ A 1 0 = x × 0
20 19 iuneq2i ⊢ ⋃ x ∈ O ∖ A x × if x ∈ A 1 0 = ⋃ x ∈ O ∖ A x × 0
21 iunxpconst ⊢ ⋃ x ∈ O ∖ A x × 0 = O ∖ A × 0
22 20 21 eqtri ⊢ ⋃ x ∈ O ∖ A x × if x ∈ A 1 0 = O ∖ A × 0
23 14 22 uneq12i ⊢ ⋃ x ∈ A x × if x ∈ A 1 0 ∪ ⋃ x ∈ O ∖ A x × if x ∈ A 1 0 = A × 1 ∪ O ∖ A × 0
24 8 23 eqtrdi ⊢ O ∈ V ∧ A ⊆ O → 𝟙 O ⁡ A = A × 1 ∪ O ∖ A × 0