Metamath Proof Explorer


Theorem meadif

Description: The measure of the difference of two sets. (Contributed by Glauco Siliprandi, 8-Apr-2021)

Ref Expression
Hypotheses meadif.m ⊢ φ → M ∈ Meas
meadif.a ⊢ φ → A ∈ dom ⁡ M
meadif.r ⊢ φ → M ⁡ A ∈ ℝ
meadif.b ⊢ φ → B ∈ dom ⁡ M
meadif.s ⊢ φ → B ⊆ A
Assertion meadif ⊢ φ → M ⁡ A ∖ B = M ⁡ A − M ⁡ B

Proof

Step Hyp Ref Expression
1 meadif.m ⊢ φ → M ∈ Meas
2 meadif.a ⊢ φ → A ∈ dom ⁡ M
3 meadif.r ⊢ φ → M ⁡ A ∈ ℝ
4 meadif.b ⊢ φ → B ∈ dom ⁡ M
5 meadif.s ⊢ φ → B ⊆ A
6 undif ⊢ B ⊆ A ↔ B ∪ A ∖ B = A
7 5 6 sylib ⊢ φ → B ∪ A ∖ B = A
8 7 eqcomd ⊢ φ → A = B ∪ A ∖ B
9 8 fveq2d ⊢ φ → M ⁡ A = M ⁡ B ∪ A ∖ B
10 eqid ⊢ dom ⁡ M = dom ⁡ M
11 1 10 dmmeasal ⊢ φ → dom ⁡ M ∈ SAlg
12 saldifcl2 ⊢ dom ⁡ M ∈ SAlg ∧ A ∈ dom ⁡ M ∧ B ∈ dom ⁡ M → A ∖ B ∈ dom ⁡ M
13 11 2 4 12 syl3anc ⊢ φ → A ∖ B ∈ dom ⁡ M
14 disjdif ⊢ B ∩ A ∖ B = ∅
15 14 a1i ⊢ φ → B ∩ A ∖ B = ∅
16 1 2 3 5 4 meassre ⊢ φ → M ⁡ B ∈ ℝ
17 difssd ⊢ φ → A ∖ B ⊆ A
18 1 2 3 17 13 meassre ⊢ φ → M ⁡ A ∖ B ∈ ℝ
19 1 10 4 13 15 16 18 meadjunre ⊢ φ → M ⁡ B ∪ A ∖ B = M ⁡ B + M ⁡ A ∖ B
20 9 19 eqtr2d ⊢ φ → M ⁡ B + M ⁡ A ∖ B = M ⁡ A
21 16 recnd ⊢ φ → M ⁡ B ∈ ℂ
22 18 recnd ⊢ φ → M ⁡ A ∖ B ∈ ℂ
23 3 recnd ⊢ φ → M ⁡ A ∈ ℂ
24 21 22 23 addrsub ⊢ φ → M ⁡ B + M ⁡ A ∖ B = M ⁡ A ↔ M ⁡ A ∖ B = M ⁡ A − M ⁡ B
25 20 24 mpbid ⊢ φ → M ⁡ A ∖ B = M ⁡ A − M ⁡ B