Metamath Proof Explorer


Theorem lclkrlem2r

Description: Lemma for lclkr . When B is zero, i.e. when X and Y are colinear, the intersection of the kernels of E and G equal the kernel of G , so the kernels of G and the sum are comparable. (Contributed by NM, 18-Jan-2015)

Ref Expression
Hypotheses lclkrlem2m.v ⊢ V = Base U
lclkrlem2m.t ⊢ · ˙ = ⋅ U
lclkrlem2m.s ⊢ S = Scalar ⁡ U
lclkrlem2m.q ⊢ × ˙ = ⋅ S
lclkrlem2m.z ⊢ 0 ˙ = 0 S
lclkrlem2m.i ⊢ I = inv r ⁡ S
lclkrlem2m.m ⊢ - ˙ = - U
lclkrlem2m.f ⊢ F = LFnl ⁡ U
lclkrlem2m.d ⊢ D = LDual ⁡ U
lclkrlem2m.p ⊢ + ˙ = + D
lclkrlem2m.x ⊢ φ → X ∈ V
lclkrlem2m.y ⊢ φ → Y ∈ V
lclkrlem2m.e ⊢ φ → E ∈ F
lclkrlem2m.g ⊢ φ → G ∈ F
lclkrlem2n.n ⊢ N = LSpan ⁡ U
lclkrlem2n.l ⊢ L = LKer ⁡ U
lclkrlem2o.h ⊢ H = LHyp ⁡ K
lclkrlem2o.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lclkrlem2o.u ⊢ U = DVecH ⁡ K ⁡ W
lclkrlem2o.a ⊢ ⊕ ˙ = LSSum ⁡ U
lclkrlem2o.k ⊢ φ → K ∈ HL ∧ W ∈ H
lclkrlem2q.le ⊢ φ → L ⁡ E = ⊥ ˙ ⁡ X
lclkrlem2q.lg ⊢ φ → L ⁡ G = ⊥ ˙ ⁡ Y
lclkrlem2q.b ⊢ B = X - ˙ E + ˙ G ⁡ X × ˙ I ⁡ E + ˙ G ⁡ Y · ˙ Y
lclkrlem2q.n ⊢ φ → E + ˙ G ⁡ Y ≠ 0 ˙
lclkrlem2r.bn ⊢ φ → B = 0 U
Assertion lclkrlem2r ⊢ φ → L ⁡ G ⊆ L ⁡ E + ˙ G

Proof

Step Hyp Ref Expression
1 lclkrlem2m.v ⊢ V = Base U
2 lclkrlem2m.t ⊢ · ˙ = ⋅ U
3 lclkrlem2m.s ⊢ S = Scalar ⁡ U
4 lclkrlem2m.q ⊢ × ˙ = ⋅ S
5 lclkrlem2m.z ⊢ 0 ˙ = 0 S
6 lclkrlem2m.i ⊢ I = inv r ⁡ S
7 lclkrlem2m.m ⊢ - ˙ = - U
8 lclkrlem2m.f ⊢ F = LFnl ⁡ U
9 lclkrlem2m.d ⊢ D = LDual ⁡ U
10 lclkrlem2m.p ⊢ + ˙ = + D
11 lclkrlem2m.x ⊢ φ → X ∈ V
12 lclkrlem2m.y ⊢ φ → Y ∈ V
13 lclkrlem2m.e ⊢ φ → E ∈ F
14 lclkrlem2m.g ⊢ φ → G ∈ F
15 lclkrlem2n.n ⊢ N = LSpan ⁡ U
16 lclkrlem2n.l ⊢ L = LKer ⁡ U
17 lclkrlem2o.h ⊢ H = LHyp ⁡ K
18 lclkrlem2o.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
19 lclkrlem2o.u ⊢ U = DVecH ⁡ K ⁡ W
20 lclkrlem2o.a ⊢ ⊕ ˙ = LSSum ⁡ U
21 lclkrlem2o.k ⊢ φ → K ∈ HL ∧ W ∈ H
22 lclkrlem2q.le ⊢ φ → L ⁡ E = ⊥ ˙ ⁡ X
23 lclkrlem2q.lg ⊢ φ → L ⁡ G = ⊥ ˙ ⁡ Y
24 lclkrlem2q.b ⊢ B = X - ˙ E + ˙ G ⁡ X × ˙ I ⁡ E + ˙ G ⁡ Y · ˙ Y
25 lclkrlem2q.n ⊢ φ → E + ˙ G ⁡ Y ≠ 0 ˙
26 lclkrlem2r.bn ⊢ φ → B = 0 U
27 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 24 25 26 lclkrlem2p ⊢ φ → ⊥ ˙ ⁡ Y ⊆ ⊥ ˙ ⁡ X
28 27 23 22 3sstr4d ⊢ φ → L ⁡ G ⊆ L ⁡ E
29 sseqin2 ⊢ L ⁡ G ⊆ L ⁡ E ↔ L ⁡ E ∩ L ⁡ G = L ⁡ G
30 28 29 sylib ⊢ φ → L ⁡ E ∩ L ⁡ G = L ⁡ G
31 17 19 21 dvhlmod ⊢ φ → U ∈ LMod
32 8 16 9 10 31 13 14 lkrin ⊢ φ → L ⁡ E ∩ L ⁡ G ⊆ L ⁡ E + ˙ G
33 30 32 eqsstrrd ⊢ φ → L ⁡ G ⊆ L ⁡ E + ˙ G