Metamath Proof Explorer


Theorem prodrblem

Description: Lemma for prodrb . (Contributed by Scott Fenton, 4-Dec-2017)

Ref Expression
Hypotheses prodmo.1 ⊢ F = k ∈ ℤ ⟼ if k ∈ A B 1
prodmo.2 ⊢ φ ∧ k ∈ A → B ∈ ℂ
prodrb.3 ⊢ φ → N ∈ ℤ ≥ M
Assertion prodrblem ⊢ φ ∧ A ⊆ ℤ ≥ N → seq M × F ↾ ℤ ≥ N = seq N × F

Proof

Step Hyp Ref Expression
1 prodmo.1 ⊢ F = k ∈ ℤ ⟼ if k ∈ A B 1
2 prodmo.2 ⊢ φ ∧ k ∈ A → B ∈ ℂ
3 prodrb.3 ⊢ φ → N ∈ ℤ ≥ M
4 mullid ⊢ n ∈ ℂ → 1 ⁢ n = n
5 4 adantl ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ ℂ → 1 ⁢ n = n
6 1cnd ⊢ φ ∧ A ⊆ ℤ ≥ N → 1 ∈ ℂ
7 3 adantr ⊢ φ ∧ A ⊆ ℤ ≥ N → N ∈ ℤ ≥ M
8 iftrue ⊢ k ∈ A → if k ∈ A B 1 = B
9 8 adantl ⊢ φ ∧ k ∈ ℤ ∧ k ∈ A → if k ∈ A B 1 = B
10 2 adantlr ⊢ φ ∧ k ∈ ℤ ∧ k ∈ A → B ∈ ℂ
11 9 10 eqeltrd ⊢ φ ∧ k ∈ ℤ ∧ k ∈ A → if k ∈ A B 1 ∈ ℂ
12 11 ex ⊢ φ ∧ k ∈ ℤ → k ∈ A → if k ∈ A B 1 ∈ ℂ
13 iffalse ⊢ ¬ k ∈ A → if k ∈ A B 1 = 1
14 ax-1cn ⊢ 1 ∈ ℂ
15 13 14 eqeltrdi ⊢ ¬ k ∈ A → if k ∈ A B 1 ∈ ℂ
16 12 15 pm2.61d1 ⊢ φ ∧ k ∈ ℤ → if k ∈ A B 1 ∈ ℂ
17 16 1 fmptd ⊢ φ → F : ℤ ⟶ ℂ
18 uzssz ⊢ ℤ ≥ M ⊆ ℤ
19 18 3 sselid ⊢ φ → N ∈ ℤ
20 17 19 ffvelcdmd ⊢ φ → F ⁡ N ∈ ℂ
21 20 adantr ⊢ φ ∧ A ⊆ ℤ ≥ N → F ⁡ N ∈ ℂ
22 elfzelz ⊢ n ∈ M … N − 1 → n ∈ ℤ
23 22 adantl ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → n ∈ ℤ
24 simplr ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → A ⊆ ℤ ≥ N
25 19 zcnd ⊢ φ → N ∈ ℂ
26 25 adantr ⊢ φ ∧ A ⊆ ℤ ≥ N → N ∈ ℂ
27 26 adantr ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → N ∈ ℂ
28 1cnd ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → 1 ∈ ℂ
29 27 28 npcand ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → N - 1 + 1 = N
30 29 fveq2d ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → ℤ ≥ N - 1 + 1 = ℤ ≥ N
31 24 30 sseqtrrd ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → A ⊆ ℤ ≥ N - 1 + 1
32 fznuz ⊢ n ∈ M … N − 1 → ¬ n ∈ ℤ ≥ N - 1 + 1
33 32 adantl ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → ¬ n ∈ ℤ ≥ N - 1 + 1
34 31 33 ssneldd ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → ¬ n ∈ A
35 23 34 eldifd ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → n ∈ ℤ ∖ A
36 fveqeq2 ⊢ k = n → F ⁡ k = 1 ↔ F ⁡ n = 1
37 eldifi ⊢ k ∈ ℤ ∖ A → k ∈ ℤ
38 eldifn ⊢ k ∈ ℤ ∖ A → ¬ k ∈ A
39 38 13 syl ⊢ k ∈ ℤ ∖ A → if k ∈ A B 1 = 1
40 39 14 eqeltrdi ⊢ k ∈ ℤ ∖ A → if k ∈ A B 1 ∈ ℂ
41 1 fvmpt2 ⊢ k ∈ ℤ ∧ if k ∈ A B 1 ∈ ℂ → F ⁡ k = if k ∈ A B 1
42 37 40 41 syl2anc ⊢ k ∈ ℤ ∖ A → F ⁡ k = if k ∈ A B 1
43 42 39 eqtrd ⊢ k ∈ ℤ ∖ A → F ⁡ k = 1
44 36 43 vtoclga ⊢ n ∈ ℤ ∖ A → F ⁡ n = 1
45 35 44 syl ⊢ φ ∧ A ⊆ ℤ ≥ N ∧ n ∈ M … N − 1 → F ⁡ n = 1
46 5 6 7 21 45 seqid ⊢ φ ∧ A ⊆ ℤ ≥ N → seq M × F ↾ ℤ ≥ N = seq N × F