Metamath Proof Explorer


Theorem dihvalrel

Description: The value of isomorphism H is a relation. (Contributed by NM, 9-Mar-2014)

Ref Expression
Hypotheses dihvalrel.h ⊢ H = LHyp ⁡ K
dihvalrel.i ⊢ I = DIsoH ⁡ K ⁡ W
Assertion dihvalrel ⊢ K ∈ HL ∧ W ∈ H → Rel ⁡ I ⁡ X

Proof

Step Hyp Ref Expression
1 dihvalrel.h ⊢ H = LHyp ⁡ K
2 dihvalrel.i ⊢ I = DIsoH ⁡ K ⁡ W
3 eqid ⊢ Base K = Base K
4 3 1 2 dihdm ⊢ K ∈ HL ∧ W ∈ H → dom ⁡ I = Base K
5 4 eleq2d ⊢ K ∈ HL ∧ W ∈ H → X ∈ dom ⁡ I ↔ X ∈ Base K
6 eqid ⊢ DVecH ⁡ K ⁡ W = DVecH ⁡ K ⁡ W
7 eqid ⊢ Base DVecH ⁡ K ⁡ W = Base DVecH ⁡ K ⁡ W
8 3 1 2 6 7 dihss ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ Base K → I ⁡ X ⊆ Base DVecH ⁡ K ⁡ W
9 eqid ⊢ LTrn ⁡ K ⁡ W = LTrn ⁡ K ⁡ W
10 eqid ⊢ TEndo ⁡ K ⁡ W = TEndo ⁡ K ⁡ W
11 1 9 10 6 7 dvhvbase ⊢ K ∈ HL ∧ W ∈ H → Base DVecH ⁡ K ⁡ W = LTrn ⁡ K ⁡ W × TEndo ⁡ K ⁡ W
12 11 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ Base K → Base DVecH ⁡ K ⁡ W = LTrn ⁡ K ⁡ W × TEndo ⁡ K ⁡ W
13 8 12 sseqtrd ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ Base K → I ⁡ X ⊆ LTrn ⁡ K ⁡ W × TEndo ⁡ K ⁡ W
14 xpss ⊢ LTrn ⁡ K ⁡ W × TEndo ⁡ K ⁡ W ⊆ V × V
15 13 14 sstrdi ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ Base K → I ⁡ X ⊆ V × V
16 df-rel ⊢ Rel ⁡ I ⁡ X ↔ I ⁡ X ⊆ V × V
17 15 16 sylibr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ Base K → Rel ⁡ I ⁡ X
18 17 ex ⊢ K ∈ HL ∧ W ∈ H → X ∈ Base K → Rel ⁡ I ⁡ X
19 5 18 sylbid ⊢ K ∈ HL ∧ W ∈ H → X ∈ dom ⁡ I → Rel ⁡ I ⁡ X
20 rel0 ⊢ Rel ⁡ ∅
21 ndmfv ⊢ ¬ X ∈ dom ⁡ I → I ⁡ X = ∅
22 21 releqd ⊢ ¬ X ∈ dom ⁡ I → Rel ⁡ I ⁡ X ↔ Rel ⁡ ∅
23 20 22 mpbiri ⊢ ¬ X ∈ dom ⁡ I → Rel ⁡ I ⁡ X
24 19 23 pm2.61d1 ⊢ K ∈ HL ∧ W ∈ H → Rel ⁡ I ⁡ X