Metamath Proof Explorer


Theorem dstfrvel

Description: Elementhood of preimage maps produced by the "less than or equal to" relation. (Contributed by Thierry Arnoux, 13-Feb-2017)

Ref Expression
Hypotheses dstfrv.1 ⊢ φ → P ∈ Prob
dstfrv.2 ⊢ φ → X ∈ RndVar ℝ ⁡ P
orvclteel.1 ⊢ φ → A ∈ ℝ
dstfrvel.1 ⊢ φ → B ∈ ⋃ dom ⁡ P
dstfrvel.2 ⊢ φ → X ⁡ B ≤ A
Assertion dstfrvel ⊢ φ → B ∈ X ≤ RV/c A

Proof

Step Hyp Ref Expression
1 dstfrv.1 ⊢ φ → P ∈ Prob
2 dstfrv.2 ⊢ φ → X ∈ RndVar ℝ ⁡ P
3 orvclteel.1 ⊢ φ → A ∈ ℝ
4 dstfrvel.1 ⊢ φ → B ∈ ⋃ dom ⁡ P
5 dstfrvel.2 ⊢ φ → X ⁡ B ≤ A
6 1 2 rrvvf ⊢ φ → X : ⋃ dom ⁡ P ⟶ ℝ
7 6 4 ffvelcdmd ⊢ φ → X ⁡ B ∈ ℝ
8 breq1 ⊢ x = X ⁡ B → x ≤ A ↔ X ⁡ B ≤ A
9 8 elrab ⊢ X ⁡ B ∈ x ∈ ℝ | x ≤ A ↔ X ⁡ B ∈ ℝ ∧ X ⁡ B ≤ A
10 7 5 9 sylanbrc ⊢ φ → X ⁡ B ∈ x ∈ ℝ | x ≤ A
11 6 ffund ⊢ φ → Fun ⁡ X
12 1 2 rrvdm ⊢ φ → dom ⁡ X = ⋃ dom ⁡ P
13 4 12 eleqtrrd ⊢ φ → B ∈ dom ⁡ X
14 fvimacnv ⊢ Fun ⁡ X ∧ B ∈ dom ⁡ X → X ⁡ B ∈ x ∈ ℝ | x ≤ A ↔ B ∈ X -1 x ∈ ℝ | x ≤ A
15 11 13 14 syl2anc ⊢ φ → X ⁡ B ∈ x ∈ ℝ | x ≤ A ↔ B ∈ X -1 x ∈ ℝ | x ≤ A
16 10 15 mpbid ⊢ φ → B ∈ X -1 x ∈ ℝ | x ≤ A
17 1 2 3 orrvcval4 ⊢ φ → X ≤ RV/c A = X -1 x ∈ ℝ | x ≤ A
18 16 17 eleqtrrd ⊢ φ → B ∈ X ≤ RV/c A