Metamath Proof Explorer


Theorem lcfrlem3

Description: Lemma for lcfr . (Contributed by NM, 27-Feb-2015)

Ref Expression
Hypotheses lcfrlem1.v ⊢ V = Base U
lcfrlem1.s ⊢ S = Scalar ⁡ U
lcfrlem1.q ⊢ × ˙ = ⋅ S
lcfrlem1.z ⊢ 0 ˙ = 0 S
lcfrlem1.i ⊢ I = inv r ⁡ S
lcfrlem1.f ⊢ F = LFnl ⁡ U
lcfrlem1.d ⊢ D = LDual ⁡ U
lcfrlem1.t ⊢ · ˙ = ⋅ D
lcfrlem1.m ⊢ - ˙ = - D
lcfrlem1.u ⊢ φ → U ∈ LVec
lcfrlem1.e ⊢ φ → E ∈ F
lcfrlem1.g ⊢ φ → G ∈ F
lcfrlem1.x ⊢ φ → X ∈ V
lcfrlem1.n ⊢ φ → G ⁡ X ≠ 0 ˙
lcfrlem1.h ⊢ H = E - ˙ I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G
lcfrlem2.l ⊢ L = LKer ⁡ U
Assertion lcfrlem3 ⊢ φ → X ∈ L ⁡ H

Proof

Step Hyp Ref Expression
1 lcfrlem1.v ⊢ V = Base U
2 lcfrlem1.s ⊢ S = Scalar ⁡ U
3 lcfrlem1.q ⊢ × ˙ = ⋅ S
4 lcfrlem1.z ⊢ 0 ˙ = 0 S
5 lcfrlem1.i ⊢ I = inv r ⁡ S
6 lcfrlem1.f ⊢ F = LFnl ⁡ U
7 lcfrlem1.d ⊢ D = LDual ⁡ U
8 lcfrlem1.t ⊢ · ˙ = ⋅ D
9 lcfrlem1.m ⊢ - ˙ = - D
10 lcfrlem1.u ⊢ φ → U ∈ LVec
11 lcfrlem1.e ⊢ φ → E ∈ F
12 lcfrlem1.g ⊢ φ → G ∈ F
13 lcfrlem1.x ⊢ φ → X ∈ V
14 lcfrlem1.n ⊢ φ → G ⁡ X ≠ 0 ˙
15 lcfrlem1.h ⊢ H = E - ˙ I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G
16 lcfrlem2.l ⊢ L = LKer ⁡ U
17 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 lcfrlem1 ⊢ φ → H ⁡ X = 0 ˙
18 lveclmod ⊢ U ∈ LVec → U ∈ LMod
19 10 18 syl ⊢ φ → U ∈ LMod
20 eqid ⊢ Base S = Base S
21 2 lmodring ⊢ U ∈ LMod → S ∈ Ring
22 19 21 syl ⊢ φ → S ∈ Ring
23 2 lvecdrng ⊢ U ∈ LVec → S ∈ DivRing
24 10 23 syl ⊢ φ → S ∈ DivRing
25 2 20 1 6 lflcl ⊢ U ∈ LVec ∧ G ∈ F ∧ X ∈ V → G ⁡ X ∈ Base S
26 10 12 13 25 syl3anc ⊢ φ → G ⁡ X ∈ Base S
27 20 4 5 drnginvrcl ⊢ S ∈ DivRing ∧ G ⁡ X ∈ Base S ∧ G ⁡ X ≠ 0 ˙ → I ⁡ G ⁡ X ∈ Base S
28 24 26 14 27 syl3anc ⊢ φ → I ⁡ G ⁡ X ∈ Base S
29 2 20 1 6 lflcl ⊢ U ∈ LVec ∧ E ∈ F ∧ X ∈ V → E ⁡ X ∈ Base S
30 10 11 13 29 syl3anc ⊢ φ → E ⁡ X ∈ Base S
31 20 3 ringcl ⊢ S ∈ Ring ∧ I ⁡ G ⁡ X ∈ Base S ∧ E ⁡ X ∈ Base S → I ⁡ G ⁡ X × ˙ E ⁡ X ∈ Base S
32 22 28 30 31 syl3anc ⊢ φ → I ⁡ G ⁡ X × ˙ E ⁡ X ∈ Base S
33 6 2 20 7 8 19 32 12 ldualvscl ⊢ φ → I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ∈ F
34 6 7 9 19 11 33 ldualvsubcl ⊢ φ → E - ˙ I ⁡ G ⁡ X × ˙ E ⁡ X · ˙ G ∈ F
35 15 34 eqeltrid ⊢ φ → H ∈ F
36 1 2 4 6 16 10 35 13 ellkr2 ⊢ φ → X ∈ L ⁡ H ↔ H ⁡ X = 0 ˙
37 17 36 mpbird ⊢ φ → X ∈ L ⁡ H