Metamath Proof Explorer


Theorem safesnsupfidom1o

Description: If B is a finite subset of ordered class A , we can safely create a small subset with the same largest element and upper bound, if any. (Contributed by RP, 1-Sep-2024)

Ref Expression
Hypotheses safesnsupfidom1o.small ⊢ φ → O = ∅ ∨ O = 1 𝑜
safesnsupfidom1o.finite ⊢ φ → B ∈ Fin
Assertion safesnsupfidom1o ⊢ φ → if O ≺ B sup B A R B ≼ 1 𝑜

Proof

Step Hyp Ref Expression
1 safesnsupfidom1o.small ⊢ φ → O = ∅ ∨ O = 1 𝑜
2 safesnsupfidom1o.finite ⊢ φ → B ∈ Fin
3 iftrue ⊢ O ≺ B → if O ≺ B sup B A R B = sup B A R
4 3 adantl ⊢ φ ∧ O ≺ B → if O ≺ B sup B A R B = sup B A R
5 ensn1g ⊢ sup B A R ∈ V → sup B A R ≈ 1 𝑜
6 1on ⊢ 1 𝑜 ∈ On
7 domrefg ⊢ 1 𝑜 ∈ On → 1 𝑜 ≼ 1 𝑜
8 6 7 ax-mp ⊢ 1 𝑜 ≼ 1 𝑜
9 endomtr ⊢ sup B A R ≈ 1 𝑜 ∧ 1 𝑜 ≼ 1 𝑜 → sup B A R ≼ 1 𝑜
10 5 8 9 sylancl ⊢ sup B A R ∈ V → sup B A R ≼ 1 𝑜
11 snprc ⊢ ¬ sup B A R ∈ V ↔ sup B A R = ∅
12 snex ⊢ sup B A R ∈ V
13 eqeng ⊢ sup B A R ∈ V → sup B A R = ∅ → sup B A R ≈ ∅
14 12 13 ax-mp ⊢ sup B A R = ∅ → sup B A R ≈ ∅
15 11 14 sylbi ⊢ ¬ sup B A R ∈ V → sup B A R ≈ ∅
16 0domg ⊢ 1 𝑜 ∈ On → ∅ ≼ 1 𝑜
17 6 16 ax-mp ⊢ ∅ ≼ 1 𝑜
18 endomtr ⊢ sup B A R ≈ ∅ ∧ ∅ ≼ 1 𝑜 → sup B A R ≼ 1 𝑜
19 15 17 18 sylancl ⊢ ¬ sup B A R ∈ V → sup B A R ≼ 1 𝑜
20 10 19 pm2.61i ⊢ sup B A R ≼ 1 𝑜
21 4 20 eqbrtrdi ⊢ φ ∧ O ≺ B → if O ≺ B sup B A R B ≼ 1 𝑜
22 iffalse ⊢ ¬ O ≺ B → if O ≺ B sup B A R B = B
23 22 adantl ⊢ φ ∧ ¬ O ≺ B → if O ≺ B sup B A R B = B
24 0elon ⊢ ∅ ∈ On
25 eleq1 ⊢ O = ∅ → O ∈ On ↔ ∅ ∈ On
26 24 25 mpbiri ⊢ O = ∅ → O ∈ On
27 eleq1 ⊢ O = 1 𝑜 → O ∈ On ↔ 1 𝑜 ∈ On
28 6 27 mpbiri ⊢ O = 1 𝑜 → O ∈ On
29 26 28 jaoi ⊢ O = ∅ ∨ O = 1 𝑜 → O ∈ On
30 fidomtri ⊢ B ∈ Fin ∧ O ∈ On → B ≼ O ↔ ¬ O ≺ B
31 29 30 sylan2 ⊢ B ∈ Fin ∧ O = ∅ ∨ O = 1 𝑜 → B ≼ O ↔ ¬ O ≺ B
32 breq2 ⊢ O = ∅ → B ≼ O ↔ B ≼ ∅
33 domtr ⊢ B ≼ ∅ ∧ ∅ ≼ 1 𝑜 → B ≼ 1 𝑜
34 17 33 mpan2 ⊢ B ≼ ∅ → B ≼ 1 𝑜
35 32 34 biimtrdi ⊢ O = ∅ → B ≼ O → B ≼ 1 𝑜
36 breq2 ⊢ O = 1 𝑜 → B ≼ O ↔ B ≼ 1 𝑜
37 36 biimpd ⊢ O = 1 𝑜 → B ≼ O → B ≼ 1 𝑜
38 35 37 jaoi ⊢ O = ∅ ∨ O = 1 𝑜 → B ≼ O → B ≼ 1 𝑜
39 38 adantl ⊢ B ∈ Fin ∧ O = ∅ ∨ O = 1 𝑜 → B ≼ O → B ≼ 1 𝑜
40 31 39 sylbird ⊢ B ∈ Fin ∧ O = ∅ ∨ O = 1 𝑜 → ¬ O ≺ B → B ≼ 1 𝑜
41 2 1 40 syl2anc ⊢ φ → ¬ O ≺ B → B ≼ 1 𝑜
42 41 imp ⊢ φ ∧ ¬ O ≺ B → B ≼ 1 𝑜
43 23 42 eqbrtrd ⊢ φ ∧ ¬ O ≺ B → if O ≺ B sup B A R B ≼ 1 𝑜
44 21 43 pm2.61dan ⊢ φ → if O ≺ B sup B A R B ≼ 1 𝑜