Metamath Proof Explorer


Theorem mbfmcst

Description: A constant function is measurable. Cf. mbfconst . (Contributed by Thierry Arnoux, 26-Jan-2017)

Ref Expression
Hypotheses mbfmcst.1 ⊢ φ → S ∈ ⋃ ran ⁡ sigAlgebra
mbfmcst.2 ⊢ φ → T ∈ ⋃ ran ⁡ sigAlgebra
mbfmcst.3 ⊢ φ → F = x ∈ ⋃ S ⟼ A
mbfmcst.4 ⊢ φ → A ∈ ⋃ T
Assertion mbfmcst ⊢ φ → F ∈ S MblFn μ T

Proof

Step Hyp Ref Expression
1 mbfmcst.1 ⊢ φ → S ∈ ⋃ ran ⁡ sigAlgebra
2 mbfmcst.2 ⊢ φ → T ∈ ⋃ ran ⁡ sigAlgebra
3 mbfmcst.3 ⊢ φ → F = x ∈ ⋃ S ⟼ A
4 mbfmcst.4 ⊢ φ → A ∈ ⋃ T
5 4 adantr ⊢ φ ∧ x ∈ ⋃ S → A ∈ ⋃ T
6 3 5 fmpt3d ⊢ φ → F : ⋃ S ⟶ ⋃ T
7 unielsiga ⊢ T ∈ ⋃ ran ⁡ sigAlgebra → ⋃ T ∈ T
8 2 7 syl ⊢ φ → ⋃ T ∈ T
9 unielsiga ⊢ S ∈ ⋃ ran ⁡ sigAlgebra → ⋃ S ∈ S
10 1 9 syl ⊢ φ → ⋃ S ∈ S
11 8 10 elmapd ⊢ φ → F ∈ ⋃ T ⋃ S ↔ F : ⋃ S ⟶ ⋃ T
12 6 11 mpbird ⊢ φ → F ∈ ⋃ T ⋃ S
13 fconstmpt ⊢ ⋃ S × A = x ∈ ⋃ S ⟼ A
14 13 cnveqi ⊢ ⋃ S × A -1 = x ∈ ⋃ S ⟼ A -1
15 cnvxp ⊢ ⋃ S × A -1 = A × ⋃ S
16 14 15 eqtr3i ⊢ x ∈ ⋃ S ⟼ A -1 = A × ⋃ S
17 16 imaeq1i ⊢ x ∈ ⋃ S ⟼ A -1 y = A × ⋃ S y
18 df-ima ⊢ A × ⋃ S y = ran ⁡ A × ⋃ S ↾ y
19 df-rn ⊢ ran ⁡ A × ⋃ S ↾ y = dom ⁡ A × ⋃ S ↾ y -1
20 17 18 19 3eqtri ⊢ x ∈ ⋃ S ⟼ A -1 y = dom ⁡ A × ⋃ S ↾ y -1
21 xpres ⊢ A × ⋃ S ↾ y = A ∩ y × ⋃ S
22 21 cnveqi ⊢ A × ⋃ S ↾ y -1 = A ∩ y × ⋃ S -1
23 22 dmeqi ⊢ dom ⁡ A × ⋃ S ↾ y -1 = dom ⁡ A ∩ y × ⋃ S -1
24 cnvxp ⊢ A ∩ y × ⋃ S -1 = ⋃ S × A ∩ y
25 24 dmeqi ⊢ dom ⁡ A ∩ y × ⋃ S -1 = dom ⁡ ⋃ S × A ∩ y
26 20 23 25 3eqtri ⊢ x ∈ ⋃ S ⟼ A -1 y = dom ⁡ ⋃ S × A ∩ y
27 xpeq2 ⊢ A ∩ y = ∅ → ⋃ S × A ∩ y = ⋃ S × ∅
28 xp0 ⊢ ⋃ S × ∅ = ∅
29 27 28 eqtrdi ⊢ A ∩ y = ∅ → ⋃ S × A ∩ y = ∅
30 29 dmeqd ⊢ A ∩ y = ∅ → dom ⁡ ⋃ S × A ∩ y = dom ⁡ ∅
31 dm0 ⊢ dom ⁡ ∅ = ∅
32 30 31 eqtrdi ⊢ A ∩ y = ∅ → dom ⁡ ⋃ S × A ∩ y = ∅
33 32 adantl ⊢ φ ∧ A ∩ y = ∅ → dom ⁡ ⋃ S × A ∩ y = ∅
34 0elsiga ⊢ S ∈ ⋃ ran ⁡ sigAlgebra → ∅ ∈ S
35 1 34 syl ⊢ φ → ∅ ∈ S
36 35 adantr ⊢ φ ∧ A ∩ y = ∅ → ∅ ∈ S
37 33 36 eqeltrd ⊢ φ ∧ A ∩ y = ∅ → dom ⁡ ⋃ S × A ∩ y ∈ S
38 26 37 eqeltrid ⊢ φ ∧ A ∩ y = ∅ → x ∈ ⋃ S ⟼ A -1 y ∈ S
39 dmxp ⊢ A ∩ y ≠ ∅ → dom ⁡ ⋃ S × A ∩ y = ⋃ S
40 39 adantl ⊢ φ ∧ A ∩ y ≠ ∅ → dom ⁡ ⋃ S × A ∩ y = ⋃ S
41 10 adantr ⊢ φ ∧ A ∩ y ≠ ∅ → ⋃ S ∈ S
42 40 41 eqeltrd ⊢ φ ∧ A ∩ y ≠ ∅ → dom ⁡ ⋃ S × A ∩ y ∈ S
43 26 42 eqeltrid ⊢ φ ∧ A ∩ y ≠ ∅ → x ∈ ⋃ S ⟼ A -1 y ∈ S
44 38 43 pm2.61dane ⊢ φ → x ∈ ⋃ S ⟼ A -1 y ∈ S
45 44 ralrimivw ⊢ φ → ∀ y ∈ T x ∈ ⋃ S ⟼ A -1 y ∈ S
46 3 cnveqd ⊢ φ → F -1 = x ∈ ⋃ S ⟼ A -1
47 46 imaeq1d ⊢ φ → F -1 y = x ∈ ⋃ S ⟼ A -1 y
48 47 eleq1d ⊢ φ → F -1 y ∈ S ↔ x ∈ ⋃ S ⟼ A -1 y ∈ S
49 48 ralbidv ⊢ φ → ∀ y ∈ T F -1 y ∈ S ↔ ∀ y ∈ T x ∈ ⋃ S ⟼ A -1 y ∈ S
50 45 49 mpbird ⊢ φ → ∀ y ∈ T F -1 y ∈ S
51 1 2 ismbfm ⊢ φ → F ∈ S MblFn μ T ↔ F ∈ ⋃ T ⋃ S ∧ ∀ y ∈ T F -1 y ∈ S
52 12 50 51 mpbir2and ⊢ φ → F ∈ S MblFn μ T