Metamath Proof Explorer


Theorem ismbfm

Description: The predicate " F is a measurable function from the measurable space S to the measurable space T ". Cf. ismbf . (Contributed by Thierry Arnoux, 23-Jan-2017)

Ref Expression
Hypotheses ismbfm.1 ⊢ φ → S ∈ ⋃ ran ⁡ sigAlgebra
ismbfm.2 ⊢ φ → T ∈ ⋃ ran ⁡ sigAlgebra
Assertion ismbfm ⊢ φ → F ∈ S MblFn μ T ↔ F ∈ ⋃ T ⋃ S ∧ ∀ x ∈ T F -1 x ∈ S

Proof

Step Hyp Ref Expression
1 ismbfm.1 ⊢ φ → S ∈ ⋃ ran ⁡ sigAlgebra
2 ismbfm.2 ⊢ φ → T ∈ ⋃ ran ⁡ sigAlgebra
3 unieq ⊢ s = S → ⋃ s = ⋃ S
4 3 oveq2d ⊢ s = S → ⋃ t ⋃ s = ⋃ t ⋃ S
5 eleq2 ⊢ s = S → f -1 x ∈ s ↔ f -1 x ∈ S
6 5 ralbidv ⊢ s = S → ∀ x ∈ t f -1 x ∈ s ↔ ∀ x ∈ t f -1 x ∈ S
7 4 6 rabeqbidv ⊢ s = S → f ∈ ⋃ t ⋃ s | ∀ x ∈ t f -1 x ∈ s = f ∈ ⋃ t ⋃ S | ∀ x ∈ t f -1 x ∈ S
8 unieq ⊢ t = T → ⋃ t = ⋃ T
9 8 oveq1d ⊢ t = T → ⋃ t ⋃ S = ⋃ T ⋃ S
10 raleq ⊢ t = T → ∀ x ∈ t f -1 x ∈ S ↔ ∀ x ∈ T f -1 x ∈ S
11 9 10 rabeqbidv ⊢ t = T → f ∈ ⋃ t ⋃ S | ∀ x ∈ t f -1 x ∈ S = f ∈ ⋃ T ⋃ S | ∀ x ∈ T f -1 x ∈ S
12 df-mbfm ⊢ MblFn μ = s ∈ ⋃ ran ⁡ sigAlgebra , t ∈ ⋃ ran ⁡ sigAlgebra ⟼ f ∈ ⋃ t ⋃ s | ∀ x ∈ t f -1 x ∈ s
13 ovex ⊢ ⋃ T ⋃ S ∈ V
14 13 rabex ⊢ f ∈ ⋃ T ⋃ S | ∀ x ∈ T f -1 x ∈ S ∈ V
15 7 11 12 14 ovmpo ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → S MblFn μ T = f ∈ ⋃ T ⋃ S | ∀ x ∈ T f -1 x ∈ S
16 1 2 15 syl2anc ⊢ φ → S MblFn μ T = f ∈ ⋃ T ⋃ S | ∀ x ∈ T f -1 x ∈ S
17 16 eleq2d ⊢ φ → F ∈ S MblFn μ T ↔ F ∈ f ∈ ⋃ T ⋃ S | ∀ x ∈ T f -1 x ∈ S
18 cnveq ⊢ f = F → f -1 = F -1
19 18 imaeq1d ⊢ f = F → f -1 x = F -1 x
20 19 eleq1d ⊢ f = F → f -1 x ∈ S ↔ F -1 x ∈ S
21 20 ralbidv ⊢ f = F → ∀ x ∈ T f -1 x ∈ S ↔ ∀ x ∈ T F -1 x ∈ S
22 21 elrab ⊢ F ∈ f ∈ ⋃ T ⋃ S | ∀ x ∈ T f -1 x ∈ S ↔ F ∈ ⋃ T ⋃ S ∧ ∀ x ∈ T F -1 x ∈ S
23 17 22 bitrdi ⊢ φ → F ∈ S MblFn μ T ↔ F ∈ ⋃ T ⋃ S ∧ ∀ x ∈ T F -1 x ∈ S