Metamath Proof Explorer


Theorem tngngpd

Description: Derive the axioms for a normed group from the axioms for a metric space. (Contributed by Mario Carneiro, 4-Oct-2015)

Ref Expression
Hypotheses tngngp.t ⊢ T = G toNrmGrp N
tngngp.x ⊢ X = Base G
tngngp.m ⊢ - ˙ = - G
tngngp.z ⊢ 0 ˙ = 0 G
tngngpd.1 ⊢ φ → G ∈ Grp
tngngpd.2 ⊢ φ → N : X ⟶ ℝ
tngngpd.3 ⊢ φ ∧ x ∈ X → N ⁡ x = 0 ↔ x = 0 ˙
tngngpd.4 ⊢ φ ∧ x ∈ X ∧ y ∈ X → N ⁡ x - ˙ y ≤ N ⁡ x + N ⁡ y
Assertion tngngpd ⊢ φ → T ∈ NrmGrp

Proof

Step Hyp Ref Expression
1 tngngp.t ⊢ T = G toNrmGrp N
2 tngngp.x ⊢ X = Base G
3 tngngp.m ⊢ - ˙ = - G
4 tngngp.z ⊢ 0 ˙ = 0 G
5 tngngpd.1 ⊢ φ → G ∈ Grp
6 tngngpd.2 ⊢ φ → N : X ⟶ ℝ
7 tngngpd.3 ⊢ φ ∧ x ∈ X → N ⁡ x = 0 ↔ x = 0 ˙
8 tngngpd.4 ⊢ φ ∧ x ∈ X ∧ y ∈ X → N ⁡ x - ˙ y ≤ N ⁡ x + N ⁡ y
9 2 fvexi ⊢ X ∈ V
10 reex ⊢ ℝ ∈ V
11 fex2 ⊢ N : X ⟶ ℝ ∧ X ∈ V ∧ ℝ ∈ V → N ∈ V
12 9 10 11 mp3an23 ⊢ N : X ⟶ ℝ → N ∈ V
13 1 3 tngds ⊢ N ∈ V → N ∘ - ˙ = dist ⁡ T
14 6 12 13 3syl ⊢ φ → N ∘ - ˙ = dist ⁡ T
15 2 3 4 5 6 7 8 nrmmetd ⊢ φ → N ∘ - ˙ ∈ Met ⁡ X
16 14 15 eqeltrrd ⊢ φ → dist ⁡ T ∈ Met ⁡ X
17 eqid ⊢ dist ⁡ T = dist ⁡ T
18 1 2 17 tngngp2 ⊢ N : X ⟶ ℝ → T ∈ NrmGrp ↔ G ∈ Grp ∧ dist ⁡ T ∈ Met ⁡ X
19 6 18 syl ⊢ φ → T ∈ NrmGrp ↔ G ∈ Grp ∧ dist ⁡ T ∈ Met ⁡ X
20 5 16 19 mpbir2and ⊢ φ → T ∈ NrmGrp