Metamath Proof Explorer


Theorem dflringlem3

Description: Lemma for dflring3 . In a commutative local ring R , the set ( B \ U ) of non-units is a maximal ideal. (Contributed by Thierry Arnoux, 2-Jun-2026)

Ref Expression
Hypotheses dflringlem2.b ⊢ B = Base R
dflringlem2.u ⊢ U = Unit ⁡ R
dflringlem2.1 ⊢ φ → R ∈ CRing
dflringlem2.2 ⊢ φ → R ∈ LRing
Assertion dflringlem3 ⊢ φ → B ∖ U ∈ MaxIdeal ⁡ R

Proof

Step Hyp Ref Expression
1 dflringlem2.b ⊢ B = Base R
2 dflringlem2.u ⊢ U = Unit ⁡ R
3 dflringlem2.1 ⊢ φ → R ∈ CRing
4 dflringlem2.2 ⊢ φ → R ∈ LRing
5 crngring ⊢ R ∈ CRing → R ∈ Ring
6 3 5 syl ⊢ φ → R ∈ Ring
7 1 2 3 4 dflringlem2 ⊢ φ → B ∖ U ∈ LIdeal ⁡ R
8 eqid ⊢ 1 R = 1 R
9 1 8 5 ringidcld ⊢ R ∈ CRing → 1 R ∈ B
10 3 9 syl ⊢ φ → 1 R ∈ B
11 2 8 1unit ⊢ R ∈ Ring → 1 R ∈ U
12 6 11 syl ⊢ φ → 1 R ∈ U
13 elndif ⊢ 1 R ∈ U → ¬ 1 R ∈ B ∖ U
14 12 13 syl ⊢ φ → ¬ 1 R ∈ B ∖ U
15 nelne1 ⊢ 1 R ∈ B ∧ ¬ 1 R ∈ B ∖ U → B ≠ B ∖ U
16 10 14 15 syl2anc ⊢ φ → B ≠ B ∖ U
17 16 necomd ⊢ φ → B ∖ U ≠ B
18 eqid ⊢ LIdeal ⁡ R = LIdeal ⁡ R
19 1 18 lidlss ⊢ j ∈ LIdeal ⁡ R → j ⊆ B
20 19 ad3antlr ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → j ⊆ B
21 ssdif0 ⊢ j ⊆ B ↔ j ∖ B = ∅
22 20 21 sylib ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → j ∖ B = ∅
23 22 uneq1d ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → j ∖ B ∪ j ∩ U = ∅ ∪ j ∩ U
24 0un ⊢ ∅ ∪ j ∩ U = j ∩ U
25 23 24 eqtr2di ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → j ∩ U = j ∖ B ∪ j ∩ U
26 simplr ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → B ∖ U ⊆ j
27 neqne ⊢ ¬ j = B ∖ U → j ≠ B ∖ U
28 27 adantl ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → j ≠ B ∖ U
29 28 necomd ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → B ∖ U ≠ j
30 difdif2 ⊢ j ∖ B ∖ U = j ∖ B ∪ j ∩ U
31 pssdifn0 ⊢ B ∖ U ⊆ j ∧ B ∖ U ≠ j → j ∖ B ∖ U ≠ ∅
32 30 31 eqnetrrid ⊢ B ∖ U ⊆ j ∧ B ∖ U ≠ j → j ∖ B ∪ j ∩ U ≠ ∅
33 26 29 32 syl2anc ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → j ∖ B ∪ j ∩ U ≠ ∅
34 25 33 eqnetrd ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → j ∩ U ≠ ∅
35 simpr ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U ∧ x ∈ j ∩ U → x ∈ j ∩ U
36 35 elin2d ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U ∧ x ∈ j ∩ U → x ∈ U
37 35 elin1d ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U ∧ x ∈ j ∩ U → x ∈ j
38 6 ad4antr ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U ∧ x ∈ j ∩ U → R ∈ Ring
39 simp-4r ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U ∧ x ∈ j ∩ U → j ∈ LIdeal ⁡ R
40 1 2 36 37 38 39 lidlunitel ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U ∧ x ∈ j ∩ U → j = B
41 34 40 n0limd ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j ∧ ¬ j = B ∖ U → j = B
42 41 ex ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j → ¬ j = B ∖ U → j = B
43 42 orrd ⊢ φ ∧ j ∈ LIdeal ⁡ R ∧ B ∖ U ⊆ j → j = B ∖ U ∨ j = B
44 43 ex ⊢ φ ∧ j ∈ LIdeal ⁡ R → B ∖ U ⊆ j → j = B ∖ U ∨ j = B
45 44 ralrimiva ⊢ φ → ∀ j ∈ LIdeal ⁡ R B ∖ U ⊆ j → j = B ∖ U ∨ j = B
46 1 ismxidl ⊢ R ∈ Ring → B ∖ U ∈ MaxIdeal ⁡ R ↔ B ∖ U ∈ LIdeal ⁡ R ∧ B ∖ U ≠ B ∧ ∀ j ∈ LIdeal ⁡ R B ∖ U ⊆ j → j = B ∖ U ∨ j = B
47 46 biimpar ⊢ R ∈ Ring ∧ B ∖ U ∈ LIdeal ⁡ R ∧ B ∖ U ≠ B ∧ ∀ j ∈ LIdeal ⁡ R B ∖ U ⊆ j → j = B ∖ U ∨ j = B → B ∖ U ∈ MaxIdeal ⁡ R
48 6 7 17 45 47 syl13anc ⊢ φ → B ∖ U ∈ MaxIdeal ⁡ R